Theorem dmqseqeq1i 39327

Description: Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021.)

Hypothesis

Ref	Expression
dmqseqeq1i.1	⊢ 𝑅 = 𝑆

Assertion

Ref	Expression
dmqseqeq1i	⊢ ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴)

Proof of Theorem dmqseqeq1i

Step	Hyp	Ref	Expression
1		dmqseqeq1i.1	. 2 ⊢ 𝑅 = 𝑆
2		dmqseqeq1 39326	. 2 ⊢ (𝑅 = 𝑆 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴))
3	1, 2	ax-mp 5	1 ⊢ ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴)

Syntax hints:   ↔ wb 209   = wceq 1568  dom cdm 5665   / cqs 8696

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1823  ax-4 1837  ax-5 1938  ax-6 1995  ax-7 2036  ax-8 2152  ax-9 2160  ax-ext 2742

This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1571  df-fal 1581  df-ex 1808  df-sb 2099  df-clab 2749  df-cleq 2762  df-clel 2845  df-rex 3097  df-rab 3424  df-v 3464  df-dif 3916  df-un 3918  df-in 3920  df-ss 3930  df-nul 4295  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-br 5115  df-opab 5179  df-cnv 5673  df-dm 5675  df-rn 5676  df-res 5677  df-ima 5678  df-ec 8699  df-qs 8703

This theorem is referenced by:  dmqs1cosscnvepreseq  39346