Theorem xnegpnf 10247

Description: Minus +oo. Remark of [BourbakiTop1] p. IV.15. (Contributed by FL, 26-Dec-2011.)

Assertion

Ref	Expression
xnegpnf	|- -e +oo = -oo

Proof of Theorem xnegpnf

Step	Hyp	Ref	Expression
1		df-xneg 10191	. 2 |- -e +oo = if ( +oo = +oo , -oo , if ( +oo = -oo , +oo , -u +oo ) )
2		eqid 2238	. . 3 |- +oo = +oo
3	2	iftruei 3646	. 2 |- if ( +oo = +oo , -oo , if ( +oo = -oo , +oo , -u +oo ) ) = -oo
4	1, 3	eqtri 2259	1 |- -e +oo = -oo

This proof depends on syntax axioms:   = wceq 1402   ifcif 3638   +oocpnf 8363   -oocmnf 8364   -ucneg 8505   -ecxne 10188

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-11 1559  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-if 3639  df-xneg 10191

This theorem is used by:  xnegcl  10251  xnegneg  10252  xltnegi  10254  xnegid  10278  xnegdi  10287  xaddass2  10289  xsubge0  10300  xposdif  10301  xlesubadd  10302  xblss2ps  15630  xblss2  15631