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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4619 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 = wceq 1541 ∈ wcel 2113 Vcvv 3438 {csn 4578 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1968 ax-7 2009 ax-8 2115 ax-9 2123 ax-ext 2706 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1544 df-ex 1781 df-sb 2068 df-clab 2713 df-cleq 2726 df-clel 2809 df-sn 4579 |
| This theorem is referenced by: fparlem1 8052 fparlem2 8053 el1o 8420 fin1a2lem11 10318 fin1a2lem12 10319 elnn0 12401 elxnn0 12474 elfzp1 13488 fsumss 15646 fprodss 15869 elhoma 17954 rnglidl0 21182 islpidl 21278 zrhrhmb 21463 rest0 23111 qustgphaus 24065 taylfval 26320 eqscut3 27792 elch0 31278 atoml2i 32407 prmidl0 33480 bj-eltag 37121 bj-rest10b 37233 dibopelvalN 41342 dibopelval2 41344 aks4d1p1p4 42264 climrec 45791 |
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