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Theorem df3o2 43551
Description: Ordinal 3 is the unordered triple containing ordinals 0, 1, and 2. (Contributed by RP, 8-Jul-2021.)
Assertion
Ref Expression
df3o2 3o = {∅, 1o, 2o}

Proof of Theorem df3o2
StepHypRef Expression
1 df-3o 8399 . 2 3o = suc 2o
2 df2o3 8405 . . . 4 2o = {∅, 1o}
32uneq1i 4116 . . 3 (2o ∪ {2o}) = ({∅, 1o} ∪ {2o})
4 df-suc 6323 . . 3 suc 2o = (2o ∪ {2o})
5 df-tp 4585 . . 3 {∅, 1o, 2o} = ({∅, 1o} ∪ {2o})
63, 4, 53eqtr4i 2769 . 2 suc 2o = {∅, 1o, 2o}
71, 6eqtri 2759 1 3o = {∅, 1o, 2o}
Colors of variables: wff setvar class
Syntax hints:   = wceq 1541  cun 3899  c0 4285  {csn 4580  {cpr 4582  {ctp 4584  suc csuc 6319  1oc1o 8390  2oc2o 8391  3oc3o 8392
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2715  df-cleq 2728  df-clel 2811  df-v 3442  df-dif 3904  df-un 3906  df-nul 4286  df-pr 4583  df-tp 4585  df-suc 6323  df-1o 8397  df-2o 8398  df-3o 8399
This theorem is referenced by:  oenord1ex  43553  oenord1  43554  clsk1indlem4  44281  clsk1indlem1  44282
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