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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4628 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 = wceq 1540 ∈ wcel 2109 Vcvv 3447 {csn 4589 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1795 ax-4 1809 ax-5 1910 ax-6 1967 ax-7 2008 ax-8 2111 ax-9 2119 ax-ext 2701 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1543 df-ex 1780 df-sb 2066 df-clab 2708 df-cleq 2721 df-clel 2803 df-sn 4590 |
| This theorem is referenced by: fparlem1 8091 fparlem2 8092 el1o 8459 fin1a2lem11 10363 fin1a2lem12 10364 elnn0 12444 elxnn0 12517 elfzp1 13535 fsumss 15691 fprodss 15914 elhoma 17994 rnglidl0 21139 islpidl 21235 zrhrhmb 21420 rest0 23056 qustgphaus 24010 taylfval 26266 elch0 31183 atoml2i 32312 prmidl0 33421 bj-eltag 36965 bj-rest10b 37077 dibopelvalN 41137 dibopelval2 41139 aks4d1p1p4 42059 climrec 45601 |
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