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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | xppss12 43101 | Proper subset theorem for Cartesian product. (Contributed by Steven Nguyen, 17-Jul-2022.) |
| ⊢ ((𝐴 ⊊ 𝐵 ∧ 𝐶 ⊊ 𝐷) → (𝐴 × 𝐶) ⊊ (𝐵 × 𝐷)) | ||
| Theorem | elpwbi 43102 | Membership in a power set, biconditional. (Contributed by Steven Nguyen, 17-Jul-2022.) (Proof shortened by Steven Nguyen, 16-Sep-2022.) |
| ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 ∈ 𝒫 𝐵) | ||
| Theorem | imaopab 43103* | The image of a class of ordered pairs. (Contributed by Steven Nguyen, 6-Jun-2023.) |
| ⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} “ 𝐴) = {𝑦 ∣ ∃𝑥 ∈ 𝐴 𝜑} | ||
| Theorem | eqresfnbd 43104 | Property of being the restriction of a function. Note that this is closer to funssres 6581 than fnssres 6659. (Contributed by SN, 11-Mar-2025.) |
| ⊢ (𝜑 → 𝐹 Fn 𝐵) & ⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝑅 = (𝐹 ↾ 𝐴) ↔ (𝑅 Fn 𝐴 ∧ 𝑅 ⊆ 𝐹))) | ||
| Theorem | fmpocos 43105* | Composition of two functions. Variation of fmpoco 8095 with more context in the substitution hypothesis for 𝑇. (Contributed by SN, 14-Mar-2025.) |
| ⊢ ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵)) → 𝑅 ∈ 𝐶) & ⊢ (𝜑 → 𝐹 = (𝑥 ∈ 𝐴, 𝑦 ∈ 𝐵 ↦ 𝑅)) & ⊢ (𝜑 → 𝐺 = (𝑧 ∈ 𝐶 ↦ 𝑆)) & ⊢ ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵)) → ⦋𝑅 / 𝑧⦌𝑆 = 𝑇) ⇒ ⊢ (𝜑 → (𝐺 ∘ 𝐹) = (𝑥 ∈ 𝐴, 𝑦 ∈ 𝐵 ↦ 𝑇)) | ||
| Theorem | ovmpogad 43106* | Value of an operation given by a maps-to rule. Deduction form of ovmpoga 7570. (Contributed by SN, 14-Mar-2025.) |
| ⊢ 𝐹 = (𝑥 ∈ 𝐶, 𝑦 ∈ 𝐷 ↦ 𝑅) & ⊢ ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → 𝑅 = 𝑆) & ⊢ (𝜑 → 𝐴 ∈ 𝐶) & ⊢ (𝜑 → 𝐵 ∈ 𝐷) & ⊢ (𝜑 → 𝑆 ∈ 𝑉) ⇒ ⊢ (𝜑 → (𝐴𝐹𝐵) = 𝑆) | ||
| Theorem | ofun 43107 | A function operation of unions of disjoint functions is a union of function operations. (Contributed by SN, 16-Jun-2024.) |
| ⊢ (𝜑 → 𝐴 Fn 𝑀) & ⊢ (𝜑 → 𝐵 Fn 𝑀) & ⊢ (𝜑 → 𝐶 Fn 𝑁) & ⊢ (𝜑 → 𝐷 Fn 𝑁) & ⊢ (𝜑 → 𝑀 ∈ 𝑉) & ⊢ (𝜑 → 𝑁 ∈ 𝑊) & ⊢ (𝜑 → (𝑀 ∩ 𝑁) = ∅) ⇒ ⊢ (𝜑 → ((𝐴 ∪ 𝐶) ∘f 𝑅(𝐵 ∪ 𝐷)) = ((𝐴 ∘f 𝑅𝐵) ∪ (𝐶 ∘f 𝑅𝐷))) | ||
| Theorem | dfqs3 43108* | Alternate definition of quotient set. (Contributed by Steven Nguyen, 7-Jun-2023.) |
| ⊢ (𝐴 / 𝑅) = ∪ 𝑥 ∈ 𝐴 {[𝑥]𝑅} | ||
| Theorem | qseq12d 43109 | Equality theorem for quotient set, deduction form. (Contributed by Steven Nguyen, 30-Apr-2023.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 / 𝐶) = (𝐵 / 𝐷)) | ||
| Theorem | qsalrel 43110* | The quotient set is equal to the singleton of 𝐴 when all elements are related and 𝐴 is nonempty. (Contributed by SN, 8-Jun-2023.) |
| ⊢ ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐴)) → 𝑥 ∼ 𝑦) & ⊢ (𝜑 → ∼ Er 𝐴) & ⊢ (𝜑 → 𝑁 ∈ 𝐴) ⇒ ⊢ (𝜑 → (𝐴 / ∼ ) = {𝐴}) | ||
| Theorem | supinf 43111* | The supremum is the infimum of the upper bounds. (Contributed by SN, 29-Jun-2025.) |
| ⊢ (𝜑 → < Or 𝐴) & ⊢ (𝜑 → ∃𝑥 ∈ 𝐴 (∀𝑦 ∈ 𝐵 ¬ 𝑥 < 𝑦 ∧ ∀𝑦 ∈ 𝐴 (𝑦 < 𝑥 → ∃𝑧 ∈ 𝐵 𝑦 < 𝑧))) ⇒ ⊢ (𝜑 → sup(𝐵, 𝐴, < ) = inf({𝑥 ∈ 𝐴 ∣ ∀𝑤 ∈ 𝐵 ¬ 𝑥 < 𝑤}, 𝐴, < )) | ||
| Theorem | mapcod 43112 | Compose two mappings. (Contributed by SN, 11-Mar-2025.) |
| ⊢ (𝜑 → 𝐹 ∈ (𝐴 ↑m 𝐵)) & ⊢ (𝜑 → 𝐺 ∈ (𝐵 ↑m 𝐶)) ⇒ ⊢ (𝜑 → (𝐹 ∘ 𝐺) ∈ (𝐴 ↑m 𝐶)) | ||
| Theorem | fisdomnn 43113 | A finite set is dominated by the set of natural numbers. (Contributed by SN, 6-Jul-2025.) |
| ⊢ (𝐴 ∈ Fin → 𝐴 ≺ ℕ) | ||
| Theorem | ltex 43114 | The less-than relation is a set. (Contributed by SN, 5-Jun-2025.) |
| ⊢ < ∈ V | ||
| Theorem | leex 43115 | The less-than-or-equal-to relation is a set. (Contributed by SN, 5-Jun-2025.) |
| ⊢ ≤ ∈ V | ||
| Theorem | subex 43116 | The subtraction operation is a set. (Contributed by SN, 5-Jun-2025.) |
| ⊢ − ∈ V | ||
| Theorem | absex 43117 | The absolute value function is a set. (Contributed by SN, 5-Jun-2025.) |
| ⊢ abs ∈ V | ||
| Theorem | cjex 43118 | The conjugate function is a set. (Contributed by SN, 5-Jun-2025.) |
| ⊢ ∗ ∈ V | ||
| Theorem | fzosumm1 43119* | Separate out the last term in a finite sum. (Contributed by Steven Nguyen, 22-Aug-2023.) |
| ⊢ (𝜑 → (𝑁 − 1) ∈ (ℤ≥‘𝑀)) & ⊢ ((𝜑 ∧ 𝑘 ∈ (𝑀..^𝑁)) → 𝐴 ∈ ℂ) & ⊢ (𝑘 = (𝑁 − 1) → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝑁 ∈ ℤ) ⇒ ⊢ (𝜑 → Σ𝑘 ∈ (𝑀..^𝑁)𝐴 = (Σ𝑘 ∈ (𝑀..^(𝑁 − 1))𝐴 + 𝐵)) | ||
| Theorem | ccatcan2d 43120 | Cancellation law for concatenation. (Contributed by SN, 6-Sep-2023.) |
| ⊢ (𝜑 → 𝐴 ∈ Word 𝑉) & ⊢ (𝜑 → 𝐵 ∈ Word 𝑉) & ⊢ (𝜑 → 𝐶 ∈ Word 𝑉) ⇒ ⊢ (𝜑 → ((𝐴 ++ 𝐶) = (𝐵 ++ 𝐶) ↔ 𝐴 = 𝐵)) | ||
Towards the start of this section are several proofs regarding the different complex number axioms that could be used to prove some results. For example, ax-1rid 11197 is used in mulrid 11233 related theorems, so one could trade off the extra axioms in mulrid 11233 for the axioms needed to prove that something is a real number. Another example is avoiding complex number closure laws by using real number closure laws and then using ax-resscn 11184; in the other direction, real number closure laws can be avoided by using ax-resscn 11184 and then the complex number closure laws. (This only works if the result of (𝐴 + 𝐵) only needs to be a complex number). The natural numbers are especially amenable to axiom reductions, as the set ℕ is the recursive set {1, (1 + 1), ((1 + 1) + 1)}, etc., i.e. the set of numbers formed by only additions of 1. The digits 2 through 9 are defined so that they expand into additions of 1. This conveniently allows for adding natural numbers by rearranging parentheses, as shown below: (4 + 3) = 7 ((3 + 1) + (2 + 1)) = (6 + 1) ((((1 + 1) + 1) + 1) + ((1 + 1) + 1)) = ((((((1 + 1) + 1) + 1) + 1) + 1) + 1) This only requires ax-addass 11192, ax-1cn 11185, and ax-addcl 11187. (And in practice, the expression isn't fully expanded into