Theorem wl-exeq 38282

Description: The semantics of ∃𝑥𝑦 = 𝑧. (Contributed by Wolf Lammen, 27-Apr-2018.)

Assertion

Ref	Expression
wl-exeq	⊢ (∃𝑥 𝑦 = 𝑧 ↔ (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))

Proof of Theorem wl-exeq

Step	Hyp	Ref	Expression
1		nfeqf 2412	. . . . . . . . 9 ⊢ ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ¬ ∀𝑥 𝑥 = 𝑧) → Ⅎ𝑥 𝑦 = 𝑧)
2	1	19.9d 2241	. . . . . . . 8 ⊢ ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ¬ ∀𝑥 𝑥 = 𝑧) → (∃𝑥 𝑦 = 𝑧 → 𝑦 = 𝑧))
3	2	impancom 457	. . . . . . 7 ⊢ ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ∃𝑥 𝑦 = 𝑧) → (¬ ∀𝑥 𝑥 = 𝑧 → 𝑦 = 𝑧))
4	3	orrd 877	. . . . . 6 ⊢ ((¬ ∀𝑥 𝑥 = 𝑦 ∧ ∃𝑥 𝑦 = 𝑧) → (∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧))
5	4	expcom 419	. . . . 5 ⊢ (∃𝑥 𝑦 = 𝑧 → (¬ ∀𝑥 𝑥 = 𝑦 → (∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧)))
6	5	orrd 877	. . . 4 ⊢ (∃𝑥 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 ∨ (∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧)))
7		3orass 1106	. . . 4 ⊢ ((∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧) ↔ (∀𝑥 𝑥 = 𝑦 ∨ (∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧)))
8	6, 7	sylibr 237	. . 3 ⊢ (∃𝑥 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧))
9		3orrot 1108	. . 3 ⊢ ((𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧) ↔ (∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧 ∨ 𝑦 = 𝑧))
10	8, 9	sylibr 237	. 2 ⊢ (∃𝑥 𝑦 = 𝑧 → (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))
11		19.8a 2219	. . 3 ⊢ (𝑦 = 𝑧 → ∃𝑥 𝑦 = 𝑧)
12		ax6e 2414	. . . . 5 ⊢ ∃𝑥 𝑥 = 𝑧
13		ax7 2049	. . . . . 6 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 → 𝑦 = 𝑧))
14	13	com12 33	. . . . 5 ⊢ (𝑥 = 𝑧 → (𝑥 = 𝑦 → 𝑦 = 𝑧))
15	12, 14	eximii 1870	. . . 4 ⊢ ∃𝑥(𝑥 = 𝑦 → 𝑦 = 𝑧)
16	15	19.35i 1911	. . 3 ⊢ (∀𝑥 𝑥 = 𝑦 → ∃𝑥 𝑦 = 𝑧)
17		ax6e 2414	. . . . 5 ⊢ ∃𝑥 𝑥 = 𝑦
18	17, 13	eximii 1870	. . . 4 ⊢ ∃𝑥(𝑥 = 𝑧 → 𝑦 = 𝑧)
19	18	19.35i 1911	. . 3 ⊢ (∀𝑥 𝑥 = 𝑧 → ∃𝑥 𝑦 = 𝑧)
20	11, 16, 19	3jaoi 1454	. 2 ⊢ ((𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧) → ∃𝑥 𝑦 = 𝑧)
21	10, 20	impbii 212	1 ⊢ (∃𝑥 𝑦 = 𝑧 ↔ (𝑦 = 𝑧 ∨ ∀𝑥 𝑥 = 𝑦 ∨ ∀𝑥 𝑥 = 𝑧))

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401   ∨ wo 861   ∨ w3o 1102  ∀wal 1568  ∃wex 1812

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-10 2178  ax-12 2215  ax-13 2403

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-ex 1813  df-nf 1817

This theorem is used by:  wl-nfeqfb  38284