MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  disjeq2 Structured version   Visualization version   GIF version

Theorem disjeq2 5073
Description: Equality theorem for disjoint collection. (Contributed by Mario Carneiro, 14-Nov-2016.)
Assertion
Ref Expression
disjeq2 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → (Disj 𝑥 ∈ 𝐴 𝐵 ↔ Disj 𝑥 ∈ 𝐴 𝐶))

Proof of Theorem disjeq2
StepHypRef Expression
1 eqimss2 3967 . . . 4 (𝐵 = 𝐶 → 𝐶 ⊆ 𝐵)
21ralimi 3099 . . 3 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → ∀𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵)
3 disjss2 5072 . . 3 (∀𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵 → (Disj 𝑥 ∈ 𝐴 𝐵 → Disj 𝑥 ∈ 𝐴 𝐶))
42, 3syl 18 . 2 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → (Disj 𝑥 ∈ 𝐴 𝐵 → Disj 𝑥 ∈ 𝐴 𝐶))
5 eqimss 3966 . . . 4 (𝐵 = 𝐶 → 𝐵 ⊆ 𝐶)
65ralimi 3099 . . 3 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → ∀𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶)
7 disjss2 5072 . . 3 (∀𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶 → (Disj 𝑥 ∈ 𝐴 𝐶 → Disj 𝑥 ∈ 𝐴 𝐵))
86, 7syl 18 . 2 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → (Disj 𝑥 ∈ 𝐴 𝐶 → Disj 𝑥 ∈ 𝐴 𝐵))
94, 8impbid 215 1 (∀𝑥 ∈ 𝐴 𝐵 = 𝐶 → (Disj 𝑥 ∈ 𝐴 𝐵 ↔ Disj 𝑥 ∈ 𝐴 𝐶))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   = wceq 1569  ∀wral 3076   ⊆ wss 3895  Disj wdisj 5069
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812  df-mo 2564  df-cleq 2752  df-clel 2835  df-ral 3077  df-rmo 3365  df-ss 3896  df-disj 5070
This theorem is used by:  disjeq2dv  5074  voliun  25875  carsgclctunlem2  34951  disjeq12i  36982  mblfinlem2  38577  voliunnfl  38583
  Copyright terms: Public domain W3C validator