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Theorem elsn2g 4596
Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 28-Oct-2003.)
Assertion
Ref Expression
elsn2g (𝐵𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵))

Proof of Theorem elsn2g
StepHypRef Expression
1 elsni 4572 . 2 (𝐴 ∈ {𝐵} → 𝐴 = 𝐵)
2 snidg 4592 . . 3 (𝐵𝑉𝐵 ∈ {𝐵})
3 eleq1 2827 . . 3 (𝐴 = 𝐵 → (𝐴 ∈ {𝐵} ↔ 𝐵 ∈ {𝐵}))
42, 3syl5ibrcom 248 . 2 (𝐵𝑉 → (𝐴 = 𝐵𝐴 ∈ {𝐵}))
51, 4impbid2 227 1 (𝐵𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 207   = wceq 1547  wcel 2119  {csn 4555
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2711
This theorem depends on definitions:  df-bi 208  df-an 397  df-tru 1550  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-sn 4556
This theorem is referenced by:  elsn2  4597  mptiniseg  6190  elsuc2g  6381  extmptsuppeq  8128  fzosplitsni  13725  1nsgtrivd  19140  limcco  25878  ply1termlem  26186  mptprop  32790  bj-elsn12g  37413  elpmapat  40256  stirlinglem8  46524  dirkercncflem2  46547  clnbgrel  48319
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