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Theorem axextmo 2736
Description: There exists at most one set with prescribed elements. Theorem 1.1 of [BellMachover] p. 462. (Contributed by NM, 30-Jun-1994.) (Proof shortened by Wolf Lammen, 13-Nov-2019.) Use the at-most-one quantifier. (Revised by BJ, 17-Sep-2022.)
Hypothesis
Ref Expression
axextmo.1 Ⅎ𝑥𝜑
Assertion
Ref Expression
axextmo ∃*𝑥∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑)
Distinct variable group:   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)

Proof of Theorem axextmo
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 biantr 818 . . . . 5 (((𝑦 ∈ 𝑥 ↔ 𝜑) ∧ (𝑦 ∈ 𝑧 ↔ 𝜑)) → (𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑧))
21alanimi 1848 . . . 4 ((∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ∧ ∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)) → ∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑧))
3 ax-ext 2732 . . . 4 (∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑧) → 𝑥 = 𝑧)
42, 3syl 18 . . 3 ((∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ∧ ∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)) → 𝑥 = 𝑧)
54gen2 1828 . 2 ∀𝑥∀𝑧((∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ∧ ∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)) → 𝑥 = 𝑧)
6 nfv 1946 . . . . 5 Ⅎ𝑥 𝑦 ∈ 𝑧
7 axextmo.1 . . . . 5 Ⅎ𝑥𝜑
86, 7nfbi 1935 . . . 4 Ⅎ𝑥(𝑦 ∈ 𝑧 ↔ 𝜑)
98nfal 2353 . . 3 Ⅎ𝑥∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)
10 elequ2 2159 . . . . 5 (𝑥 = 𝑧 → (𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑧))
1110bibi1d 346 . . . 4 (𝑥 = 𝑧 → ((𝑦 ∈ 𝑥 ↔ 𝜑) ↔ (𝑦 ∈ 𝑧 ↔ 𝜑)))
1211albidv 1952 . . 3 (𝑥 = 𝑧 → (∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ↔ ∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)))
139, 12mo4f 2592 . 2 (∃*𝑥∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ↔ ∀𝑥∀𝑧((∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑) ∧ ∀𝑦(𝑦 ∈ 𝑧 ↔ 𝜑)) → 𝑥 = 𝑧))
145, 13mpbir 234 1 ∃*𝑥∀𝑦(𝑦 ∈ 𝑥 ↔ 𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1567  Ⅎwnf 1815  ∃*wmo 2562
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564
This theorem is used by:  nulmo  2737
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