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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4635 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 209 = wceq 1567 ∈ wcel 2149 Vcvv 3463 {csn 4594 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-tru 1570 df-ex 1807 df-sb 2098 df-clab 2748 df-cleq 2761 df-clel 2844 df-sn 4595 |
| This theorem is referenced by: fparlem1 8107 fparlem2 8108 el1o 8480 fin1a2lem11 10394 fin1a2lem12 10395 elnn0 12506 elxnn0 12579 elfzp1 13602 fsumss 15776 fprodss 16002 elhoma 18089 rnglidl0 21333 prmidl0 21447 islpidl 21462 zrhrhmb 21629 rest0 23295 qustgphaus 24249 taylfval 26488 eqcuts3 27963 elch0 31547 atoml2i 32676 bj-eltag 37501 bj-rest10b 37619 dibopelvalN 41807 dibopelval2 41809 aks4d1p1p4 42728 climrec 46211 |
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