MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  ex-natded9.26 Structured version   Visualization version   GIF version

Theorem ex-natded9.26 30899
Description: Theorem 9.26 of [Clemente] p. 45, translated line by line using an interpretation of natural deduction in Metamath. This proof has some additional complications due to the fact that Metamath's existential elimination rule does not change bound variables, so we need to verify that 𝑥 is bound in the conclusion. For information about ND and Metamath, see the page on Deduction Form and Natural Deduction in Metamath Proof Explorer. The original proof, which uses Fitch style, was written as follows (the leading "..." shows an embedded ND hypothesis, beginning with the initial assumption of the ND hypothesis):
#MPE#ND Expression MPE TranslationND Rationale MPE Rationale
13 𝑥𝑦𝜓(𝑥, 𝑦) (𝜑 → ∃𝑥𝑦𝜓) Given $e.
26 ...| 𝑦𝜓(𝑥, 𝑦) ((𝜑 ∧ ∀𝑦𝜓) → ∀𝑦𝜓) ND hypothesis assumption simpr 490. Later statements will have this scope.
37;5,4 ... 𝜓(𝑥, 𝑦) ((𝜑 ∧ ∀𝑦𝜓) → 𝜓) E 2,y spsbcd 3753 (E), 5,6. To use it we need a1i 11 and vex 3454. This could be immediately done with 19.21bi 2225, but we want to show the general approach for substitution.
412;8,9,10,11 ... 𝑥𝜓(𝑥, 𝑦) ((𝜑 ∧ ∀𝑦𝜓) → ∃𝑥𝜓) I 3,a spesbcd 3830 (I), 11. To use it we need sylibr 237, which in turn requires sylib 221 and two uses of sbcid 3756. This could be more immediately done using 19.8a 2217, but we want to show the general approach for substitution.
513;1,2 𝑥𝜓(𝑥, 𝑦) (𝜑 → ∃𝑥𝜓) E 1,2,4,a exlimdd 2256 (E), 1,2,3,12. We'll need supporting assertions that the variable is free (not bound), as provided in nfv 1947 and nfe1 2187 (MPE# 1,2)
614 𝑦𝑥𝜓(𝑥, 𝑦) (𝜑 → ∀𝑦𝑥𝜓) I 5 alrimiv 1960 (I), 13

The original used Latin letters for predicates; we have replaced them with Greek letters to follow Metamath naming conventions and so that it is easier to follow the Metamath translation. The Metamath line-for-line translation of this natural deduction approach precedes every line with an antecedent including 𝜑 and uses the Metamath equivalents of the natural deduction rules. Below is the final Metamath proof (which reorders some steps).

Note that in the original proof, 𝜓(𝑥, 𝑦) has explicit parameters. In Metamath, these parameters are always implicit, and the parameters upon which a wff variable can depend are recorded in the "allowed substitution hints" below.

A much more efficient proof, using more of Metamath and MPE's capabilities, is shown in ex-natded9.26-2 30900.

(Contributed by Mario Carneiro, 9-Feb-2017.) (Revised by David A. Wheeler, 18-Feb-2017.) (Proof modification is discouraged.) (New usage is discouraged.)

Hypothesis
Ref Expression
ex-natded9.26.1 (𝜑 → ∃𝑥𝑦𝜓)
Assertion
Ref Expression
ex-natded9.26 (𝜑 → ∀𝑦𝑥𝜓)
Distinct variable group:   𝑥,𝑦,𝜑
Allowed substitution hints:   𝜓(𝑥, 𝑦)

Proof of Theorem ex-natded9.26
StepHypRef Expression
1 nfv 1947 . . 3 𝑥𝜑
2 nfe1 2187 . . 3 𝑥𝑥𝜓
3 ex-natded9.26.1 . . 3 (𝜑 → ∃𝑥𝑦𝜓)
4 vex 3454 . . . . . . . 8 𝑦 ∈ V
54a1i 11 . . . . . . 7 ((𝜑 ∧ ∀𝑦𝜓) → 𝑦 ∈ V)
6 simpr 490 . . . . . . 7 ((𝜑 ∧ ∀𝑦𝜓) → ∀𝑦𝜓)
75, 6spsbcd 3753 . . . . . 6 ((𝜑 ∧ ∀𝑦𝜓) → [𝑦 / 𝑦]𝜓)
8 sbcid 3756 . . . . . 6 ([𝑦 / 𝑦]𝜓𝜓)
97, 8sylib 221 . . . . 5 ((𝜑 ∧ ∀𝑦𝜓) → 𝜓)
10 sbcid 3756 . . . . 5 ([𝑥 / 𝑥]𝜓𝜓)
119, 10sylibr 237 . . . 4 ((𝜑 ∧ ∀𝑦𝜓) → [𝑥 / 𝑥]𝜓)
1211spesbcd 3830 . . 3 ((𝜑 ∧ ∀𝑦𝜓) → ∃𝑥𝜓)
131, 2, 3, 12exlimdd 2256 . 2 (𝜑 → ∃𝑥𝜓)
1413alrimiv 1960 1 (𝜑 → ∀𝑦𝑥𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wa 401  wal 1568  wex 1812  wcel 2145  Vcvv 3450  [wsbc 3739
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ral 3077  df-rex 3087  df-v 3452  df-sbc 3740
This theorem is used by: (None)
  Copyright terms: Public domain W3C validator