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Theorem disjresdif 38784
Description: The difference between restrictions to disjoint is the first restriction. (Contributed by Peter Mazsa, 24-Jul-2024.)
Assertion
Ref Expression
disjresdif ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))

Proof of Theorem disjresdif
StepHypRef Expression
1 disjresdisj 38783 . 2 ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∩ (𝑅𝐵)) = ∅)
2 disjdif2 4446 . 2 (((𝑅𝐴) ∩ (𝑅𝐵)) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))
31, 2syl 18 1 ((𝐴𝐵) = ∅ → ((𝑅𝐴) ∖ (𝑅𝐵)) = (𝑅𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1567  cdif 3910  cin 3912  c0 4294  cres 5664
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-8 2151  ax-9 2159  ax-ext 2741  ax-sep 5261  ax-pr 5405
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1570  df-fal 1580  df-ex 1807  df-sb 2098  df-clab 2748  df-cleq 2761  df-clel 2844  df-ral 3086  df-rex 3096  df-rab 3424  df-v 3465  df-dif 3916  df-un 3918  df-in 3920  df-ss 3930  df-nul 4295  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-opab 5178  df-xp 5668  df-rel 5669  df-res 5674
This theorem is referenced by:  disjresundif  38785
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