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Mirrors > Home > MPE Home > Th. List > eqimss | Structured version Visualization version GIF version |
Description: Equality implies inclusion. (Contributed by NM, 21-Jun-1993.) (Proof shortened by Andrew Salmon, 21-Jun-2011.) |
Ref | Expression |
---|---|
eqimss | ⊢ (𝐴 = 𝐵 → 𝐴 ⊆ 𝐵) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqss 3932 | . 2 ⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴)) | |
2 | 1 | simplbi 497 | 1 ⊢ (𝐴 = 𝐵 → 𝐴 ⊆ 𝐵) |
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