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Theorem nfci 2889
Description: Deduce that a class 𝐴 does not have 𝑥 free in it. (Contributed by Mario Carneiro, 11-Aug-2016.)
Hypothesis
Ref Expression
nfci.1 𝑥 𝑦𝐴
Assertion
Ref Expression
nfci 𝑥𝐴
Distinct variable groups:   𝑥,𝑦   𝑦,𝐴
Allowed substitution hint:   𝐴(𝑥)

Proof of Theorem nfci
StepHypRef Expression
1 df-nfc 2888 . 2 (𝑥𝐴 ↔ ∀𝑦𝑥 𝑦𝐴)
2 nfci.1 . 2 𝑥 𝑦𝐴
31, 2mpgbir 1806 1 𝑥𝐴
Colors of variables: wff setvar class
Syntax hints:  wnf 1790  wcel 2119  wnfc 2886
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802
This theorem depends on definitions:  df-bi 208  df-nfc 2888
This theorem is referenced by:  nfcii  2890  nfcv  2901  nfab1  2903  nfab  2907  nfabg  2908  nfaba1  2909  nfdif  4060  nfun  4100  nfin  4153  nfiu1  4957  iinabrex  32658  fpwrelmap  32825  esumfzf  34253  fsumiunss  46020  climsuse  46053  climinff  46056  fnlimfvre  46117  limsupre3uzlem  46178  pimdecfgtioc  47158  pimincfltioc  47159  smfmullem4  47237  smflimsupmpt  47272
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