Theorem breq 4111

Description: Equality theorem for binary relations. (Contributed by NM, 4-Jun-1995.)

Assertion

Ref	Expression
breq	⊢ (𝑅 = 𝑆 → (𝐴𝑅𝐵 ↔ 𝐴𝑆𝐵))

Proof of Theorem breq

Step	Hyp	Ref	Expression
1		eleq2 2296	. 2 ⊢ (𝑅 = 𝑆 → (⟨𝐴, 𝐵⟩ ∈ 𝑅 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑆))
2		df-br 4110	. 2 ⊢ (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑅)
3		df-br 4110	. 2 ⊢ (𝐴𝑆𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑆)
4	1, 2, 3	3bitr4g 223	1 ⊢ (𝑅 = 𝑆 → (𝐴𝑅𝐵 ↔ 𝐴𝑆𝐵))

Syntax hints:   → wi 4   ↔ wb 105   = wceq 1398   ∈ wcel 2203  ⟨cop 3692   class class class wbr 4109

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-4 1559  ax-17 1575  ax-ial 1583  ax-ext 2214

This theorem depends on definitions:  df-bi 117  df-cleq 2225  df-clel 2228  df-br 4110

This theorem is referenced by:  breqi  4115  breqd  4120  poeq1  4420  soeq1  4436  frforeq1  4464  weeq1  4477  fveq1  5669  foeqcnvco  5963  f1eqcocnv  5964  isoeq2  5975  isoeq3  5976  ofreq  6270  supeq3  7281  tapeq1  7566  shftfvalg  11503  shftfval  11506  pw1nct  16777