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Theorem 3brtr4g 4032
Description: Substitution of equality into both sides of a binary relation. (Contributed by NM, 16-Jan-1997.)
Hypotheses
Ref Expression
3brtr4g.1 (𝜑𝐴𝑅𝐵)
3brtr4g.2 𝐶 = 𝐴
3brtr4g.3 𝐷 = 𝐵
Assertion
Ref Expression
3brtr4g (𝜑𝐶𝑅𝐷)

Proof of Theorem 3brtr4g
StepHypRef Expression
1 3brtr4g.1 . 2 (𝜑𝐴𝑅𝐵)
2 3brtr4g.2 . . 3 𝐶 = 𝐴
3 3brtr4g.3 . . 3 𝐷 = 𝐵
42, 3breq12i 4007 . 2 (𝐶𝑅𝐷𝐴𝑅𝐵)
51, 4sylibr 134 1 (𝜑𝐶𝑅𝐷)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1353   class class class wbr 3998
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1445  ax-7 1446  ax-gen 1447  ax-ie1 1491  ax-ie2 1492  ax-8 1502  ax-10 1503  ax-11 1504  ax-i12 1505  ax-bndl 1507  ax-4 1508  ax-17 1524  ax-i9 1528  ax-ial 1532  ax-i5r 1533  ax-ext 2157
This theorem depends on definitions:  df-bi 117  df-3an 980  df-tru 1356  df-nf 1459  df-sb 1761  df-clab 2162  df-cleq 2168  df-clel 2171  df-nfc 2306  df-v 2737  df-un 3131  df-sn 3595  df-pr 3596  df-op 3598  df-br 3999
This theorem is referenced by:  eqbrtrid  4033  enpr2d  6807  crth  12189  4sqlem6  12346  trilpolemgt1  14328
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