Users' Mathboxes Mathbox for Steven Nguyen < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  elre0re Structured version   Visualization version   GIF version

Theorem elre0re 42272
Description: Specialized version of 0red 11243 without using ax-1cn 11192 and ax-cnre 11207. (Contributed by Steven Nguyen, 28-Jan-2023.)
Assertion
Ref Expression
elre0re (𝐴 ∈ ℝ → 0 ∈ ℝ)

Proof of Theorem elre0re
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 ax-rnegex 11205 . 2 (𝐴 ∈ ℝ → ∃𝑥 ∈ ℝ (𝐴 + 𝑥) = 0)
2 readdcl 11217 . . . 4 ((𝐴 ∈ ℝ ∧ 𝑥 ∈ ℝ) → (𝐴 + 𝑥) ∈ ℝ)
3 eleq1 2823 . . . 4 ((𝐴 + 𝑥) = 0 → ((𝐴 + 𝑥) ∈ ℝ ↔ 0 ∈ ℝ))
42, 3syl5ibcom 245 . . 3 ((𝐴 ∈ ℝ ∧ 𝑥 ∈ ℝ) → ((𝐴 + 𝑥) = 0 → 0 ∈ ℝ))
54rexlimdva 3142 . 2 (𝐴 ∈ ℝ → (∃𝑥 ∈ ℝ (𝐴 + 𝑥) = 0 → 0 ∈ ℝ))
61, 5mpd 15 1 (𝐴 ∈ ℝ → 0 ∈ ℝ)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395   = wceq 1540  wcel 2109  wrex 3061  (class class class)co 7410  cr 11133  0cc0 11134   + caddc 11137
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2708  ax-addrcl 11195  ax-rnegex 11205
This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1780  df-cleq 2728  df-clel 2810  df-rex 3062
This theorem is referenced by:  redvmptabs  42370  rernegcl  42381  renegadd  42382  reneg0addlid  42384  resubeulem1  42385  resubeulem2  42386  resubeu  42387  remul02  42415  remul01  42417  readdrid  42419  resubid1  42420  renegneg  42421  renegid2  42423  sn-it0e0  42425  relt0neg2  42455
  Copyright terms: Public domain W3C validator