Theorem csbhypf 3874

Description: Introduce an explicit substitution into an implicit substitution hypothesis. See sbhypf 3509 for class substitution version. (Contributed by NM, 19-Dec-2008.)

Hypotheses

Ref	Expression
csbhypf.1	⊢ Ⅎ𝑥𝐴
csbhypf.2	⊢ Ⅎ𝑥𝐶
csbhypf.3	⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶)

Assertion

Ref	Expression
csbhypf	⊢ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶)

Distinct variable group:   𝑥,𝑦

Allowed substitution hints:   𝐴(𝑥, 𝑦)   𝐵(𝑥, 𝑦)   𝐶(𝑥, 𝑦)

Proof of Theorem csbhypf

Step	Hyp	Ref	Expression
1		csbhypf.1	. . . 4 ⊢ Ⅎ𝑥𝐴
2	1	nfeq2 2939	. . 3 ⊢ Ⅎ𝑥 𝑦 = 𝐴
3		nfcsb1v 3870	. . . 4 ⊢ Ⅎ𝑥⦋𝑦 / 𝑥⦌𝐵
4		csbhypf.2	. . . 4 ⊢ Ⅎ𝑥𝐶
5	3, 4	nfeq 2935	. . 3 ⊢ Ⅎ𝑥⦋𝑦 / 𝑥⦌𝐵 = 𝐶
6	2, 5	nfim 1928	. 2 ⊢ Ⅎ𝑥(𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶)
7		eqeq1 2764	. . 3 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝐴 ↔ 𝑦 = 𝐴))
8		csbeq1a 3860	. . . 4 ⊢ (𝑥 = 𝑦 → 𝐵 = ⦋𝑦 / 𝑥⦌𝐵)
9	8	eqeq1d 2762	. . 3 ⊢ (𝑥 = 𝑦 → (𝐵 = 𝐶 ↔ ⦋𝑦 / 𝑥⦌𝐵 = 𝐶))
10	7, 9	imbi12d 347	. 2 ⊢ (𝑥 = 𝑦 → ((𝑥 = 𝐴 → 𝐵 = 𝐶) ↔ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶)))
11		csbhypf.3	. 2 ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶)
12	6, 10, 11	chvarfv 2276	1 ⊢ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶)

This proof depends on syntax axioms:   → wi 4   = wceq 1569  Ⅎwnfc 2907  ⦋csb 3846

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-ex 1812  df-nf 1816  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-sbc 3739  df-csb 3847

This theorem is used by:  disji2  5086  disjprg  5098  disjxun  5100  tfisi  7870  coe1fzgsumdlem  22622  evl1gsumdlem  22675  iundisj2  25871  disji2f  33214  disjif2  33218  iundisj2f  33227  iundisj2fi  33432  evl1gprodd  43243