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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4608 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 = wceq 1542 ∈ wcel 2114 Vcvv 3429 {csn 4567 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1912 ax-6 1969 ax-7 2010 ax-8 2116 ax-9 2124 ax-ext 2708 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1545 df-ex 1782 df-sb 2069 df-clab 2715 df-cleq 2728 df-clel 2811 df-sn 4568 |
| This theorem is referenced by: fparlem1 8062 fparlem2 8063 el1o 8430 fin1a2lem11 10332 fin1a2lem12 10333 elnn0 12439 elxnn0 12512 elfzp1 13528 fsumss 15687 fprodss 15913 elhoma 17999 rnglidl0 21227 islpidl 21323 zrhrhmb 21490 rest0 23134 qustgphaus 24088 taylfval 26324 eqcuts3 27796 elch0 31325 atoml2i 32454 prmidl0 33510 bj-eltag 37284 bj-rest10b 37401 dibopelvalN 41589 dibopelval2 41591 aks4d1p1p4 42510 climrec 46033 |
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