Theorem bi2anan9r 639

Description: Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 19-Feb-1996.)

Hypotheses

Ref	Expression
bi2an9.1	⊢ (𝜑 → (𝜓 ↔ 𝜒))
bi2an9.2	⊢ (𝜃 → (𝜏 ↔ 𝜂))

Assertion

Ref	Expression
bi2anan9r	⊢ ((𝜃 ∧ 𝜑) → ((𝜓 ∧ 𝜏) ↔ (𝜒 ∧ 𝜂)))

Proof of Theorem bi2anan9r

Step	Hyp	Ref	Expression
1		bi2an9.1	. . 3 ⊢ (𝜑 → (𝜓 ↔ 𝜒))
2		bi2an9.2	. . 3 ⊢ (𝜃 → (𝜏 ↔ 𝜂))
3	1, 2	bi2anan9 638	. 2 ⊢ ((𝜑 ∧ 𝜃) → ((𝜓 ∧ 𝜏) ↔ (𝜒 ∧ 𝜂)))
4	3	ancoms 458	1 ⊢ ((𝜃 ∧ 𝜑) → ((𝜓 ∧ 𝜏) ↔ (𝜒 ∧ 𝜂)))

Syntax hints:   → wi 4   ↔ wb 206   ∧ wa 395

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-an 396

This theorem is referenced by:  efrn2lp  5592  ltsosr  10980  seqf1olem2  13944  seqf1o  13945  pcval  16751  sltlpss  27848  uspgr2wlkeq  29619  satf0op  35413  fmlafvel  35421  fneval  36386  prtlem5  38899  prjspval  42636  rmydioph  43047  wepwsolem  43075  aomclem8  43094  sprsymrelfolem2  47524  pgnbgreunbgrlem1  48144  pgnbgreunbgrlem4  48150