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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4623 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 = wceq 1542 ∈ wcel 2114 Vcvv 3442 {csn 4582 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1912 ax-6 1969 ax-7 2010 ax-8 2116 ax-9 2124 ax-ext 2709 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1545 df-ex 1782 df-sb 2069 df-clab 2716 df-cleq 2729 df-clel 2812 df-sn 4583 |
| This theorem is referenced by: fparlem1 8064 fparlem2 8065 el1o 8432 fin1a2lem11 10332 fin1a2lem12 10333 elnn0 12415 elxnn0 12488 elfzp1 13502 fsumss 15660 fprodss 15883 elhoma 17968 rnglidl0 21196 islpidl 21292 zrhrhmb 21477 rest0 23125 qustgphaus 24079 taylfval 26334 eqcuts3 27812 elch0 31342 atoml2i 32471 prmidl0 33543 bj-eltag 37225 bj-rest10b 37342 dibopelvalN 41519 dibopelval2 41521 aks4d1p1p4 42441 climrec 45963 |
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