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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4623 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 208 = wceq 1560 ∈ wcel 2142 Vcvv 3454 {csn 4582 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1815 ax-4 1829 ax-5 1930 ax-6 1987 ax-7 2028 ax-8 2144 ax-9 2152 ax-ext 2734 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-tru 1563 df-ex 1800 df-sb 2091 df-clab 2741 df-cleq 2754 df-clel 2837 df-sn 4583 |
| This theorem is referenced by: fparlem1 8091 fparlem2 8092 el1o 8464 fin1a2lem11 10367 fin1a2lem12 10368 elnn0 12483 elxnn0 12556 elfzp1 13579 fsumss 15752 fprodss 15978 elhoma 18065 rnglidl0 21299 islpidl 21395 zrhrhmb 21562 rest0 23229 qustgphaus 24183 taylfval 26422 eqcuts3 27897 elch0 31457 atoml2i 32586 prmidl0 33637 bj-eltag 37462 bj-rest10b 37579 dibopelvalN 41767 dibopelval2 41769 aks4d1p1p4 42688 climrec 46179 |
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