Theorem elsucg 4507

Description: Membership in a successor. Exercise 5 of [TakeutiZaring] p. 17. (Contributed by NM, 15-Sep-1995.)

Assertion

Ref	Expression
elsucg	|- ( A e. V -> ( A e. suc B <-> ( A e. B \/ A = B ) ) )

Proof of Theorem elsucg

Step	Hyp	Ref	Expression
1		df-suc 4474	. . . 4 |- suc B = ( B u. { B } )
2	1	eleq2i 2298	. . 3 |- ( A e. suc B <-> A e. ( B u. { B } ) )
3		elun 3350	. . 3 |- ( A e. ( B u. { B } ) <-> ( A e. B \/ A e. { B } ) )
4	2, 3	bitri 184	. 2 |- ( A e. suc B <-> ( A e. B \/ A e. { B } ) )
5		elsng 3688	. . 3 |- ( A e. V -> ( A e. { B } <-> A = B ) )
6	5	orbi2d 798	. 2 |- ( A e. V -> ( ( A e. B \/ A e. { B } ) <-> ( A e. B \/ A = B ) ) )
7	4, 6	bitrid 192	1 |- ( A e. V -> ( A e. suc B <-> ( A e. B \/ A = B ) ) )

Syntax hints:   -> wi 4   <-> wb 105   \/ wo 716   = wceq 1398   e. wcel 2202   u. cun 3199   {csn 3673   suc csuc 4468

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2364  df-v 2805  df-un 3205  df-sn 3679  df-suc 4474

This theorem is referenced by:  elsuc  4509  elelsuc  4512  sucidg  4519  onsucelsucr  4612  onsucsssucexmid  4631  suc11g  4661  nnsssuc  6713  nlt1pig  7621  bj-peano4  16671