ones.) Multiplication by 1 requires either mullidi 11241 or (ax-1rid 11197 and 1re 11235) as seen in 1t1e1 12429 and 1t1e1ALT 12318. Multiplying with greater natural numbers uses ax-distr 11194. Still, this takes fewer axioms than adding zero, which is often implicit in theorems such as (9 + 1) = ;10. Adding zero uses almost every complex number axiom, though notably not ax-mulcom 11191 (see readdrid 43287 and readdlid 43280). | ||
| Theorem | c0exALT 43121 | Alternate proof of c0ex 11227 using more set theory axioms but fewer complex number axioms (add ax-10 2178, ax-11 2194, ax-13 2403, ax-nul 5267, and remove ax-1cn 11185, ax-icn 11186, ax-addcl 11187, and ax-mulcl 11189). (Contributed by Steven Nguyen, 4-Dec-2022.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 0 ∈ V | ||
| Theorem | 0cnALT3 43122 | Alternate proof of 0cn 11225 using ax-resscn 11184, ax-addrcl 11188, ax-rnegex 11198, ax-cnre 11200 instead of ax-icn 11186, ax-addcl 11187, ax-mulcl 11189, ax-i2m1 11195. Version of 0cnALT 11472 using ax-1cn 11185 instead of ax-icn 11186. (Contributed by Steven Nguyen, 7-Jan-2022.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 0 ∈ ℂ | ||
| Theorem | elre0re 43123 | Specialized version of 0red 11238 without using ax-1cn 11185 and ax-cnre 11200. (Contributed by Steven Nguyen, 28-Jan-2023.) |
| ⊢ (𝐴 ∈ ℝ → 0 ∈ ℝ) | ||
| Theorem | lttrii 43124 | 'Less than' is transitive. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 𝐴 ∈ ℝ & ⊢ 𝐵 ∈ ℝ & ⊢ 𝐶 ∈ ℝ & ⊢ 𝐴 < 𝐵 & ⊢ 𝐵 < 𝐶 ⇒ ⊢ 𝐴 < 𝐶 | ||
| Theorem | remulcan2d 43125 | mulcan2d 11875 for real numbers using fewer axioms. (Contributed by Steven Nguyen, 15-Apr-2023.) |
| ⊢ (𝜑 → 𝐴 ∈ ℝ) & ⊢ (𝜑 → 𝐵 ∈ ℝ) & ⊢ (𝜑 → 𝐶 ∈ ℝ) & ⊢ (𝜑 → 𝐶 ≠ 0) ⇒ ⊢ (𝜑 → ((𝐴 · 𝐶) = (𝐵 · 𝐶) ↔ 𝐴 = 𝐵)) | ||
| Theorem | readdridaddlidd 43126 | Given some real number 𝐵 where 𝐴 acts like a right additive identity, derive that 𝐴 is a left additive identity. Note that the hypothesis is weaker than proving that 𝐴 is a right additive identity (for all numbers). Although, if there is a right additive identity, then by readdcan 11411, 𝐴 is the right additive identity. (Contributed by Steven Nguyen, 14-Jan-2023.) |
| ⊢ (𝜑 → 𝐴 ∈ ℝ) & ⊢ (𝜑 → 𝐵 ∈ ℝ) & ⊢ (𝜑 → (𝐵 + 𝐴) = 𝐵) ⇒ ⊢ ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶) | ||
| Theorem | 4p4e8ALT 43127 | A shorter proof of 4p4e8 12422 if 6p2e8 12426 was moved up. The most clean way to do this would be to start with 7p2e9 12428, then go 6p2e8 12426, 6p3e9 12427, etc., which is still inelegant. The idea here is that using 4 = 2 + 2 and 2cn 12343 is shorter than using 4 = 3 + 1, 3cn 12349, and ax-1cn 11185. This also works with 5p4e9 12425. (Contributed by SN, 24-Aug-2026.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ (4 + 4) = 8 | ||
| Theorem | 1p3e4 43128 | 1 + 3 = 4. (Contributed by SN, 19-Nov-2025.) |
