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Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version |
Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
Ref | Expression |
---|---|
elsn2.1 | ⊢ 𝐵 ∈ V |
Ref | Expression |
---|---|
elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
2 | elsn2g 4669 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 206 = wceq 1537 ∈ wcel 2106 Vcvv 3478 {csn 4631 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1792 ax-4 1806 ax-5 1908 ax-6 1965 ax-7 2005 ax-8 2108 ax-9 2116 ax-ext 2706 |
This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1540 df-ex 1777 df-sb 2063 df-clab 2713 df-cleq 2727 df-clel 2814 df-sn 4632 |
This theorem is referenced by: fparlem1 8136 fparlem2 8137 el1o 8532 fin1a2lem11 10448 fin1a2lem12 10449 elnn0 12526 elxnn0 12599 elfzp1 13611 fsumss 15758 fprodss 15981 elhoma 18086 rnglidl0 21257 islpidl 21353 zrhrhmb 21539 rest0 23193 qustgphaus 24147 taylfval 26415 elch0 31283 atoml2i 32412 prmidl0 33458 bj-eltag 36960 bj-rest10b 37072 dibopelvalN 41126 dibopelval2 41128 aks4d1p1p4 42053 climrec 45559 |
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