Theorem qseq2i 8765

Description: Equality theorem for quotient set, inference form. (Contributed by Peter Mazsa, 3-Jun-2021.)

Hypothesis

Ref	Expression
qseq2i.1	⊢ 𝐴 = 𝐵

Assertion

Ref	Expression
qseq2i	⊢ (𝐶 / 𝐴) = (𝐶 / 𝐵)

Proof of Theorem qseq2i

Step	Hyp	Ref	Expression
1		qseq2i.1	. 2 ⊢ 𝐴 = 𝐵
2		qseq2 8764	. 2 ⊢ (𝐴 = 𝐵 → (𝐶 / 𝐴) = (𝐶 / 𝐵))
3	1, 2	ax-mp 5	1 ⊢ (𝐶 / 𝐴) = (𝐶 / 𝐵)

This proof depends on syntax axioms:   = wceq 1570   / cqs 8702

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2738

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2745  df-cleq 2758  df-clel 2841  df-rex 3093  df-rab 3420  df-v 3460  df-dif 3911  df-un 3913  df-in 3915  df-ss 3925  df-nul 4290  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-br 5115  df-opab 5179  df-cnv 5674  df-dm 5676  df-rn 5677  df-res 5678  df-ima 5679  df-ec 8705  df-qs 8709

This theorem is used by: (None)