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Theorem df3o2 44040
Description: Ordinal 3 is the unordered triple containing ordinals 0, 1, and 2. (Contributed by RP, 8-Jul-2021.)
Assertion
Ref Expression
df3o2 3o = {∅, 1o, 2o}

Proof of Theorem df3o2
StepHypRef Expression
1 df-3o 8451 . 2 3o = suc 2o
2 df2o3 8457 . . . 4 2o = {∅, 1o}
32uneq1i 4118 . . 3 (2o ∪ {2o}) = ({∅, 1o} ∪ {2o})
4 df-suc 6366 . . 3 suc 2o = (2o ∪ {2o})
5 df-tp 4594 . . 3 {∅, 1o, 2o} = ({∅, 1o} ∪ {2o})
63, 4, 53eqtr4i 2796 . 2 suc 2o = {∅, 1o, 2o}
71, 6eqtri 2786 1 3o = {∅, 1o, 2o}
Colors of variables: wff setvar class
Syntax hints:   = wceq 1570  cun 3903  c0 4286  {csn 4589  {cpr 4591  {ctp 4593  suc csuc 6362  1oc1o 8442  2oc2o 8443  3oc3o 8444
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-v 3457  df-dif 3908  df-un 3910  df-nul 4287  df-pr 4592  df-tp 4594  df-suc 6366  df-1o 8449  df-2o 8450  df-3o 8451
This theorem is referenced by:  oenord1ex  44042  oenord1  44043  clsk1indlem4  44770  clsk1indlem1  44771
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