Theorem ifbi 3397

Description: Equivalence theorem for conditional operators. (Contributed by Raph Levien, 15-Jan-2004.)

Assertion

Ref	Expression
ifbi	⊢ ((𝜑 ↔ 𝜓) → if(𝜑, 𝐴, 𝐵) = if(𝜓, 𝐴, 𝐵))

Proof of Theorem ifbi

Dummy variable 𝑥 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		anbi2 455	. . . 4 ⊢ ((𝜑 ↔ 𝜓) → ((𝑥 ∈ 𝐴 ∧ 𝜑) ↔ (𝑥 ∈ 𝐴 ∧ 𝜓)))
2		id 19	. . . . . 6 ⊢ ((𝜑 ↔ 𝜓) → (𝜑 ↔ 𝜓))
3	2	notbid 625	. . . . 5 ⊢ ((𝜑 ↔ 𝜓) → (¬ 𝜑 ↔ ¬ 𝜓))
4	3	anbi2d 452	. . . 4 ⊢ ((𝜑 ↔ 𝜓) → ((𝑥 ∈ 𝐵 ∧ ¬ 𝜑) ↔ (𝑥 ∈ 𝐵 ∧ ¬ 𝜓)))
5	1, 4	orbi12d 740	. . 3 ⊢ ((𝜑 ↔ 𝜓) → (((𝑥 ∈ 𝐴 ∧ 𝜑) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜑)) ↔ ((𝑥 ∈ 𝐴 ∧ 𝜓) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜓))))
6	5	abbidv 2202	. 2 ⊢ ((𝜑 ↔ 𝜓) → {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜑))} = {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜓) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜓))})
7		df-if 3380	. 2 ⊢ if(𝜑, 𝐴, 𝐵) = {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜑))}
8		df-if 3380	. 2 ⊢ if(𝜓, 𝐴, 𝐵) = {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜓) ∨ (𝑥 ∈ 𝐵 ∧ ¬ 𝜓))}
9	6, 7, 8	3eqtr4g 2142	1 ⊢ ((𝜑 ↔ 𝜓) → if(𝜑, 𝐴, 𝐵) = if(𝜓, 𝐴, 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   ∧ wa 102   ↔ wb 103   ∨ wo 662   = wceq 1287   ∈ wcel 1436  {cab 2071  ifcif 3379

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in1 577  ax-in2 578  ax-io 663  ax-5 1379  ax-7 1380  ax-gen 1381  ax-ie1 1425  ax-ie2 1426  ax-8 1438  ax-11 1440  ax-4 1443  ax-17 1462  ax-i9 1466  ax-ial 1470  ax-i5r 1471  ax-ext 2067

This theorem depends on definitions:  df-bi 115  df-tru 1290  df-nf 1393  df-sb 1690  df-clab 2072  df-cleq 2078  df-if 3380

This theorem is referenced by:  ifbid  3398  ifbieq2i  3400  fodjuomni  6748  1tonninf  9774  nninfsellemqall  11345  nninfomni  11349