Theorem preq12bg 4816

Description: Closed form of preq12b 4813. (Contributed by Scott Fenton, 28-Mar-2014.)

Assertion

Ref	Expression
preq12bg	⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ (𝐶 ∈ 𝑋 ∧ 𝐷 ∈ 𝑌)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))

Proof of Theorem preq12bg

Dummy variables 𝑥 𝑦 𝑧 𝑤 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		preq1 4697	. . . . . . 7 ⊢ (𝑥 = 𝐴 → {𝑥, 𝑦} = {𝐴, 𝑦})
2	1	eqeq1d 2764	. . . . . 6 ⊢ (𝑥 = 𝐴 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ {𝐴, 𝑦} = {𝑧, 𝐷}))
3		eqeq1 2766	. . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 = 𝑧 ↔ 𝐴 = 𝑧))
4	3	anbi1d 643	. . . . . . 7 ⊢ (𝑥 = 𝐴 → ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ↔ (𝐴 = 𝑧 ∧ 𝑦 = 𝐷)))
5		eqeq1 2766	. . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 = 𝐷 ↔ 𝐴 = 𝐷))
6	5	anbi1d 643	. . . . . . 7 ⊢ (𝑥 = 𝐴 → ((𝑥 = 𝐷 ∧ 𝑦 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))
7	4, 6	orbi12d 932	. . . . . 6 ⊢ (𝑥 = 𝐴 → (((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)) ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))))
8	2, 7	bibi12d 348	. . . . 5 ⊢ (𝑥 = 𝐴 → (({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))) ↔ ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))))
9	8	imbi2d 343	. . . 4 ⊢ (𝑥 = 𝐴 → ((𝐷 ∈ 𝑌 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))))))
10		preq2 4698	. . . . . . 7 ⊢ (𝑦 = 𝐵 → {𝐴, 𝑦} = {𝐴, 𝐵})
11	10	eqeq1d 2764	. . . . . 6 ⊢ (𝑦 = 𝐵 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ {𝐴, 𝐵} = {𝑧, 𝐷}))
12		eqeq1 2766	. . . . . . . 8 ⊢ (𝑦 = 𝐵 → (𝑦 = 𝐷 ↔ 𝐵 = 𝐷))
13	12	anbi2d 642	. . . . . . 7 ⊢ (𝑦 = 𝐵 → ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ↔ (𝐴 = 𝑧 ∧ 𝐵 = 𝐷)))
14		eqeq1 2766	. . . . . . . 8 ⊢ (𝑦 = 𝐵 → (𝑦 = 𝑧 ↔ 𝐵 = 𝑧))
15	14	anbi2d 642	. . . . . . 7 ⊢ (𝑦 = 𝐵 → ((𝐴 = 𝐷 ∧ 𝑦 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))
16	13, 15	orbi12d 932	. . . . . 6 ⊢ (𝑦 = 𝐵 → (((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)) ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))))
17	11, 16	bibi12d 348	. . . . 5 ⊢ (𝑦 = 𝐵 → (({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))) ↔ ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))))
18	17	imbi2d 343	. . . 4 ⊢ (𝑦 = 𝐵 → ((𝐷 ∈ 𝑌 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))))))
19		preq1 4697	. . . . . . 7 ⊢ (𝑧 = 𝐶 → {𝑧, 𝐷} = {𝐶, 𝐷})
20	19	eqeq2d 2773	. . . . . 6 ⊢ (𝑧 = 𝐶 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ {𝐴, 𝐵} = {𝐶, 𝐷}))
21		eqeq2 2774	. . . . . . . 8 ⊢ (𝑧 = 𝐶 → (𝐴 = 𝑧 ↔ 𝐴 = 𝐶))
22	21	anbi1d 643	. . . . . . 7 ⊢ (𝑧 = 𝐶 → ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ↔ (𝐴 = 𝐶 ∧ 𝐵 = 𝐷)))
23		eqeq2 2774	. . . . . . . 8 ⊢ (𝑧 = 𝐶 → (𝐵 = 𝑧 ↔ 𝐵 = 𝐶))
24	23	anbi2d 642	. . . . . . 7 ⊢ (𝑧 = 𝐶 → ((𝐴 = 𝐷 ∧ 𝐵 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))
25	22, 24	orbi12d 932	. . . . . 6 ⊢ (𝑧 = 𝐶 → (((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)) ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))
26	20, 25	bibi12d 348	. . . . 5 ⊢ (𝑧 = 𝐶 → (({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))) ↔ ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
27	26	imbi2d 343	. . . 4 ⊢ (𝑧 = 𝐶 → ((𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))))
28		preq2 4698	. . . . . 6 ⊢ (𝑤 = 𝐷 → {𝑧, 𝑤} = {𝑧, 𝐷})
29	28	eqeq2d 2773	. . . . 5 ⊢ (𝑤 = 𝐷 → ({𝑥, 𝑦} = {𝑧, 𝑤} ↔ {𝑥, 𝑦} = {𝑧, 𝐷}))
30		eqeq2 2774	. . . . . . 7 ⊢ (𝑤 = 𝐷 → (𝑦 = 𝑤 ↔ 𝑦 = 𝐷))
31	30	anbi2d 642	. . . . . 6 ⊢ (𝑤 = 𝐷 → ((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ↔ (𝑥 = 𝑧 ∧ 𝑦 = 𝐷)))
32		eqeq2 2774	. . . . . . 7 ⊢ (𝑤 = 𝐷 → (𝑥 = 𝑤 ↔ 𝑥 = 𝐷))
33	32	anbi1d 643	. . . . . 6 ⊢ (𝑤 = 𝐷 → ((𝑥 = 𝑤 ∧ 𝑦 = 𝑧) ↔ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)))
34	31, 33	orbi12d 932	. . . . 5 ⊢ (𝑤 = 𝐷 → (((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ∨ (𝑥 = 𝑤 ∧ 𝑦 = 𝑧)) ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))))
35		vex 3457	. . . . . 6 ⊢ 𝑥 ∈ V
36		vex 3457	. . . . . 6 ⊢ 𝑦 ∈ V
37		vex 3457	. . . . . 6 ⊢ 𝑧 ∈ V
38		vex 3457	. . . . . 6 ⊢ 𝑤 ∈ V
39	35, 36, 37, 38	preq12b 4813	. . . . 5 ⊢ ({𝑥, 𝑦} = {𝑧, 𝑤} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ∨ (𝑥 = 𝑤 ∧ 𝑦 = 𝑧)))
40	29, 34, 39	vtoclbg 3522	. . . 4 ⊢ (𝐷 ∈ 𝑌 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))))
41	9, 18, 27, 40	vtocl3g 3537	. . 3 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
42	41	3expa 1136	. 2 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ 𝐶 ∈ 𝑋) → (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
43	42	impr 460	1 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ (𝐶 ∈ 𝑋 ∧ 𝐷 ∈ 𝑌)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   ∨ wo 861   = wceq 1570   ∈ wcel 2145  {cpr 4589

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-v 3455  df-un 3907  df-sn 4588  df-pr 4590

This theorem is used by:  prneimg  4817  prneimg2  4818  pr1eqbg  4820  preqsnd  4822  preq12nebg  4826  opthprneg  4828  preleqALT  9599  pythagtriplem2  16913  pythagtrip  16930  upgrpredgv  29582  uhgr2edg  29654  usgredg2v  29673  2pthon3v  30397  opprb  47906  or2expropbi  47909  ich2exprop  48358  prsprel  48374  paireqne  48398  poprelb  48411  gpgvtxedg0  48966  gpgvtxedg1  48967