Theorem dmqseqi 38758

Description: Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021.)

Hypothesis

Ref	Expression
dmqseqi.1	⊢ 𝑅 = 𝑆

Assertion

Ref	Expression
dmqseqi	⊢ (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)

Proof of Theorem dmqseqi

Step	Hyp	Ref	Expression
1		dmqseqi.1	. 2 ⊢ 𝑅 = 𝑆
2		dmqseq 38757	. 2 ⊢ (𝑅 = 𝑆 → (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆))
3	1, 2	ax-mp 5	1 ⊢ (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)

Syntax hints:   = wceq 1541  dom cdm 5619   / cqs 8627

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2705

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2712  df-cleq 2725  df-clel 2808  df-rex 3058  df-rab 3397  df-v 3439  df-dif 3901  df-un 3903  df-in 3905  df-ss 3915  df-nul 4283  df-if 4475  df-sn 4576  df-pr 4578  df-op 4582  df-br 5094  df-opab 5156  df-cnv 5627  df-dm 5629  df-rn 5630  df-res 5631  df-ima 5632  df-ec 8630  df-qs 8634

This theorem is referenced by: (None)