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Theorem difdif 3306
Description: Double class difference. Exercise 11 of [TakeutiZaring] p. 22. (Contributed by NM, 17-May-1998.)
Assertion
Ref Expression
difdif (𝐴 ∖ (𝐵𝐴)) = 𝐴

Proof of Theorem difdif
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 simpl 109 . . 3 ((𝑥𝐴 ∧ ¬ 𝑥 ∈ (𝐵𝐴)) → 𝑥𝐴)
2 pm4.45im 334 . . . 4 (𝑥𝐴 ↔ (𝑥𝐴 ∧ (𝑥𝐵𝑥𝐴)))
3 imanim 690 . . . . . 6 ((𝑥𝐵𝑥𝐴) → ¬ (𝑥𝐵 ∧ ¬ 𝑥𝐴))
4 eldif 3183 . . . . . 6 (𝑥 ∈ (𝐵𝐴) ↔ (𝑥𝐵 ∧ ¬ 𝑥𝐴))
53, 4sylnibr 679 . . . . 5 ((𝑥𝐵𝑥𝐴) → ¬ 𝑥 ∈ (𝐵𝐴))
65anim2i 342 . . . 4 ((𝑥𝐴 ∧ (𝑥𝐵𝑥𝐴)) → (𝑥𝐴 ∧ ¬ 𝑥 ∈ (𝐵𝐴)))
72, 6sylbi 121 . . 3 (𝑥𝐴 → (𝑥𝐴 ∧ ¬ 𝑥 ∈ (𝐵𝐴)))
81, 7impbii 126 . 2 ((𝑥𝐴 ∧ ¬ 𝑥 ∈ (𝐵𝐴)) ↔ 𝑥𝐴)
98difeqri 3301 1 (𝐴 ∖ (𝐵𝐴)) = 𝐴
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wa 104   = wceq 1373  wcel 2178  cdif 3171
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 711  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-10 1529  ax-11 1530  ax-i12 1531  ax-bndl 1533  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2189
This theorem depends on definitions:  df-bi 117  df-tru 1376  df-nf 1485  df-sb 1787  df-clab 2194  df-cleq 2200  df-clel 2203  df-nfc 2339  df-v 2778  df-dif 3176
This theorem is referenced by:  dif0  3539
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