Users' Mathboxes Mathbox for Steven Nguyen < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  elre0re Structured version   Visualization version   GIF version

Theorem elre0re 42576
Description: Specialized version of 0red 11139 without using ax-1cn 11088 and ax-cnre 11103. (Contributed by Steven Nguyen, 28-Jan-2023.)
Assertion
Ref Expression
elre0re (𝐴 ∈ ℝ → 0 ∈ ℝ)

Proof of Theorem elre0re
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 ax-rnegex 11101 . 2 (𝐴 ∈ ℝ → ∃𝑥 ∈ ℝ (𝐴 + 𝑥) = 0)
2 readdcl 11113 . . . 4 ((𝐴 ∈ ℝ ∧ 𝑥 ∈ ℝ) → (𝐴 + 𝑥) ∈ ℝ)
3 eleq1 2825 . . . 4 ((𝐴 + 𝑥) = 0 → ((𝐴 + 𝑥) ∈ ℝ ↔ 0 ∈ ℝ))
42, 3syl5ibcom 245 . . 3 ((𝐴 ∈ ℝ ∧ 𝑥 ∈ ℝ) → ((𝐴 + 𝑥) = 0 → 0 ∈ ℝ))
54rexlimdva 3138 . 2 (𝐴 ∈ ℝ → (∃𝑥 ∈ ℝ (𝐴 + 𝑥) = 0 → 0 ∈ ℝ))
61, 5mpd 15 1 (𝐴 ∈ ℝ → 0 ∈ ℝ)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395   = wceq 1542  wcel 2114  wrex 3061  (class class class)co 7360  cr 11029  0cc0 11030   + caddc 11033
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709  ax-addrcl 11091  ax-rnegex 11101
This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1782  df-cleq 2729  df-clel 2812  df-rex 3062
This theorem is referenced by:  redvmptabs  42682  rernegcl  42693  renegadd  42694  reneg0addlid  42696  resubeulem1  42697  resubeulem2  42698  resubeu  42699  remul02  42727  remul01  42729  readdrid  42732  resubid1  42733  renegneg  42734  renegid2  42736  sn-it0e0  42738  relt0neg2  42779
  Copyright terms: Public domain W3C validator