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Theorem nfci 2910
Description: Deduce that a class 𝐴 does not have 𝑥 free in it. (Contributed by Mario Carneiro, 11-Aug-2016.)
Hypothesis
Ref Expression
nfci.1 𝑥 𝑦𝐴
Assertion
Ref Expression
nfci 𝑥𝐴
Distinct variable groups:   𝑥,𝑦   𝑦,𝐴
Allowed substitution hint:   𝐴(𝑥)

Proof of Theorem nfci
StepHypRef Expression
1 df-nfc 2909 . 2 (𝑥𝐴 ↔ ∀𝑦𝑥 𝑦𝐴)
2 nfci.1 . 2 𝑥 𝑦𝐴
31, 2mpgbir 1832 1 𝑥𝐴
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wnf 1816  wcel 2145  wnfc 2907
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828
This proof depends on definitions:  df-bi 210  df-nfc 2909
This theorem is used by:  nfcii  2911  nfcv  2922  nfab1  2924  nfab  2928  nfabg  2929  nfaba1  2930  nfdif  4077  nfun  4117  nfin  4170  nfiu1  4986  iinabrex  33042  fpwrelmap  33204  esumfzf  34579  fsumiunss  46405  climsuse  46438  climinff  46441  fnlimfvre  46502  limsupre3uzlem  46563  pimdecfgtioc  47543  pimincfltioc  47544  smfmullem4  47622  smflimsupmpt  47657
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