Theorem preq12bg 4811

Description: Closed form of preq12b 4808. (Contributed by Scott Fenton, 28-Mar-2014.)

Assertion

Ref	Expression
preq12bg	⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ (𝐶 ∈ 𝑋 ∧ 𝐷 ∈ 𝑌)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))

Proof of Theorem preq12bg

Dummy variables 𝑥 𝑦 𝑧 𝑤 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		preq1 4694	. . . . . . 7 ⊢ (𝑥 = 𝐴 → {𝑥, 𝑦} = {𝐴, 𝑦})
2	1	eqeq1d 2765	. . . . . 6 ⊢ (𝑥 = 𝐴 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ {𝐴, 𝑦} = {𝑧, 𝐷}))
3		eqeq1 2767	. . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 = 𝑧 ↔ 𝐴 = 𝑧))
4	3	anbi1d 643	. . . . . . 7 ⊢ (𝑥 = 𝐴 → ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ↔ (𝐴 = 𝑧 ∧ 𝑦 = 𝐷)))
5		eqeq1 2767	. . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 = 𝐷 ↔ 𝐴 = 𝐷))
6	5	anbi1d 643	. . . . . . 7 ⊢ (𝑥 = 𝐴 → ((𝑥 = 𝐷 ∧ 𝑦 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))
7	4, 6	orbi12d 932	. . . . . 6 ⊢ (𝑥 = 𝐴 → (((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)) ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))))
8	2, 7	bibi12d 348	. . . . 5 ⊢ (𝑥 = 𝐴 → (({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))) ↔ ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))))
9	8	imbi2d 343	. . . 4 ⊢ (𝑥 = 𝐴 → ((𝐷 ∈ 𝑌 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))))))
10		preq2 4695	. . . . . . 7 ⊢ (𝑦 = 𝐵 → {𝐴, 𝑦} = {𝐴, 𝐵})
11	10	eqeq1d 2765	. . . . . 6 ⊢ (𝑦 = 𝐵 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ {𝐴, 𝐵} = {𝑧, 𝐷}))
12		eqeq1 2767	. . . . . . . 8 ⊢ (𝑦 = 𝐵 → (𝑦 = 𝐷 ↔ 𝐵 = 𝐷))
13	12	anbi2d 642	. . . . . . 7 ⊢ (𝑦 = 𝐵 → ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ↔ (𝐴 = 𝑧 ∧ 𝐵 = 𝐷)))
14		eqeq1 2767	. . . . . . . 8 ⊢ (𝑦 = 𝐵 → (𝑦 = 𝑧 ↔ 𝐵 = 𝑧))
15	14	anbi2d 642	. . . . . . 7 ⊢ (𝑦 = 𝐵 → ((𝐴 = 𝐷 ∧ 𝑦 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))
16	13, 15	orbi12d 932	. . . . . 6 ⊢ (𝑦 = 𝐵 → (((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)) ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))))
17	11, 16	bibi12d 348	. . . . 5 ⊢ (𝑦 = 𝐵 → (({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧))) ↔ ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))))
18	17	imbi2d 343	. . . 4 ⊢ (𝑦 = 𝐵 → ((𝐷 ∈ 𝑌 → ({𝐴, 𝑦} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝑦 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))))))
19		preq1 4694	. . . . . . 7 ⊢ (𝑧 = 𝐶 → {𝑧, 𝐷} = {𝐶, 𝐷})
20	19	eqeq2d 2774	. . . . . 6 ⊢ (𝑧 = 𝐶 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ {𝐴, 𝐵} = {𝐶, 𝐷}))
21		eqeq2 2775	. . . . . . . 8 ⊢ (𝑧 = 𝐶 → (𝐴 = 𝑧 ↔ 𝐴 = 𝐶))
22	21	anbi1d 643	. . . . . . 7 ⊢ (𝑧 = 𝐶 → ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ↔ (𝐴 = 𝐶 ∧ 𝐵 = 𝐷)))
23		eqeq2 2775	. . . . . . . 8 ⊢ (𝑧 = 𝐶 → (𝐵 = 𝑧 ↔ 𝐵 = 𝐶))
