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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | weinxp 5701 | Intersection of well-ordering with Cartesian product of its field. (Contributed by NM, 9-Mar-1997.) (Revised by Mario Carneiro, 10-Jul-2014.) |
| ⊢ (𝑅 We 𝐴 ↔ (𝑅 ∩ (𝐴 × 𝐴)) We 𝐴) | ||
| Theorem | posn 5702 | Partial ordering of a singleton. (Contributed by NM, 27-Apr-2009.) (Revised by Mario Carneiro, 23-Apr-2015.) |
| ⊢ (Rel 𝑅 → (𝑅 Po {𝐴} ↔ ¬ 𝐴𝑅𝐴)) | ||
| Theorem | sosn 5703 | Strict ordering on a singleton. (Contributed by Mario Carneiro, 28-Dec-2014.) |
| ⊢ (Rel 𝑅 → (𝑅 Or {𝐴} ↔ ¬ 𝐴𝑅𝐴)) | ||
| Theorem | frsn 5704 | Founded relation on a singleton. (Contributed by Mario Carneiro, 28-Dec-2014.) (Revised by Mario Carneiro, 23-Apr-2015.) |
| ⊢ (Rel 𝑅 → (𝑅 Fr {𝐴} ↔ ¬ 𝐴𝑅𝐴)) | ||
| Theorem | wesn 5705 | Well-ordering of a singleton. (Contributed by Mario Carneiro, 28-Dec-2014.) |
| ⊢ (Rel 𝑅 → (𝑅 We {𝐴} ↔ ¬ 𝐴𝑅𝐴)) | ||
| Theorem | elopaelxp 5706* | Membership in an ordered-pair class abstraction implies membership in a Cartesian product. (Contributed by Alexander van der Vekens, 23-Jun-2018.) Avoid ax-sep 5234, ax-nul 5244, ax-pr 5370. (Revised by SN, 11-Dec-2024.) |
| ⊢ (𝐴 ∈ {〈𝑥, 𝑦〉 ∣ 𝜓} → 𝐴 ∈ (V × V)) | ||
| Theorem | bropaex12 5707* | Two classes related by an ordered-pair class abstraction are sets. (Contributed by AV, 21-Jan-2020.) |
| ⊢ 𝑅 = {〈𝑥, 𝑦〉 ∣ 𝜓} ⇒ ⊢ (𝐴𝑅𝐵 → (𝐴 ∈ V ∧ 𝐵 ∈ V)) | ||
| Theorem | opabssxp 5708* | An abstraction relation is a subset of a related Cartesian product. (Contributed by NM, 16-Jul-1995.) |
| ⊢ {〈𝑥, 𝑦〉 ∣ ((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ 𝜑)} ⊆ (𝐴 × 𝐵) | ||
| Theorem | brab2a 5709* | The law of concretion for a binary relation. Ordered pair membership in an ordered pair class abstraction. (Contributed by Mario Carneiro, 28-Apr-2015.) |
| ⊢ ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → (𝜑 ↔ 𝜓)) & ⊢ 𝑅 = {〈𝑥, 𝑦〉 ∣ ((𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) ∧ 𝜑)} ⇒ ⊢ (𝐴𝑅𝐵 ↔ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷) ∧ 𝜓)) | ||
| Theorem | optocl 5710* | Implicit substitution of class for ordered pair. (Contributed by NM, 5-Mar-1995.) Shorten and reduce axiom usage. (Revised by TM, 29-Dec-2025.) |
| ⊢ 𝐷 = (𝐵 × 𝐶) & ⊢ (〈𝑥, 𝑦〉 = 𝐴 → (𝜑 ↔ 𝜓)) & ⊢ ((𝑥 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶) → 𝜑) ⇒ ⊢ (𝐴 ∈ 𝐷 → 𝜓) | ||
| Theorem | optoclOLD 5711* | Obsolete version of optocl 5710 as of 29-Dec-2025. (Contributed by NM, 5-Mar-1995.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 𝐷 = (𝐵 × 𝐶) & ⊢ (〈𝑥, 𝑦〉 = 𝐴 → (𝜑 ↔ 𝜓)) & ⊢ ((𝑥 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶) → 𝜑) ⇒ ⊢ (𝐴 ∈ 𝐷 → 𝜓) | ||
| Theorem | 2optocl 5712* | Implicit substitution of classes for ordered pairs. (Contributed by NM, 12-Mar-1995.) |
| ⊢ 𝑅 = (𝐶 × 𝐷) & ⊢ (〈𝑥, 𝑦〉 = 𝐴 → (𝜑 ↔ 𝜓)) & ⊢ (〈𝑧, 𝑤〉 = 𝐵 → (𝜓 ↔ 𝜒)) & ⊢ (((𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) ∧ (𝑧 ∈ 𝐶 ∧ 𝑤 ∈ 𝐷)) → 𝜑) ⇒ ⊢ ((𝐴 ∈ 𝑅 ∧ 𝐵 ∈ 𝑅) → 𝜒) | ||
| Theorem | 3optocl 5713* | Implicit substitution of classes for ordered pairs. (Contributed by NM, 12-Mar-1995.) |
| ⊢ 𝑅 = (𝐷 × 𝐹) & ⊢ (〈𝑥, 𝑦〉 = 𝐴 → (𝜑 ↔ 𝜓)) & ⊢ (〈𝑧, 𝑤〉 = 𝐵 → (𝜓 ↔ 𝜒)) & ⊢ (〈𝑣, 𝑢〉 = 𝐶 → (𝜒 ↔ 𝜃)) & ