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| Mirrors > Home > ILE Home > Th. List > 3sstr4d | Unicode version | ||
| Description: Substitution of equality into both sides of a subclass relationship. (Contributed by NM, 30-Nov-1995.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
| Ref | Expression |
|---|---|
| 3sstr4d.1 |
|
| 3sstr4d.2 |
|
| 3sstr4d.3 |
|
| Ref | Expression |
|---|---|
| 3sstr4d |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 3sstr4d.1 |
. 2
| |
| 2 | 3sstr4d.2 |
. . 3
| |
| 3 | 3sstr4d.3 |
. . 3
| |
| 4 | 2, 3 | sseq12d 3279 |
. 2
|
| 5 | 1, 4 | mpbird 167 |
1
|
| Colors of variables: wff set class |
| This proof depends on syntax axioms:
|
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1500 ax-7 1501 ax-gen 1502 ax-ie1 1546 ax-ie2 1547 ax-8 1557 ax-11 1559 ax-4 1563 ax-17 1579 ax-i9 1583 ax-ial 1587 ax-i5r 1588 ax-ext 2220 |
| This proof depends on definitions: df-bi 117 df-nf 1514 df-sb 1816 df-clab 2225 df-cleq 2231 df-clel 2234 df-in 3226 df-ss 3233 |
| This theorem is used by: ressuppss 6498 suppfnss 6501 suppssfvg 6507 rdgss 6659 sucinc2 6724 oawordi 6747 nnnninf 7472 fzoss1 10596 fzoss2 10597 swrd0g 11453 lspss 14844 aspss 15127 clsss 15361 ntrss 15362 sslm 15490 txss12 15509 metss2lem 15740 xmettxlem 15752 xmettx 15753 plyss 15981 ifpsnprss 16806 nnsf 17271 nninfself 17279 |
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