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Theorem elsn2g 4599
Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 28-Oct-2003.)
Assertion
Ref Expression
elsn2g (𝐵𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵))

Proof of Theorem elsn2g
StepHypRef Expression
1 elsni 4578 . 2 (𝐴 ∈ {𝐵} → 𝐴 = 𝐵)
2 snidg 4595 . . 3 (𝐵𝑉𝐵 ∈ {𝐵})
3 eleq1 2826 . . 3 (𝐴 = 𝐵 → (𝐴 ∈ {𝐵} ↔ 𝐵 ∈ {𝐵}))
42, 3syl5ibrcom 246 . 2 (𝐵𝑉 → (𝐴 = 𝐵𝐴 ∈ {𝐵}))
51, 4impbid2 225 1 (𝐵𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 205   = wceq 1539  wcel 2106  {csn 4561
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1913  ax-6 1971  ax-7 2011  ax-8 2108  ax-9 2116  ax-ext 2709
This theorem depends on definitions:  df-bi 206  df-an 397  df-tru 1542  df-ex 1783  df-sb 2068  df-clab 2716  df-cleq 2730  df-clel 2816  df-sn 4562
This theorem is referenced by:  elsn2  4600  mptiniseg  6142  elsuc2g  6334  extmptsuppeq  8004  fzosplitsni  13498  1nsgtrivd  18802  limcco  25057  ply1termlem  25364  mptprop  31031  bj-elsn12g  35231  elpmapat  37778  stirlinglem8  43622  dirkercncflem2  43645
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