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Theorem iotasbc2 44960
Description: Theorem *14.111 in [WhiteheadRussell] p. 184. (Contributed by Andrew Salmon, 11-Jul-2011.)
Assertion
Ref Expression
iotasbc2 ((∃!𝑥𝜑 ∧ ∃!𝑥𝜓) → ([(℩𝑥𝜑) / 𝑦][(℩𝑥𝜓) / 𝑧]𝜒 ↔ ∃𝑦𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
Distinct variable groups:   𝑥,𝑦,𝑧   𝜑,𝑦,𝑧   𝜓,𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)   𝜒(𝑥,𝑦,𝑧)

Proof of Theorem iotasbc2
StepHypRef Expression
1 iotasbc 44959 . 2 (∃!𝑥𝜑 → ([(℩𝑥𝜑) / 𝑦][(℩𝑥𝜓) / 𝑧]𝜒 ↔ ∃𝑦(∀𝑥(𝜑𝑥 = 𝑦) ∧ [(℩𝑥𝜓) / 𝑧]𝜒)))
2 iotasbc 44959 . . . . 5 (∃!𝑥𝜓 → ([(℩𝑥𝜓) / 𝑧]𝜒 ↔ ∃𝑧(∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
32anbi2d 639 . . . 4 (∃!𝑥𝜓 → ((∀𝑥(𝜑𝑥 = 𝑦) ∧ [(℩𝑥𝜓) / 𝑧]𝜒) ↔ (∀𝑥(𝜑𝑥 = 𝑦) ∧ ∃𝑧(∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒))))
4 3anass 1105 . . . . . 6 ((∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒) ↔ (∀𝑥(𝜑𝑥 = 𝑦) ∧ (∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
54exbii 1867 . . . . 5 (∃𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒) ↔ ∃𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ (∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
6 19.42v 1972 . . . . 5 (∃𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ (∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)) ↔ (∀𝑥(𝜑𝑥 = 𝑦) ∧ ∃𝑧(∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
75, 6bitr2i 278 . . . 4 ((∀𝑥(𝜑𝑥 = 𝑦) ∧ ∃𝑧(∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)) ↔ ∃𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒))
83, 7bitrdi 289 . . 3 (∃!𝑥𝜓 → ((∀𝑥(𝜑𝑥 = 𝑦) ∧ [(℩𝑥𝜓) / 𝑧]𝜒) ↔ ∃𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
98exbidv 1940 . 2 (∃!𝑥𝜓 → (∃𝑦(∀𝑥(𝜑𝑥 = 𝑦) ∧ [(℩𝑥𝜓) / 𝑧]𝜒) ↔ ∃𝑦𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
101, 9sylan9bb 517 1 ((∃!𝑥𝜑 ∧ ∃!𝑥𝜓) → ([(℩𝑥𝜑) / 𝑦][(℩𝑥𝜓) / 𝑧]𝜒 ↔ ∃𝑦𝑧(∀𝑥(𝜑𝑥 = 𝑦) ∧ ∀𝑥(𝜓𝑥 = 𝑧) ∧ 𝜒)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wa 399  w3a 1097  wal 1557  wex 1798  ∃!weu 2594  [wsbc 3744  cio 6471
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-10 2174  ax-12 2211  ax-ext 2733
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1099  df-tru 1562  df-ex 1799  df-nf 1803  df-sb 2090  df-mo 2565  df-eu 2595  df-clab 2740  df-cleq 2753  df-clel 2836  df-v 3455  df-sbc 3745  df-un 3909  df-ss 3921  df-sn 4582  df-pr 4584  df-uni 4865  df-iota 6473
This theorem is referenced by: (None)
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