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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4630 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 209 = wceq 1570 ∈ wcel 2143 Vcvv 3455 {csn 4589 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1825 ax-4 1839 ax-5 1940 ax-6 1997 ax-7 2038 ax-8 2145 ax-9 2153 ax-ext 2735 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-tru 1573 df-ex 1810 df-sb 2097 df-clab 2742 df-cleq 2755 df-clel 2838 df-sn 4590 |
| This theorem is referenced by: fparlem1 8103 fparlem2 8104 el1o 8476 fin1a2lem11 10389 fin1a2lem12 10390 elnn0 12501 elxnn0 12574 elfzp1 13598 fsumss 15772 fprodss 15998 elhoma 18084 rnglidl0 21355 prmidl0 21478 islpidl 21493 zrhrhmb 21660 rest0 23326 qustgphaus 24280 taylfval 26522 eqcuts3 27997 elch0 31606 atoml2i 32735 bj-eltag 37633 bj-rest10b 37751 dibopelvalN 41937 dibopelval2 41939 aks4d1p1p4 42858 climrec 46339 |
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