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| Mirrors > Home > MPE Home > Th. List > invdisjrab | Structured version Visualization version GIF version | ||
| Description: The restricted class abstractions {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} for distinct 𝑦 ∈ 𝐴 are disjoint. (Contributed by AV, 6-May-2020.) (Proof shortened by GG, 26-Jan-2024.) |
| Ref | Expression |
|---|---|
| invdisjrab | ⊢ Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfcv 2899 | . . . . 5 ⊢ Ⅎ𝑥𝑧 | |
| 2 | nfcv 2899 | . . . . 5 ⊢ Ⅎ𝑥𝐵 | |
| 3 | nfcsb1v 3875 | . . . . . 6 ⊢ Ⅎ𝑥⦋𝑧 / 𝑥⦌𝐶 | |
| 4 | 3 | nfeq1 2915 | . . . . 5 ⊢ Ⅎ𝑥⦋𝑧 / 𝑥⦌𝐶 = 𝑦 |
| 5 | csbeq1a 3865 | . . . . . 6 ⊢ (𝑥 = 𝑧 → 𝐶 = ⦋𝑧 / 𝑥⦌𝐶) | |
| 6 | 5 | eqeq1d 2739 | . . . . 5 ⊢ (𝑥 = 𝑧 → (𝐶 = 𝑦 ↔ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) |
| 7 | 1, 2, 4, 6 | elrabf 3645 | . . . 4 ⊢ (𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} ↔ (𝑧 ∈ 𝐵 ∧ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) |
| 8 | simprr 773 | . . . 4 ⊢ ((𝑦 ∈ 𝐴 ∧ (𝑧 ∈ 𝐵 ∧ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) → ⦋𝑧 / 𝑥⦌𝐶 = 𝑦) | |
| 9 | 7, 8 | sylan2b 595 | . . 3 ⊢ ((𝑦 ∈ 𝐴 ∧ 𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}) → ⦋𝑧 / 𝑥⦌𝐶 = 𝑦) |
| 10 | 9 | rgen2 3178 | . 2 ⊢ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}⦋𝑧 / 𝑥⦌𝐶 = 𝑦 |
| 11 | invdisj 5086 | . 2 ⊢ (∀𝑦 ∈ 𝐴 ∀𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}⦋𝑧 / 𝑥⦌𝐶 = 𝑦 → Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}) | |
| 12 | 10, 11 | ax-mp 5 | 1 ⊢ Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} |
| Colors of variables: wff setvar class |
| Syntax hints: ∧ wa 395 = wceq 1542 ∈ wcel 2114 ∀wral 3052 {crab 3401 ⦋csb 3851 Disj wdisj 5067 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1912 ax-6 1969 ax-7 2010 ax-8 2116 ax-9 2124 ax-10 2147 ax-11 2163 ax-12 2185 ax-ext 2709 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 849 df-tru 1545 df-ex 1782 df-nf 1786 df-sb 2069 df-mo 2540 df-clab 2716 df-cleq 2729 df-clel 2812 df-nfc 2886 df-ral 3053 df-rmo 3352 df-rab 3402 df-v 3444 df-sbc 3743 df-csb 3852 df-disj 5068 |
| This theorem is referenced by: disjwrdpfx 14635 |
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