| ⊢ (1 + 3) = 4 | ||
| Theorem | 1p4e5 43129 | 1 + 4 = 5. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (1 + 4) = 5 | ||
| Theorem | 1p5e6 43130 | 1 + 5 = 6. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (1 + 5) = 6 | ||
| Theorem | 1p6e7 43131 | 1 + 6 = 7. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (1 + 6) = 7 | ||
| Theorem | 1p7e8 43132 | 1 + 7 = 8. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (1 + 7) = 8 | ||
| Theorem | 1p8e9 43133 | 1 + 8 = 9. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (1 + 8) = 9 | ||
| Theorem | 2p3e5 43134 | 2 + 3 = 5. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (2 + 3) = 5 | ||
| Theorem | 2p4e6 43135 | 2 + 4 = 6. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (2 + 4) = 6 | ||
| Theorem | 2p5e7 43136 | 2 + 5 = 7. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (2 + 5) = 7 | ||
| Theorem | 2p6e8 43137 | 2 + 6 = 8. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (2 + 6) = 8 | ||
| Theorem | 2p7e9 43138 | 2 + 7 = 9. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (2 + 7) = 9 | ||
| Theorem | 3p4e7 43139 | 3 + 4 = 7. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (3 + 4) = 7 | ||
| Theorem | 3p5e8 43140 | 3 + 5 = 8. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (3 + 5) = 8 | ||
| Theorem | 3p6e9 43141 | 3 + 6 = 9. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (3 + 6) = 9 | ||
| Theorem | 4p5e9 43142 | 4 + 5 = 9. (Contributed by SN, 24-Aug-2026.) |
| ⊢ (4 + 5) = 9 | ||
| Theorem | 5ne0 43143 | The number 5 is nonzero. (Contributed by SN, 22-Oct-2025.) |
| ⊢ 5 ≠ 0 | ||
| Theorem | 6ne0 43144 | The number 6 is nonzero. (Contributed by SN, 22-Oct-2025.) |
| ⊢ 6 ≠ 0 | ||
| Theorem | 7ne0 43145 | The number 7 is nonzero. (Contributed by SN, 22-Oct-2025.) |
| ⊢ 7 ≠ 0 | ||
| Theorem | 8ne0 43146 | The number 8 is nonzero. (Contributed by SN, 22-Oct-2025.) |
| ⊢ 8 ≠ 0 | ||
| Theorem | 9ne0 43147 | The number 9 is nonzero. (Contributed by SN, 22-Oct-2025.) |
| ⊢ 9 ≠ 0 | ||
| Theorem | sn-1ne2 43148 | A proof of 1ne2 12478 without using ax-mulcom 11191, ax-mulass 11193, ax-pre-mulgt0 11204. Based on mul02lem2 11414. (Contributed by SN, 13-Dec-2023.) |
| ⊢ 1 ≠ 2 | ||
| Theorem | nnn1suc 43149* | A positive integer that is not 1 is a successor of some other positive integer. (Contributed by Steven Nguyen, 19-Aug-2023.) |
| ⊢ ((𝐴 ∈ ℕ ∧ 𝐴 ≠ 1) → ∃𝑥 ∈ ℕ (𝑥 + 1) = 𝐴) | ||
| Theorem | readdrcl2d 43150 | Reverse closure for addition: the second addend is real if the first addend is real and the sum is real. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (𝜑 → 𝐴 ∈ ℝ) & ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → (𝐴 + 𝐵) ∈ ℝ) ⇒ ⊢ (𝜑 → 𝐵 ∈ ℝ) | ||
| Theorem | mvrrsubd 43151 |
Move a subtraction in the RHS to a right-addition in the LHS. Converse
of mvlraddd 11651.
