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Theorem dffr6 5548
Description: Alternate definition of df-fr 5545. See dffr5 33730 for a definition without dummy variables (but note that their equivalence uses ax-sep 5227). (Contributed by BJ, 16-Nov-2024.)
Assertion
Ref Expression
dffr6 (𝑅 Fr 𝐴 ↔ ∀𝑥 ∈ (𝒫 𝐴 ∖ {∅})∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦)
Distinct variable groups:   𝑥,𝐴,𝑦,𝑧   𝑥,𝑅,𝑦,𝑧

Proof of Theorem dffr6
StepHypRef Expression
1 velpw 4544 . . . . . . 7 (𝑥 ∈ 𝒫 𝐴𝑥𝐴)
21bicomi 223 . . . . . 6 (𝑥𝐴𝑥 ∈ 𝒫 𝐴)
3 velsn 4583 . . . . . . . 8 (𝑥 ∈ {∅} ↔ 𝑥 = ∅)
43bicomi 223 . . . . . . 7 (𝑥 = ∅ ↔ 𝑥 ∈ {∅})
54necon3abii 2992 . . . . . 6 (𝑥 ≠ ∅ ↔ ¬ 𝑥 ∈ {∅})
62, 5anbi12i 627 . . . . 5 ((𝑥𝐴𝑥 ≠ ∅) ↔ (𝑥 ∈ 𝒫 𝐴 ∧ ¬ 𝑥 ∈ {∅}))
7 eldif 3902 . . . . 5 (𝑥 ∈ (𝒫 𝐴 ∖ {∅}) ↔ (𝑥 ∈ 𝒫 𝐴 ∧ ¬ 𝑥 ∈ {∅}))
86, 7bitr4i 277 . . . 4 ((𝑥𝐴𝑥 ≠ ∅) ↔ 𝑥 ∈ (𝒫 𝐴 ∖ {∅}))
98imbi1i 350 . . 3 (((𝑥𝐴𝑥 ≠ ∅) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦) ↔ (𝑥 ∈ (𝒫 𝐴 ∖ {∅}) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦))
109albii 1826 . 2 (∀𝑥((𝑥𝐴𝑥 ≠ ∅) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦) ↔ ∀𝑥(𝑥 ∈ (𝒫 𝐴 ∖ {∅}) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦))
11 df-fr 5545 . 2 (𝑅 Fr 𝐴 ↔ ∀𝑥((𝑥𝐴𝑥 ≠ ∅) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦))
12 df-ral 3071 . 2 (∀𝑥 ∈ (𝒫 𝐴 ∖ {∅})∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦 ↔ ∀𝑥(𝑥 ∈ (𝒫 𝐴 ∖ {∅}) → ∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦))
1310, 11, 123bitr4i 303 1 (𝑅 Fr 𝐴 ↔ ∀𝑥 ∈ (𝒫 𝐴 ∖ {∅})∃𝑦𝑥𝑧𝑥 ¬ 𝑧𝑅𝑦)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 205  wa 396  wal 1540   = wceq 1542  wcel 2110  wne 2945  wral 3066  wrex 3067  cdif 3889  wss 3892  c0 4262  𝒫 cpw 4539  {csn 4567   class class class wbr 5079   Fr wfr 5542
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1975  ax-7 2015  ax-8 2112  ax-9 2120  ax-ext 2711
This theorem depends on definitions:  df-bi 206  df-an 397  df-tru 1545  df-ex 1787  df-sb 2072  df-clab 2718  df-cleq 2732  df-clel 2818  df-ne 2946  df-ral 3071  df-v 3433  df-dif 3895  df-in 3899  df-ss 3909  df-pw 4541  df-sn 4568  df-fr 5545
This theorem is referenced by:  frd  5549
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