| Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
| Mirrors > Home > MPE Home > Th. List > invdisjrab | Structured version Visualization version GIF version | ||
| Description: The restricted class abstractions {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} for distinct 𝑦 ∈ 𝐴 are disjoint. (Contributed by AV, 6-May-2020.) (Proof shortened by GG, 26-Jan-2024.) |
| Ref | Expression |
|---|---|
| invdisjrab | ⊢ Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfcv 2931 | . . . . 5 ⊢ Ⅎ𝑥𝑧 | |
| 2 | nfcv 2931 | . . . . 5 ⊢ Ⅎ𝑥𝐵 | |
| 3 | nfcsb1v 3885 | . . . . . 6 ⊢ Ⅎ𝑥⦋𝑧 / 𝑥⦌𝐶 | |
| 4 | 3 | nfeq1 2946 | . . . . 5 ⊢ Ⅎ𝑥⦋𝑧 / 𝑥⦌𝐶 = 𝑦 |
| 5 | csbeq1a 3875 | . . . . . 6 ⊢ (𝑥 = 𝑧 → 𝐶 = ⦋𝑧 / 𝑥⦌𝐶) | |
| 6 | 5 | eqeq1d 2771 | . . . . 5 ⊢ (𝑥 = 𝑧 → (𝐶 = 𝑦 ↔ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) |
| 7 | 1, 2, 4, 6 | elrabf 3656 | . . . 4 ⊢ (𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} ↔ (𝑧 ∈ 𝐵 ∧ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) |
| 8 | simprr 784 | . . . 4 ⊢ ((𝑦 ∈ 𝐴 ∧ (𝑧 ∈ 𝐵 ∧ ⦋𝑧 / 𝑥⦌𝐶 = 𝑦)) → ⦋𝑧 / 𝑥⦌𝐶 = 𝑦) | |
| 9 | 7, 8 | sylan2b 605 | . . 3 ⊢ ((𝑦 ∈ 𝐴 ∧ 𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}) → ⦋𝑧 / 𝑥⦌𝐶 = 𝑦) |
| 10 | 9 | rgen2 3211 | . 2 ⊢ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}⦋𝑧 / 𝑥⦌𝐶 = 𝑦 |
| 11 | invdisj 5099 | . 2 ⊢ (∀𝑦 ∈ 𝐴 ∀𝑧 ∈ {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}⦋𝑧 / 𝑥⦌𝐶 = 𝑦 → Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦}) | |
| 12 | 10, 11 | ax-mp 5 | 1 ⊢ Disj 𝑦 ∈ 𝐴 {𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦} |
| Colors of variables: wff setvar class |
| Syntax hints: ∧ wa 400 = wceq 1567 ∈ wcel 2149 ∀wral 3085 {crab 3423 ⦋csb 3861 Disj wdisj 5080 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-10 2182 ax-11 2198 ax-12 2219 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-or 861 df-tru 1570 df-ex 1807 df-nf 1811 df-sb 2098 df-mo 2573 df-clab 2748 df-cleq 2761 df-clel 2844 df-nfc 2918 df-ral 3086 df-rmo 3376 df-rab 3424 df-v 3465 df-sbc 3754 df-csb 3862 df-disj 5081 |
| This theorem is referenced by: disjwrdpfx 14736 |
| Copyright terms: Public domain | W3C validator |