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Theorem nfnid 5337
Description: A setvar variable is not free from itself. This theorem is not true in a one-element domain, as illustrated by the use of dtruALT2 5332 in its proof. (Contributed by Mario Carneiro, 8-Oct-2016.)
Assertion
Ref Expression
nfnid ¬ Ⅎ𝑥𝑥

Proof of Theorem nfnid
Dummy variables 𝑤 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 dtruALT2 5332 . . 3 ¬ ∀𝑧 𝑧 = 𝑤
2 ax-ext 2733 . . . . 5 (∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤) → 𝑧 = 𝑤)
32sps 2222 . . . 4 (∀𝑤∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤) → 𝑧 = 𝑤)
43alimi 1844 . . 3 (∀𝑧∀𝑤∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤) → ∀𝑧 𝑧 = 𝑤)
51, 4mto 200 . 2 ¬ ∀𝑧∀𝑤∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤)
6 df-nfc 2910 . . 3 (Ⅎ𝑥𝑥 ↔ ∀𝑦Ⅎ𝑥 𝑦 ∈ 𝑥)
7 sbnf2 2388 . . . . 5 (Ⅎ𝑥 𝑦 ∈ 𝑥 ↔ ∀𝑧∀𝑤([𝑧 / 𝑥]𝑦 ∈ 𝑥 ↔ [𝑤 / 𝑥]𝑦 ∈ 𝑥))
8 elsb2 2162 . . . . . . 7 ([𝑧 / 𝑥]𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑧)
9 elsb2 2162 . . . . . . 7 ([𝑤 / 𝑥]𝑦 ∈ 𝑥 ↔ 𝑦 ∈ 𝑤)
108, 9bibi12i 342 . . . . . 6 (([𝑧 / 𝑥]𝑦 ∈ 𝑥 ↔ [𝑤 / 𝑥]𝑦 ∈ 𝑥) ↔ (𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
11102albii 1853 . . . . 5 (∀𝑧∀𝑤([𝑧 / 𝑥]𝑦 ∈ 𝑥 ↔ [𝑤 / 𝑥]𝑦 ∈ 𝑥) ↔ ∀𝑧∀𝑤(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
127, 11bitri 278 . . . 4 (Ⅎ𝑥 𝑦 ∈ 𝑥 ↔ ∀𝑧∀𝑤(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
1312albii 1852 . . 3 (∀𝑦Ⅎ𝑥 𝑦 ∈ 𝑥 ↔ ∀𝑦∀𝑧∀𝑤(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
14 alrot3 2197 . . 3 (∀𝑦∀𝑧∀𝑤(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤) ↔ ∀𝑧∀𝑤∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
156, 13, 143bitri 300 . 2 (Ⅎ𝑥𝑥 ↔ ∀𝑧∀𝑤∀𝑦(𝑦 ∈ 𝑧 ↔ 𝑦 ∈ 𝑤))
165, 15mtbir 326 1 ¬ Ⅎ𝑥𝑥
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   ↔ wb 209  ∀wal 1568  Ⅎwnf 1816  [wsb 2099  Ⅎwnfc 2908
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2733  ax-nul 5260  ax-pow 5327
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-nf 1817  df-sb 2100  df-nfc 2910
This theorem is used by:  nfcvb  5338
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