EDITORIAL: Do not move until it would have 7 uses: current additional uses: (none). (Contributed by SN, 21-Aug-2024.) |
| ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → 𝐶 ∈ ℂ) & ⊢ (𝜑 → 𝐴 = (𝐵 − 𝐶)) ⇒ ⊢ (𝜑 → (𝐴 + 𝐶) = 𝐵) | ||
| Theorem | laddrotrd 43152 |
Rotate the variables right in an equation with addition on the left,
converting it into a subtraction. Version of mvlladdd 11652 with a commuted
consequent, and of mvrladdd 11654 with a commuted hypothesis.
EDITORIAL: The label for this theorem is questionable. Do not move until it would have 7 uses: current additional uses: ply1dg3rt0irred 33996. (Contributed by SN, 21-Aug-2024.) |
| ⊢ (𝜑 → 𝐴 ∈ ℂ) & ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → (𝐴 + 𝐵) = 𝐶) ⇒ ⊢ (𝜑 → (𝐶 − 𝐴) = 𝐵) | ||
| Theorem | raddswap12d 43153 |
Swap the first two variables in an equation with addition on the right,
converting it into a subtraction. Version of mvrraddd 11653 with a commuted
consequent, and of mvlraddd 11651 with a commuted hypothesis.
EDITORIAL: The label for this theorem is questionable. Do not move until it would have 7 uses: current additional uses: (none). (Contributed by SN, 21-Aug-2024.) |
| ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → 𝐶 ∈ ℂ) & ⊢ (𝜑 → 𝐴 = (𝐵 + 𝐶)) ⇒ ⊢ (𝜑 → 𝐵 = (𝐴 − 𝐶)) | ||
| Theorem | lsubrotld 43154 |
Rotate the variables left in an equation with subtraction on the left,
converting it into an addition.
EDITORIAL: The label for this theorem is questionable. Do not move until it would have 7 uses: current additional uses: (none). (Contributed by SN, 21-Aug-2024.) |
| ⊢ (𝜑 → 𝐴 ∈ ℂ) & ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → (𝐴 − 𝐵) = 𝐶) ⇒ ⊢ (𝜑 → (𝐵 + 𝐶) = 𝐴) | ||
| Theorem | rsubrotld 43155 |
Rotate the variables left in an equation with subtraction on the right,
converting it into an addition.
EDITORIAL: The label for this theorem is questionable. Do not move until it would have 7 uses: current additional uses: (none). (Contributed by SN, 4-Jul-2025.) |
| ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → 𝐶 ∈ ℂ) & ⊢ (𝜑 → 𝐴 = (𝐵 − 𝐶)) ⇒ ⊢ (𝜑 → 𝐵 = (𝐶 + 𝐴)) | ||
| Theorem | lsubswap23d 43156 |
Swap the second and third variables in an equation with subtraction on
the left, converting it into an addition.
EDITORIAL: The label for this theorem is questionable. Do not move until it would have 7 uses: current additional uses: (none). (Contributed by SN, 23-Aug-2024.) |
| ⊢ (𝜑 → 𝐴 ∈ ℂ) & ⊢ (𝜑 → 𝐵 ∈ ℂ) & ⊢ (𝜑 → (𝐴 − 𝐵) = 𝐶) ⇒ ⊢ (𝜑 → (𝐴 − 𝐶) = 𝐵) | ||
| Theorem | addsubeq4com 43157 | Relation between sums and differences. (Contributed by Steven Nguyen, 5-Jan-2023.) |
| ⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐵) = (𝐶 + 𝐷) ↔ (𝐴 − 𝐶) = (𝐷 − 𝐵))) | ||
| Theorem | sqsumi 43158 | A sum squared. (Contributed by Steven Nguyen, 16-Sep-2022.) |
