Users' Mathboxes Mathbox for Peter Mazsa < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  dmqseqeq1d Structured version   Visualization version   GIF version

Theorem dmqseqeq1d 38842
Description: Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 26-Sep-2021.)
Hypothesis
Ref Expression
dmqseqeq1d.1 (𝜑𝑅 = 𝑆)
Assertion
Ref Expression
dmqseqeq1d (𝜑 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴))

Proof of Theorem dmqseqeq1d
StepHypRef Expression
1 dmqseqeq1d.1 . 2 (𝜑𝑅 = 𝑆)
2 dmqseqeq1 38840 . 2 (𝑅 = 𝑆 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴))
31, 2syl 17 1 (𝜑 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206   = wceq 1541  dom cdm 5622   / cqs 8632
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2706
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2713  df-cleq 2726  df-clel 2809  df-rex 3059  df-rab 3398  df-v 3440  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4284  df-if 4478  df-sn 4579  df-pr 4581  df-op 4585  df-br 5097  df-opab 5159  df-cnv 5630  df-dm 5632  df-rn 5633  df-res 5634  df-ima 5635  df-ec 8635  df-qs 8639
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator