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Theorem 2optocl 5747
Description: Implicit substitution of classes for ordered pairs. (Contributed by NM, 12-Mar-1995.)
Hypotheses
Ref Expression
2optocl.1 𝑅 = (𝐶 × 𝐷)
2optocl.2 (⟨𝑥, 𝑦⟩ = 𝐴 → (𝜑 ↔ 𝜓))
2optocl.3 (⟨𝑧, 𝑤⟩ = 𝐵 → (𝜓 ↔ 𝜒))
2optocl.4 (((𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) ∧ (𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷)) → 𝜑)
Assertion
Ref Expression
2optocl ((𝐴 ∈ 𝑅 ∧ 𝐵 ∈ 𝑅) → 𝜒)
Distinct variable groups:   𝑥,𝑦,𝑧,𝑤,𝐴   𝑧,𝐵,𝑤   𝑥,𝐶,𝑦,𝑧,𝑤   𝑥,𝐷,𝑦,𝑧,𝑤   𝜓,𝑥,𝑦   𝜒,𝑧,𝑤   𝑧,𝑅,𝑤
Allowed substitution hints:   𝜑(𝑥, 𝑦, 𝑧, 𝑤)   𝜓(𝑧, 𝑤)   𝜒(𝑥, 𝑦)   𝐵(𝑥, 𝑦)   𝑅(𝑥, 𝑦)

Proof of Theorem 2optocl
StepHypRef Expression
1 2optocl.1 . . 3 𝑅 = (𝐶 × 𝐷)
2 2optocl.3 . . . 4 (⟨𝑧, 𝑤⟩ = 𝐵 → (𝜓 ↔ 𝜒))
32imbi2d 343 . . 3 (⟨𝑧, 𝑤⟩ = 𝐵 → ((𝐴 ∈ 𝑅 → 𝜓) ↔ (𝐴 ∈ 𝑅 → 𝜒)))
4 2optocl.2 . . . . . 6 (⟨𝑥, 𝑦⟩ = 𝐴 → (𝜑 ↔ 𝜓))
54imbi2d 343 . . . . 5 (⟨𝑥, 𝑦⟩ = 𝐴 → (((𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷) → 𝜑) ↔ ((𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷) → 𝜓)))
6 2optocl.4 . . . . . 6 (((𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) ∧ (𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷)) → 𝜑)
76ex 418 . . . . 5 ((𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) → ((𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷) → 𝜑))
81, 5, 7optocl 5745 . . . 4 (𝐴 ∈ 𝑅 → ((𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷) → 𝜓))
98com12 33 . . 3 ((𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷) → (𝐴 ∈ 𝑅 → 𝜓))
101, 3, 9optocl 5745 . 2 (𝐵 ∈ 𝑅 → (𝐴 ∈ 𝑅 → 𝜒))
1110impcom 413 1 ((𝐴 ∈ 𝑅 ∧ 𝐵 ∈ 𝑅) → 𝜒)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2145  ⟨cop 4590   × cxp 5649
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-opab 5168  df-xp 5657
This theorem is used by:  3optocl  5748  ecopovsym  8833  axaddf  11223  axmulf  11224
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