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Theorem cbvoprab1vw 36180
Description: Change the first bound variable in an operation abstraction, using implicit substitution. (Contributed by GG, 14-Aug-2025.)
Hypothesis
Ref Expression
cbvoprab1vw.1 (𝑥 = 𝑤 → (𝜓𝜒))
Assertion
Ref Expression
cbvoprab1vw {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} = {⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∣ 𝜒}
Distinct variable groups:   𝑥,𝑦,𝑤   𝑥,𝑧,𝑤   𝜓,𝑤   𝜒,𝑥
Allowed substitution hints:   𝜓(𝑥,𝑦,𝑧)   𝜒(𝑦,𝑧,𝑤)

Proof of Theorem cbvoprab1vw
Dummy variable 𝑡 is distinct from all other variables.
StepHypRef Expression
1 opeq1 4880 . . . . . . . 8 (𝑥 = 𝑤 → ⟨𝑥, 𝑦⟩ = ⟨𝑤, 𝑦⟩)
21opeq1d 4886 . . . . . . 7 (𝑥 = 𝑤 → ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩)
32eqeq2d 2744 . . . . . 6 (𝑥 = 𝑤 → (𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ↔ 𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩))
4 cbvoprab1vw.1 . . . . . 6 (𝑥 = 𝑤 → (𝜓𝜒))
53, 4anbi12d 631 . . . . 5 (𝑥 = 𝑤 → ((𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∧ 𝜓) ↔ (𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∧ 𝜒)))
652exbidv 1920 . . . 4 (𝑥 = 𝑤 → (∃𝑦𝑧(𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∧ 𝜓) ↔ ∃𝑦𝑧(𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∧ 𝜒)))
76cbvexvw 2032 . . 3 (∃𝑥𝑦𝑧(𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∧ 𝜓) ↔ ∃𝑤𝑦𝑧(𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∧ 𝜒))
87abbii 2805 . 2 {𝑡 ∣ ∃𝑥𝑦𝑧(𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∧ 𝜓)} = {𝑡 ∣ ∃𝑤𝑦𝑧(𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∧ 𝜒)}
9 df-oprab 7429 . 2 {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} = {𝑡 ∣ ∃𝑥𝑦𝑧(𝑡 = ⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∧ 𝜓)}
10 df-oprab 7429 . 2 {⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∣ 𝜒} = {𝑡 ∣ ∃𝑤𝑦𝑧(𝑡 = ⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∧ 𝜒)}
118, 9, 103eqtr4i 2771 1 {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} = {⟨⟨𝑤, 𝑦⟩, 𝑧⟩ ∣ 𝜒}
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1535  wex 1774  {cab 2710  cop 4636  {coprab 7426
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1790  ax-4 1804  ax-5 1906  ax-6 1963  ax-7 2003  ax-8 2106  ax-9 2114  ax-ext 2704
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 847  df-3an 1087  df-tru 1538  df-fal 1548  df-ex 1775  df-sb 2061  df-clab 2711  df-cleq 2725  df-clel 2812  df-rab 3433  df-v 3479  df-dif 3966  df-un 3968  df-ss 3980  df-nul 4340  df-if 4531  df-sn 4631  df-pr 4633  df-op 4637  df-oprab 7429
This theorem is referenced by:  cbvmpo1vw2  36186
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