| ⊢ 𝐴 ∈ ℂ & ⊢ 𝐵 ∈ ℂ ⇒ ⊢ ((𝐴 + 𝐵) · (𝐴 + 𝐵)) = (((𝐴 · 𝐴) + (𝐵 · 𝐵)) + (2 · (𝐴 · 𝐵))) | ||
| Theorem | negn0nposznnd 43159 | Lemma for dffltz 43482. (Contributed by Steven Nguyen, 27-Feb-2023.) |
| ⊢ (𝜑 → 𝐴 ≠ 0) & ⊢ (𝜑 → ¬ 0 < 𝐴) & ⊢ (𝜑 → 𝐴 ∈ ℤ) ⇒ ⊢ (𝜑 → -𝐴 ∈ ℕ) | ||
| Theorem | sqmid3api 43160 | Value of the square of the middle term of a 3-term arithmetic progression. (Contributed by Steven Nguyen, 20-Sep-2022.) |
| ⊢ 𝐴 ∈ ℂ & ⊢ 𝑁 ∈ ℂ & ⊢ (𝐴 + 𝑁) = 𝐵 & ⊢ (𝐵 + 𝑁) = 𝐶 ⇒ ⊢ (𝐵 · 𝐵) = ((𝐴 · 𝐶) + (𝑁 · 𝑁)) | ||
| Theorem | decaddcom 43161 | Commute ones place in addition. (Contributed by Steven Nguyen, 29-Jan-2023.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 ⇒ ⊢ (;𝐴𝐵 + 𝐶) = (;𝐴𝐶 + 𝐵) | ||
| Theorem | sqn5i 43162 | The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ (;𝐴5 · ;𝐴5) = ;;(𝐴 · (𝐴 + 1))25 | ||
| Theorem | sqn5ii 43163 | The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ (𝐴 + 1) = 𝐵 & ⊢ (𝐴 · 𝐵) = 𝐶 ⇒ ⊢ (;𝐴5 · ;𝐴5) = ;;𝐶25 | ||
| Theorem | decpmulnc 43164 | Partial products algorithm for two digit multiplication, no carry. Compare muladdi 11692. (Contributed by Steven Nguyen, 9-Dec-2022.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 & ⊢ 𝐷 ∈ ℕ0 & ⊢ (𝐴 · 𝐶) = 𝐸 & ⊢ ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹 & ⊢ (𝐵 · 𝐷) = 𝐺 ⇒ ⊢ (;𝐴𝐵 · ;𝐶𝐷) = ;;𝐸𝐹𝐺 | ||
| Theorem | decpmul 43165 | Partial products algorithm for two digit multiplication. (Contributed by Steven Nguyen, 10-Dec-2022.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 & ⊢ 𝐷 ∈ ℕ0 & ⊢ (𝐴 · 𝐶) = 𝐸 & ⊢ ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹 & ⊢ (𝐵 · 𝐷) = ;𝐺𝐻 & ⊢ (;𝐸𝐺 + 𝐹) = 𝐼 & ⊢ 𝐺 ∈ ℕ0 & ⊢ 𝐻 ∈ ℕ0 ⇒ ⊢ (;𝐴𝐵 · ;𝐶𝐷) = ;𝐼𝐻 | ||
| Theorem | sqdeccom12 43166 | The square of a number in terms of its digits switched. (Contributed by Steven Nguyen, 3-Jan-2023.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 ⇒ ⊢ ((;𝐴𝐵 · ;𝐴𝐵) − (;𝐵𝐴 · ;𝐵𝐴)) = (;99 · ((𝐴 · 𝐴) − (𝐵 · 𝐵))) | ||
| Theorem | sq3deccom12 43167 | Variant of sqdeccom12 43166 with a three digit square. (Contributed by Steven Nguyen, 3-Jan-2023.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 & ⊢ (𝐴 + 𝐶) = 𝐷 ⇒ ⊢ ((;;𝐴𝐵𝐶 · ;;𝐴𝐵𝐶) − (;𝐷𝐵 · ;𝐷𝐵)) = (;99 · ((;𝐴𝐵 · ;𝐴𝐵) − (𝐶 · 𝐶))) | ||
| Theorem | 4t5e20 43168 | 4 times 5 equals 20. (Contributed by SN, 30-Mar-2025.) |
| ⊢ (4 · 5) = ;20 | ||
| Theorem | 3rdpwhole 43169 | A third of a number plus the number is four thirds of the number. (Contributed by SN, 19-Nov-2025.) |
| ⊢ (𝐴 ∈ ℂ → ((𝐴 / 3) + 𝐴) = (4 · (𝐴 / 3))) | ||
| Theorem | sq4 43170 | The square of 4 is 16. (Contributed by SN, 26-Aug-2025.) |
| ⊢ (4↑2) = ;16 | ||
| Theorem | sq5 43171 | The square of 5 is 25. (Contributed by SN, 26-Aug-2025.) |
| ⊢ (5↑2) = ;25 | ||
| Theorem | sq6 43172 | The square of 6 is 36. (Contributed by SN, 26-Aug-2025.) |
| ⊢ (6↑2) = ;36 | ||
