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Theorem wl-exeq 35457
Description: The semantics of 𝑥𝑦 = 𝑧. (Contributed by Wolf Lammen, 27-Apr-2018.)
Assertion
Ref Expression
wl-exeq (∃𝑥 𝑦 = 𝑧 ↔ (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))

Proof of Theorem wl-exeq
StepHypRef Expression
1 nfeqf 2381 . . . . . . . . 9 ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ¬ ∀𝑥 𝑥 = 𝑧) → Ⅎ𝑥 𝑦 = 𝑧)
2119.9d 2202 . . . . . . . 8 ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ¬ ∀𝑥 𝑥 = 𝑧) → (∃𝑥 𝑦 = 𝑧𝑦 = 𝑧))
32impancom 455 . . . . . . 7 ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ∃𝑥 𝑦 = 𝑧) → (¬ ∀𝑥 𝑥 = 𝑧𝑦 = 𝑧))
43orrd 863 . . . . . 6 ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ∃𝑥 𝑦 = 𝑧) → (∀𝑥 𝑥 = 𝑧𝑦 = 𝑧))
54expcom 417 . . . . 5 (∃𝑥 𝑦 = 𝑧 → (¬ ∀𝑥 𝑥 = 𝑦 → (∀𝑥 𝑥 = 𝑧𝑦 = 𝑧)))
65orrd 863 . . . 4 (∃𝑥 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 ∨ (∀𝑥 𝑥 = 𝑧𝑦 = 𝑧)))
7 3orass 1092 . . . 4 ((∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧𝑦 = 𝑧) ↔ (∀𝑥 𝑥 = 𝑦 ∨ (∀𝑥 𝑥 = 𝑧𝑦 = 𝑧)))
86, 7sylibr 237 . . 3 (∃𝑥 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧𝑦 = 𝑧))
9 3orrot 1094 . . 3 ((𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧) ↔ (∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧𝑦 = 𝑧))
108, 9sylibr 237 . 2 (∃𝑥 𝑦 = 𝑧 → (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))
11 19.8a 2179 . . 3 (𝑦 = 𝑧 → ∃𝑥 𝑦 = 𝑧)
12 ax6e 2383 . . . . 5 𝑥 𝑥 = 𝑧
13 ax7 2024 . . . . . 6 (𝑥 = 𝑦 → (𝑥 = 𝑧𝑦 = 𝑧))
1413com12 32 . . . . 5 (𝑥 = 𝑧 → (𝑥 = 𝑦𝑦 = 𝑧))
1512, 14eximii 1844 . . . 4 𝑥(𝑥 = 𝑦𝑦 = 𝑧)
161519.35i 1886 . . 3 (∀𝑥 𝑥 = 𝑦 → ∃𝑥 𝑦 = 𝑧)
17 ax6e 2383 . . . . 5 𝑥 𝑥 = 𝑦
1817, 13eximii 1844 . . . 4 𝑥(𝑥 = 𝑧𝑦 = 𝑧)
191819.35i 1886 . . 3 (∀𝑥 𝑥 = 𝑧 → ∃𝑥 𝑦 = 𝑧)
2011, 16, 193jaoi 1429 . 2 ((𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧) → ∃𝑥 𝑦 = 𝑧)
2110, 20impbii 212 1 (∃𝑥 𝑦 = 𝑧 ↔ (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 209  wa 399  wo 847  w3o 1088  wal 1541  wex 1787
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1803  ax-4 1817  ax-5 1918  ax-6 1976  ax-7 2016  ax-10 2142  ax-12 2176  ax-13 2372
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 848  df-3or 1090  df-3an 1091  df-tru 1546  df-ex 1788  df-nf 1792
This theorem is referenced by:  wl-nfeqfb  35459
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