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Theorem disjresdif 38914
Description: The difference between restrictions to disjoint is the first restriction. (Contributed by Peter Mazsa, 24-Jul-2024.)
Assertion
Ref Expression
disjresdif ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))

Proof of Theorem disjresdif
StepHypRef Expression
1 disjresdisj 38913 . 2 ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∩ (𝑅𝐵)) = ∅)
2 disjdif2 4441 . 2 (((𝑅𝐴) ∩ (𝑅𝐵)) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))
31, 2syl 18 1 ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1570  cdif 3902  cin 3904  c0 4286  cres 5663
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735  ax-sep 5257  ax-pr 5404
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-ral 3080  df-rex 3090  df-rab 3417  df-v 3457  df-dif 3908  df-un 3910  df-in 3912  df-ss 3922  df-nul 4287  df-if 4488  df-sn 4590  df-pr 4592  df-op 4596  df-opab 5174  df-xp 5667  df-rel 5668  df-res 5673
This theorem is referenced by:  disjresundif  38915
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