| Theorem | sq7 43173 | The square of 7 is 49. (Contributed by SN, 26-Aug-2025.) |
| ⊢ (7↑2) = ;49 | ||
| Theorem | sq8 43174 | The square of 8 is 64. (Contributed by SN, 26-Aug-2025.) |
| ⊢ (8↑2) = ;64 | ||
| Theorem | sq9 43175 | The square of 9 is 81. (Contributed by SN, 30-Mar-2025.) |
| ⊢ (9↑2) = ;81 | ||
| Theorem | rpsscn 43176 | The positive reals are a subset of the complex numbers. (Contributed by SN, 1-Oct-2025.) |
| ⊢ ℝ+ ⊆ ℂ | ||
| Theorem | 4rp 43177 | 4 is a positive real. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 4 ∈ ℝ+ | ||
| Theorem | 6rp 43178 | 6 is a positive real. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 6 ∈ ℝ+ | ||
| Theorem | 7rp 43179 | 7 is a positive real. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 7 ∈ ℝ+ | ||
| Theorem | 8rp 43180 | 8 is a positive real. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 8 ∈ ℝ+ | ||
| Theorem | 9rp 43181 | 9 is a positive real. (Contributed by SN, 26-Aug-2025.) |
| ⊢ 9 ∈ ℝ+ | ||
| Theorem | 235t711 43182 |
Calculate a product by long multiplication as a base comparison with other
multiplication algorithms.
Conveniently, 711 has two ones which greatly simplifies calculations like 235 · 1. There isn't a higher level mulcomli 11245 saving the lower level uses of mulcomli 11245 within 235 · 7 since mulcom2 doesn't exist, but if commuted versions of theorems like 7t2e14 12853 are added then this proof would benefit more than ex-decpmul 43183. For practicality, this proof doesn't have "e167085" at the end of its name like 2p2e4 12402 or 8t7e56 12864. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.) |
| ⊢ (;;235 · ;;711) = ;;;;;167085 | ||
| Theorem | ex-decpmul 43183 | Example usage of decpmul 43165. This proof is significantly longer than 235t711 43182. There is more unnecessary carrying compared to 235t711 43182. Although saving 5 visual steps, using mulcomli 11245 early on increases the compressed proof length. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.) (Proof modification is discouraged.) |
| ⊢ (;;235 · ;;711) = ;;;;;167085 | ||
| Theorem | eluzp1 43184 | Membership in a successor upper set of integers. (Contributed by SN, 5-Jul-2025.) |
| ⊢ (𝑀 ∈ ℤ → (𝑁 ∈ (ℤ≥‘(𝑀 + 1)) ↔ (𝑁 ∈ ℤ ∧ 𝑀 < 𝑁))) | ||
| Theorem | sn-eluzp1l 43185 | Shorter proof of eluzp1l 12917. (Contributed by NM, 12-Sep-2005.) (Revised by SN, 5-Jul-2025.) |
| ⊢ ((𝑀 ∈ ℤ ∧ 𝑁 ∈ (ℤ≥‘(𝑀 + 1))) → 𝑀 < 𝑁) | ||
| Theorem | fz1sumconst 43186* | The sum of 𝑁 constant terms (𝑘 is not free in 𝐶). (Contributed by SN, 21-Mar-2025.) |
| ⊢ (𝜑 → 𝑁 ∈ ℕ0) & ⊢ (𝜑 → 𝐶 ∈ ℂ) ⇒ ⊢ (𝜑 → Σ𝑘 ∈ (1...𝑁)𝐶 = (𝑁 · 𝐶)) | ||
| Theorem | fz1sump1 43187* | Add one more term to a sum. Special case of fsump1 15844 generalized to 𝑁 ∈ ℕ0. (Contributed by SN, 22-Mar-2025.) |
