Theorem ax7 2048

Description: Proof of ax-7 2040 from ax7v1 2042 and ax7v2 2043 (and earlier axioms), proving sufficiency of the conjunction of the latter two weakened versions of ax7v 2041, which is itself a weakened version of ax-7 2040.

Note that the weakened version of ax-7 2040 obtained by adding a disjoint variable condition on 𝑥, 𝑧 (resp. on 𝑦, 𝑧) does not permit, together with the other axioms, to prove reflexivity (resp. symmetry). (Contributed by BJ, 7-Dec-2020.)

Assertion

Ref	Expression
ax7	⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 → 𝑦 = 𝑧))

Proof of Theorem ax7

Dummy variable 𝑡 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		ax7v2 2043	. . . 4 ⊢ (𝑥 = 𝑡 → (𝑥 = 𝑦 → 𝑡 = 𝑦))
2		ax7v2 2043	. . . 4 ⊢ (𝑥 = 𝑡 → (𝑥 = 𝑧 → 𝑡 = 𝑧))
3		ax7v1 2042	. . . . . 6 ⊢ (𝑡 = 𝑦 → (𝑡 = 𝑧 → 𝑦 = 𝑧))
4	3	imp 412	. . . . 5 ⊢ ((𝑡 = 𝑦 ∧ 𝑡 = 𝑧) → 𝑦 = 𝑧)
5	4	a1i 11	. . . 4 ⊢ (𝑥 = 𝑡 → ((𝑡 = 𝑦 ∧ 𝑡 = 𝑧) → 𝑦 = 𝑧))
6	1, 2, 5	syl2and 620	. . 3 ⊢ (𝑥 = 𝑡 → ((𝑥 = 𝑦 ∧ 𝑥 = 𝑧) → 𝑦 = 𝑧))
7		ax6evr 2047	. . 3 ⊢ ∃𝑡 𝑥 = 𝑡
8	6, 7	exlimiiv 1963	. 2 ⊢ ((𝑥 = 𝑦 ∧ 𝑥 = 𝑧) → 𝑦 = 𝑧)
9	8	ex 418	1 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 → 𝑦 = 𝑧))

This proof depends on syntax axioms:   → wi 4   ∧ wa 401

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812

This theorem is used by:  equcomi  2049  equtr  2053  equequ1  2057  cbvaev  2087  aeveq  2090  axc16i  2465  equvel  2485  mo4  2591  axextnd  10680  in-ax8  37106  ss-ax8  37107  wl-aetr  38555  wl-exeq  38560  wl-aleq  38561  wl-nfeqfb  38562  equcomi1  40051  hbequid  40060  equidqe  40073  aev-o  40082  ax6e2eq  45634  ax6e2eqVD  45983  et-equeucl  47976  2reu8i  48277