24	23	anbi2d 642	. . . . . . 7 ⊢ (𝑧 = 𝐶 → ((𝐴 = 𝐷 ∧ 𝐵 = 𝑧) ↔ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))
25	22, 24	orbi12d 932	. . . . . 6 ⊢ (𝑧 = 𝐶 → (((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)) ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))
26	20, 25	bibi12d 348	. . . . 5 ⊢ (𝑧 = 𝐶 → (({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧))) ↔ ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
27	26	imbi2d 343	. . . 4 ⊢ (𝑧 = 𝐶 → ((𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝑧, 𝐷} ↔ ((𝐴 = 𝑧 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝑧)))) ↔ (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))))
28		preq2 4695	. . . . . 6 ⊢ (𝑤 = 𝐷 → {𝑧, 𝑤} = {𝑧, 𝐷})
29	28	eqeq2d 2774	. . . . 5 ⊢ (𝑤 = 𝐷 → ({𝑥, 𝑦} = {𝑧, 𝑤} ↔ {𝑥, 𝑦} = {𝑧, 𝐷}))
30		eqeq2 2775	. . . . . . 7 ⊢ (𝑤 = 𝐷 → (𝑦 = 𝑤 ↔ 𝑦 = 𝐷))
31	30	anbi2d 642	. . . . . 6 ⊢ (𝑤 = 𝐷 → ((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ↔ (𝑥 = 𝑧 ∧ 𝑦 = 𝐷)))
32		eqeq2 2775	. . . . . . 7 ⊢ (𝑤 = 𝐷 → (𝑥 = 𝑤 ↔ 𝑥 = 𝐷))
33	32	anbi1d 643	. . . . . 6 ⊢ (𝑤 = 𝐷 → ((𝑥 = 𝑤 ∧ 𝑦 = 𝑧) ↔ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧)))
34	31, 33	orbi12d 932	. . . . 5 ⊢ (𝑤 = 𝐷 → (((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ∨ (𝑥 = 𝑤 ∧ 𝑦 = 𝑧)) ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))))
35		vex 3458	. . . . . 6 ⊢ 𝑥 ∈ V
36		vex 3458	. . . . . 6 ⊢ 𝑦 ∈ V
37		vex 3458	. . . . . 6 ⊢ 𝑧 ∈ V
38		vex 3458	. . . . . 6 ⊢ 𝑤 ∈ V
39	35, 36, 37, 38	preq12b 4808	. . . . 5 ⊢ ({𝑥, 𝑦} = {𝑧, 𝑤} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝑤) ∨ (𝑥 = 𝑤 ∧ 𝑦 = 𝑧)))
40	29, 34, 39	vtoclbg 3523	. . . 4 ⊢ (𝐷 ∈ 𝑌 → ({𝑥, 𝑦} = {𝑧, 𝐷} ↔ ((𝑥 = 𝑧 ∧ 𝑦 = 𝐷) ∨ (𝑥 = 𝐷 ∧ 𝑦 = 𝑧))))
41	9, 18, 27, 40	vtocl3g 3538	. . 3 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
42	41	3expa 1136	. 2 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ 𝐶 ∈ 𝑋) → (𝐷 ∈ 𝑌 → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶)))))
43	42	impr 460	1 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) ∧ (𝐶 ∈ 𝑋 ∧ 𝐷 ∈ 𝑌)) → ({𝐴, 𝐵} = {𝐶, 𝐷} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐷) ∨ (𝐴 = 𝐷 ∧ 𝐵 = 𝐶))))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   ∨ wo 861   = wceq 1570   ∈ wcel 2147  {cpr 4590

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-v 3456  df-un 4154  df-sn 4589  df-pr 4591

This theorem is used by:  prneimg  4812  prneimg2  4813  pr1eqbg  4815  preqsnd  4817  preq12nebg  4821  opthprneg  4823  preleqALT  9642  pythagtriplem2  17021  pythagtrip  17038  upgrpredgv  29744  uhgr2edg  29816  usgredg2v  29835  2pthon3v  30559  opprb  48304  or2expropbi  48307  ich2exprop  48756  prsprel  48772  paireqne  48796  poprelb  48809  gpgvtxedg0  49364  gpgvtxedg1  49365