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Mirrors > Home > ILE Home > Th. List > sneqr | GIF version |
Description: If the singletons of two sets are equal, the two sets are equal. Part of Exercise 4 of [TakeutiZaring] p. 15. (Contributed by NM, 27-Aug-1993.) |
Ref | Expression |
---|---|
sneqr.1 | ⊢ 𝐴 ∈ V |
Ref | Expression |
---|---|
sneqr | ⊢ ({𝐴} = {𝐵} → 𝐴 = 𝐵) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sneqr.1 | . . . 4 ⊢ 𝐴 ∈ V | |
2 | 1 | snid 3625 | . . 3 ⊢ 𝐴 ∈ {𝐴} |
3 | eleq2 2241 | . . 3 ⊢ ({𝐴} = {𝐵} → (𝐴 ∈ {𝐴} ↔ 𝐴 ∈ {𝐵})) | |
4 | 2, 3 | mpbii 148 | . 2 ⊢ ({𝐴} = {𝐵} → 𝐴 ∈ {𝐵}) |
5 | 1 | elsn 3610 | . 2 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
6 | 4, 5 | sylib 122 | 1 ⊢ ({𝐴} = {𝐵} → 𝐴 = 𝐵) |
Colors of variables: wff set class |
Syntax hints: → wi 4 = wceq 1353 ∈ wcel 2148 Vcvv 2739 {csn 3594 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 709 ax-5 1447 ax-7 1448 ax-gen 1449 ax-ie1 1493 ax-ie2 1494 ax-8 1504 ax-10 1505 ax-11 1506 ax-i12 1507 ax-bndl 1509 ax-4 1510 ax-17 1526 ax-i9 1530 ax-ial 1534 ax-i5r 1535 ax-ext 2159 |
This theorem depends on definitions: df-bi 117 df-tru 1356 df-nf 1461 df-sb 1763 df-clab 2164 df-cleq 2170 df-clel 2173 df-nfc 2308 df-v 2741 df-sn 3600 |
This theorem is referenced by: sneqrg 3764 opth1 4238 cc2lem 7267 |
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