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Theorem eldmrexrn 5823
Description: For any element in the domain of a function there is an element in the range of the function which is the function value for the element of the domain. (Contributed by Alexander van der Vekens, 8-Dec-2017.)
Assertion
Ref Expression
eldmrexrn  |-  ( Fun 
F  ->  ( Y  e.  dom  F  ->  E. x  e.  ran  F  x  =  ( F `  Y
) ) )
Distinct variable groups:    x, F    x, Y

Proof of Theorem eldmrexrn
StepHypRef Expression
1 fvelrn 5813 . . 3  |-  ( ( Fun  F  /\  Y  e.  dom  F )  -> 
( F `  Y
)  e.  ran  F
)
2 eqid 2234 . . 3  |-  ( F `
 Y )  =  ( F `  Y
)
3 eqeq1 2241 . . . 4  |-  ( x  =  ( F `  Y )  ->  (
x  =  ( F `
 Y )  <->  ( F `  Y )  =  ( F `  Y ) ) )
43rspcev 2923 . . 3  |-  ( ( ( F `  Y
)  e.  ran  F  /\  ( F `  Y
)  =  ( F `
 Y ) )  ->  E. x  e.  ran  F  x  =  ( F `
 Y ) )
51, 2, 4sylancl 413 . 2  |-  ( ( Fun  F  /\  Y  e.  dom  F )  ->  E. x  e.  ran  F  x  =  ( F `
 Y ) )
65ex 115 1  |-  ( Fun 
F  ->  ( Y  e.  dom  F  ->  E. x  e.  ran  F  x  =  ( F `  Y
) ) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 104    = wceq 1398    e. wcel 2205   E.wrex 2523   dom cdm 4754   ran crn 4755   Fun wfun 5351   ` cfv 5357
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-14 2208  ax-ext 2216  ax-sep 4233  ax-pow 4292  ax-pr 4327
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-nf 1510  df-sb 1812  df-eu 2085  df-mo 2086  df-clab 2221  df-cleq 2227  df-clel 2230  df-nfc 2375  df-ral 2527  df-rex 2528  df-v 2817  df-sbc 3046  df-un 3218  df-in 3220  df-ss 3227  df-pw 3676  df-sn 3700  df-pr 3701  df-op 3703  df-uni 3920  df-br 4115  df-opab 4177  df-id 4419  df-xp 4760  df-rel 4761  df-cnv 4762  df-co 4763  df-dm 4764  df-rn 4765  df-iota 5317  df-fun 5359  df-fn 5360  df-fv 5365
This theorem is referenced by: (None)
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