Theorem rabssd 45681

Description: Restricted class abstraction in a subclass relationship. (Contributed by Glauco Siliprandi, 2-Jan-2022.)

Hypotheses

Ref	Expression
rabssd.1	⊢ Ⅎ𝑥𝜑
rabssd.2	⊢ Ⅎ𝑥𝐵
rabssd.3	⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝜒) → 𝑥 ∈ 𝐵)

Assertion

Ref	Expression
rabssd	⊢ (𝜑 → {𝑥 ∈ 𝐴 ∣ 𝜒} ⊆ 𝐵)

Proof of Theorem rabssd

Step	Hyp	Ref	Expression
1		rabssd.1	. . 3 ⊢ Ⅎ𝑥𝜑
2		rabssd.3	. . . 4 ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝜒) → 𝑥 ∈ 𝐵)
3	2	3exp 1131	. . 3 ⊢ (𝜑 → (𝑥 ∈ 𝐴 → (𝜒 → 𝑥 ∈ 𝐵)))
4	1, 3	ralrimi 3259	. 2 ⊢ (𝜑 → ∀𝑥 ∈ 𝐴 (𝜒 → 𝑥 ∈ 𝐵))
5		rabssd.2	. . 3 ⊢ Ⅎ𝑥𝐵
6	5	rabssf 45658	. 2 ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜒} ⊆ 𝐵 ↔ ∀𝑥 ∈ 𝐴 (𝜒 → 𝑥 ∈ 𝐵))
7	4, 6	sylibr 236	1 ⊢ (𝜑 → {𝑥 ∈ 𝐴 ∣ 𝜒} ⊆ 𝐵)

Syntax hints:   → wi 4   ∧ w3a 1097  Ⅎwnf 1802   ∈ wcel 2141  Ⅎwnfc 2908  ∀wral 3075  {crab 3413   ⊆ wss 3902

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-10 2174  ax-11 2190  ax-12 2211  ax-ext 2733

This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1099  df-tru 1562  df-ex 1799  df-nf 1803  df-sb 2090  df-clab 2740  df-cleq 2753  df-clel 2836  df-nfc 2910  df-ral 3076  df-rab 3414  df-ss 3919

This theorem is referenced by:  pimxrneun  46023  fsupdm  47377  finfdm  47381