| ⊢ (𝜑 → 𝑁 ∈ ℕ0) & ⊢ ((𝜑 ∧ 𝑘 ∈ (1...(𝑁 + 1))) → 𝐴 ∈ ℂ) & ⊢ (𝑘 = (𝑁 + 1) → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → Σ𝑘 ∈ (1...(𝑁 + 1))𝐴 = (Σ𝑘 ∈ (1...𝑁)𝐴 + 𝐵)) | ||
| Theorem | oddnumth 43188* | The Odd Number Theorem. The sum of the first 𝑁 odd numbers is 𝑁↑2. A corollary of arisum 15951. (Contributed by SN, 21-Mar-2025.) |
| ⊢ (𝑁 ∈ ℕ0 → Σ𝑘 ∈ (1...𝑁)((2 · 𝑘) − 1) = (𝑁↑2)) | ||
| Theorem | nicomachus 43189* | Nicomachus's Theorem. The sum of the odd numbers from 𝑁↑2 − 𝑁 + 1 to 𝑁↑2 + 𝑁 − 1 is 𝑁↑3. Proof 2 from https://proofwiki.org/wiki/Nicomachus%27s_Theorem. (Contributed by SN, 21-Mar-2025.) |
| ⊢ (𝑁 ∈ ℕ0 → Σ𝑘 ∈ (1...𝑁)(((𝑁↑2) − 𝑁) + ((2 · 𝑘) − 1)) = (𝑁↑3)) | ||
| Theorem | sumcubes 43190* | The sum of the first 𝑁 perfect cubes is the sum of the first 𝑁 nonnegative integers, squared. This is the Proof by Nicomachus from https://proofwiki.org/wiki/Sum_of_Sequence_of_Cubes using induction and index shifting to collect all the odd numbers. (Contributed by SN, 22-Mar-2025.) |
| ⊢ (𝑁 ∈ ℕ0 → Σ𝑘 ∈ (1...𝑁)(𝑘↑3) = (Σ𝑘 ∈ (1...𝑁)𝑘↑2)) | ||
| Theorem | ine1 43191 | i is not 1. (Contributed by SN, 25-Apr-2025.) |
| ⊢ i ≠ 1 | ||
| Theorem | 0tie0 43192 | 0 times i equals 0. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (0 · i) = 0 | ||
| Theorem | it1ei 43193 | i times 1 equals i. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (i · 1) = i | ||
| Theorem | 1tiei 43194 | 1 times i equals i. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (1 · i) = i | ||
| Theorem | itrere 43195 | i times a real is real iff the real is zero. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (𝑅 ∈ ℝ → ((i · 𝑅) ∈ ℝ ↔ 𝑅 = 0)) | ||
| Theorem | retire 43196 | A real times i is real iff the real is zero. (Contributed by SN, 25-Apr-2025.) |
| ⊢ (𝑅 ∈ ℝ → ((𝑅 · i) ∈ ℝ ↔ 𝑅 = 0)) | ||
| Theorem | iocioodisjd 43197 | Adjacent intervals where the lower interval is right-closed and the upper interval is open are disjoint. (Contributed by SN, 1-Oct-2025.) |
| ⊢ (𝜑 → 𝐴 ∈ ℝ*) & ⊢ (𝜑 → 𝐵 ∈ ℝ*) & ⊢ (𝜑 → 𝐶 ∈ ℝ*) ⇒ ⊢ (𝜑 → ((𝐴(,]𝐵) ∩ (𝐵(,)𝐶)) = ∅) | ||
| Theorem | rpabsid 43198 | A positive real is its own absolute value. (Contributed by SN, 1-Oct-2025.) |
| ⊢ (𝑅 ∈ ℝ+ → (abs‘𝑅) = 𝑅) | ||
| Theorem | oexpreposd 43199 | Lemma for dffltz 43482. For a more standard version, see expgt0b 33289. TODO-SN?: This can be used to show exp11d 43203 holds for all integers when the exponent is odd. (Contributed by SN, 4-Mar-2023.) |
| ⊢ (𝜑 → 𝑁 ∈ ℝ) & ⊢ (𝜑 → 𝑀 ∈ ℕ) & ⊢ (𝜑 → ¬ (𝑀 / 2) ∈ ℕ) ⇒ ⊢ (𝜑 → (0 < 𝑁 ↔ 0 < (𝑁↑𝑀))) | ||
| Theorem | explt1d 43200 | A nonnegative real number less than one raised to a positive integer is less than one. (Contributed by SN, 3-Jul-2025.) |
| ⊢ (𝜑 → 𝐴 ∈ ℝ) & ⊢ (𝜑 → 𝑁 ∈ ℕ) & ⊢ (𝜑 → 0 ≤ 𝐴) & ⊢ (𝜑 → 𝐴 < 1) ⇒ ⊢ (𝜑 → (𝐴↑𝑁) < 1) | ||
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