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Mirrors > Home > ILE Home > Th. List > Mathboxes > sssneq | GIF version |
Description: Any two elements of a subset of a singleton are equal. (Contributed by Jim Kingdon, 28-May-2024.) |
Ref | Expression |
---|---|
sssneq | ⊢ (𝐴 ⊆ {𝐵} → ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐴 𝑦 = 𝑧) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | simpl 108 | . . . . 5 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝐴 ⊆ {𝐵}) | |
2 | simprl 521 | . . . . 5 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑦 ∈ 𝐴) | |
3 | 1, 2 | sseldd 3138 | . . . 4 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑦 ∈ {𝐵}) |
4 | elsni 3588 | . . . 4 ⊢ (𝑦 ∈ {𝐵} → 𝑦 = 𝐵) | |
5 | 3, 4 | syl 14 | . . 3 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑦 = 𝐵) |
6 | simprr 522 | . . . . 5 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑧 ∈ 𝐴) | |
7 | 1, 6 | sseldd 3138 | . . . 4 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑧 ∈ {𝐵}) |
8 | elsni 3588 | . . . 4 ⊢ (𝑧 ∈ {𝐵} → 𝑧 = 𝐵) | |
9 | 7, 8 | syl 14 | . . 3 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑧 = 𝐵) |
10 | 5, 9 | eqtr4d 2200 | . 2 ⊢ ((𝐴 ⊆ {𝐵} ∧ (𝑦 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴)) → 𝑦 = 𝑧) |
11 | 10 | ralrimivva 2546 | 1 ⊢ (𝐴 ⊆ {𝐵} → ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐴 𝑦 = 𝑧) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∧ wa 103 = wceq 1342 ∈ wcel 2135 ∀wral 2442 ⊆ wss 3111 {csn 3570 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-io 699 ax-5 1434 ax-7 1435 ax-gen 1436 ax-ie1 1480 ax-ie2 1481 ax-8 1491 ax-10 1492 ax-11 1493 ax-i12 1494 ax-bndl 1496 ax-4 1497 ax-17 1513 ax-i9 1517 ax-ial 1521 ax-i5r 1522 ax-ext 2146 |
This theorem depends on definitions: df-bi 116 df-tru 1345 df-nf 1448 df-sb 1750 df-clab 2151 df-cleq 2157 df-clel 2160 df-nfc 2295 df-ral 2447 df-v 2723 df-in 3117 df-ss 3124 df-sn 3576 |
This theorem is referenced by: (None) |
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