Theorem breq 3869

Description: Equality theorem for binary relations. (Contributed by NM, 4-Jun-1995.)

Assertion

Ref	Expression
breq	⊢ (𝑅 = 𝑆 → (𝐴𝑅𝐵 ↔ 𝐴𝑆𝐵))

Proof of Theorem breq

Step	Hyp	Ref	Expression
1		eleq2 2158	. 2 ⊢ (𝑅 = 𝑆 → (⟨𝐴, 𝐵⟩ ∈ 𝑅 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑆))
2		df-br 3868	. 2 ⊢ (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑅)
3		df-br 3868	. 2 ⊢ (𝐴𝑆𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑆)
4	1, 2, 3	3bitr4g 222	1 ⊢ (𝑅 = 𝑆 → (𝐴𝑅𝐵 ↔ 𝐴𝑆𝐵))

Syntax hints:   → wi 4   ↔ wb 104   = wceq 1296   ∈ wcel 1445  ⟨cop 3469   class class class wbr 3867

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1388  ax-gen 1390  ax-ie1 1434  ax-ie2 1435  ax-4 1452  ax-17 1471  ax-ial 1479  ax-ext 2077

This theorem depends on definitions:  df-bi 116  df-cleq 2088  df-clel 2091  df-br 3868

This theorem is referenced by:  breqi  3873  breqd  3878  poeq1  4150  soeq1  4166  frforeq1  4194  weeq1  4207  fveq1  5339  foeqcnvco  5607  f1eqcocnv  5608  isoeq2  5619  isoeq3  5620  ofreq  5897  supeq3  6765  shftfvalg  10383  shftfval  10386