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Theorem preq12nebg 4826
Description: Equality relationship for two proper unordered pairs. (Contributed by AV, 12-Jun-2022.)
Assertion
Ref Expression
preq12nebg ((𝐴𝑉𝐵𝑊𝐴𝐵) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))

Proof of Theorem preq12nebg
StepHypRef Expression
1 3simpa 1166 . . . . . 6 ((𝐴𝑉𝐵𝑊𝐴𝐵) → (𝐴𝑉𝐵𝑊))
21anim1i 627 . . . . 5 (((𝐴𝑉𝐵𝑊𝐴𝐵) ∧ (𝐶 ∈ V ∧ 𝐷 ∈ V)) → ((𝐴𝑉𝐵𝑊) ∧ (𝐶 ∈ V ∧ 𝐷 ∈ V)))
32ancoms 464 . . . 4 (((𝐶 ∈ V ∧ 𝐷 ∈ V) ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ((𝐴𝑉𝐵𝑊) ∧ (𝐶 ∈ V ∧ 𝐷 ∈ V)))
4 preq12bg 4816 . . . 4 (((𝐴𝑉𝐵𝑊) ∧ (𝐶 ∈ V ∧ 𝐷 ∈ V)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
53, 4syl 18 . . 3 (((𝐶 ∈ V ∧ 𝐷 ∈ V) ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
65ex 418 . 2 ((𝐶 ∈ V ∧ 𝐷 ∈ V) → ((𝐴𝑉𝐵𝑊𝐴𝐵) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶)))))
7 ianor 997 . . 3 (¬ (𝐶 ∈ V ∧ 𝐷 ∈ V) ↔ (¬ 𝐶 ∈ V ∨ ¬ 𝐷 ∈ V))
8 prneprprc 4824 . . . . . . . 8 (((𝐴𝑉𝐵𝑊𝐴𝐵) ∧ ¬ 𝐶 ∈ V) → {𝐴, 𝐵} ≠ {𝐶, 𝐷})
98ancoms 464 . . . . . . 7 ((¬ 𝐶 ∈ V ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → {𝐴, 𝐵} ≠ {𝐶, 𝐷})
10 eqneqall 2968 . . . . . . 7 ({𝐴, 𝐵} = {𝐶, 𝐷} → ({𝐴, 𝐵} ≠ {𝐶, 𝐷} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
119, 10syl5com 32 . . . . . 6 ((¬ 𝐶 ∈ V ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ({𝐴, 𝐵} = {𝐶, 𝐷} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
12 prneprprc 4824 . . . . . . . 8 (((𝐴𝑉𝐵𝑊𝐴𝐵) ∧ ¬ 𝐷 ∈ V) → {𝐴, 𝐵} ≠ {𝐷, 𝐶})
1312ancoms 464 . . . . . . 7 ((¬ 𝐷 ∈ V ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → {𝐴, 𝐵} ≠ {𝐷, 𝐶})
14 prcom 4696 . . . . . . . . 9 {𝐶, 𝐷} = {𝐷, 𝐶}
1514eqeq2i 2775 . . . . . . . 8 ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ {𝐴, 𝐵} = {𝐷, 𝐶})
16 eqneqall 2968 . . . . . . . 8 ({𝐴, 𝐵} = {𝐷, 𝐶} → ({𝐴, 𝐵} ≠ {𝐷, 𝐶} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
1715, 16sylbi 220 . . . . . . 7 ({𝐴, 𝐵} = {𝐶, 𝐷} → ({𝐴, 𝐵} ≠ {𝐷, 𝐶} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
1813, 17syl5com 32 . . . . . 6 ((¬ 𝐷 ∈ V ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ({𝐴, 𝐵} = {𝐶, 𝐷} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
1911, 18jaoian 971 . . . . 5 (((¬ 𝐶 ∈ V ∨ ¬ 𝐷 ∈ V) ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ({𝐴, 𝐵} = {𝐶, 𝐷} → ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
20 preq12 4699 . . . . . 6 ((𝐴 = 𝐶𝐵 = 𝐷) → {𝐴, 𝐵} = {𝐶, 𝐷})
21 preq12 4699 . . . . . . 7 ((𝐴 = 𝐷𝐵 = 𝐶) → {𝐴, 𝐵} = {𝐷, 𝐶})
22 prcom 4696 . . . . . . 7 {𝐷, 𝐶} = {𝐶, 𝐷}
2321, 22eqtrdi 2813 . . . . . 6 ((𝐴 = 𝐷𝐵 = 𝐶) → {𝐴, 𝐵} = {𝐶, 𝐷})
2420, 23jaoi 871 . . . . 5 (((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶)) → {𝐴, 𝐵} = {𝐶, 𝐷})
2519, 24impbid1 228 . . . 4 (((¬ 𝐶 ∈ V ∨ ¬ 𝐷 ∈ V) ∧ (𝐴𝑉𝐵𝑊𝐴𝐵)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
2625ex 418 . . 3 ((¬ 𝐶 ∈ V ∨ ¬ 𝐷 ∈ V) → ((𝐴𝑉𝐵𝑊𝐴𝐵) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶)))))
277, 26sylbi 220 . 2 (¬ (𝐶 ∈ V ∧ 𝐷 ∈ V) → ((𝐴𝑉𝐵𝑊𝐴𝐵) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶)))))
286, 27pm2.61i 184 1 ((𝐴𝑉𝐵𝑊𝐴𝐵) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶𝐵 = 𝐷) ∨ (𝐴 = 𝐷𝐵 = 𝐶))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3  wi 4  wb 209  wa 401  wo 861  w3a 1103   = wceq 1570  wcel 2145  wne 2957  Vcvv 3453  {cpr 4589
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-v 3455  df-dif 3905  df-un 3907  df-nul 4283  df-sn 4588  df-pr 4590
This theorem is used by:  prel12g  4827  opthhausdorff  5498  preleqg  9597  pr2cv  44375
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