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| Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version | ||
| Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
| Ref | Expression |
|---|---|
| elsn2.1 | ⊢ 𝐵 ∈ V |
| Ref | Expression |
|---|---|
| elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
| 2 | elsn2g 4596 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 207 = wceq 1547 ∈ wcel 2119 Vcvv 3431 {csn 4555 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-ext 2711 |
| This theorem depends on definitions: df-bi 208 df-an 397 df-tru 1550 df-ex 1787 df-sb 2074 df-clab 2718 df-cleq 2731 df-clel 2814 df-sn 4556 |
| This theorem is referenced by: fparlem1 8051 fparlem2 8052 el1o 8420 fin1a2lem11 10323 fin1a2lem12 10324 elnn0 12430 elxnn0 12503 elfzp1 13519 fsumss 15678 fprodss 15904 elhoma 17990 rnglidl0 21222 islpidl 21318 zrhrhmb 21485 rest0 23152 qustgphaus 24106 taylfval 26342 eqcuts3 27814 elch0 31343 atoml2i 32472 prmidl0 33533 bj-eltag 37330 bj-rest10b 37447 dibopelvalN 41635 dibopelval2 41637 aks4d1p1p4 42556 climrec 46048 |
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