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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4622 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 = wceq 1542 ∈ wcel 2114 Vcvv 3441 {csn 4581 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1912 ax-6 1969 ax-7 2010 ax-8 2116 ax-9 2124 ax-ext 2709 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1545 df-ex 1782 df-sb 2069 df-clab 2716 df-cleq 2729 df-clel 2812 df-sn 4582 |
| This theorem is referenced by: fparlem1 8056 fparlem2 8057 el1o 8424 fin1a2lem11 10324 fin1a2lem12 10325 elnn0 12407 elxnn0 12480 elfzp1 13494 fsumss 15652 fprodss 15875 elhoma 17960 rnglidl0 21188 islpidl 21284 zrhrhmb 21469 rest0 23117 qustgphaus 24071 taylfval 26326 eqscut3 27802 elch0 31312 atoml2i 32441 prmidl0 33512 bj-eltag 37153 bj-rest10b 37265 dibopelvalN 41440 dibopelval2 41442 aks4d1p1p4 42362 climrec 45885 |
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