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Theorem zfrepclf 5254
Description: An inference based on the Axiom of Replacement. Typically, 𝜑 defines a function from 𝑥 to 𝑦. (Contributed by NM, 26-Nov-1995.)
Hypotheses
Ref Expression
zfrepclf.1 𝑥𝐴
zfrepclf.2 𝐴 ∈ V
zfrepclf.3 (𝑥𝐴 → ∃𝑧𝑦(𝜑𝑦 = 𝑧))
Assertion
Ref Expression
zfrepclf 𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑))
Distinct variable groups:   𝑦,𝑧,𝐴   𝜑,𝑧   𝑥,𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝐴(𝑥)

Proof of Theorem zfrepclf
Dummy variable 𝑣 is distinct from all other variables.
StepHypRef Expression
1 zfrepclf.2 . 2 𝐴 ∈ V
2 zfrepclf.1 . . . . . 6 𝑥𝐴
32nfeq2 2944 . . . . 5 𝑥 𝑣 = 𝐴
4 eleq2 2854 . . . . . 6 (𝑣 = 𝐴 → (𝑥𝑣𝑥𝐴))
5 zfrepclf.3 . . . . . 6 (𝑥𝐴 → ∃𝑧𝑦(𝜑𝑦 = 𝑧))
64, 5biimtrdi 256 . . . . 5 (𝑣 = 𝐴 → (𝑥𝑣 → ∃𝑧𝑦(𝜑𝑦 = 𝑧)))
73, 6alrimi 2252 . . . 4 (𝑣 = 𝐴 → ∀𝑥(𝑥𝑣 → ∃𝑧𝑦(𝜑𝑦 = 𝑧)))
8 nfv 1947 . . . . 5 𝑧𝜑
98axrep5 5248 . . . 4 (∀𝑥(𝑥𝑣 → ∃𝑧𝑦(𝜑𝑦 = 𝑧)) → ∃𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝑣𝜑)))
107, 9syl 18 . . 3 (𝑣 = 𝐴 → ∃𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝑣𝜑)))
114anbi1d 643 . . . . . . 7 (𝑣 = 𝐴 → ((𝑥𝑣𝜑) ↔ (𝑥𝐴𝜑)))
123, 11exbid 2262 . . . . . 6 (𝑣 = 𝐴 → (∃𝑥(𝑥𝑣𝜑) ↔ ∃𝑥(𝑥𝐴𝜑)))
1312bibi2d 345 . . . . 5 (𝑣 = 𝐴 → ((𝑦𝑧 ↔ ∃𝑥(𝑥𝑣𝜑)) ↔ (𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑))))
1413albidv 1953 . . . 4 (𝑣 = 𝐴 → (∀𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝑣𝜑)) ↔ ∀𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑))))
1514exbidv 1954 . . 3 (𝑣 = 𝐴 → (∃𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝑣𝜑)) ↔ ∃𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑))))
1610, 15mpbid 235 . 2 (𝑣 = 𝐴 → ∃𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑)))
171, 16vtocle 3525 1 𝑧𝑦(𝑦𝑧 ↔ ∃𝑥(𝑥𝐴𝜑))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401  wal 1568   = wceq 1570  wex 1812  wcel 2146  wnfc 2912  Vcvv 3457
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2737  ax-rep 5240
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-nf 1817  df-cleq 2757  df-clel 2840  df-nfc 2914
This theorem is used by:  zfrep3cl  5255  zfrep4  5256
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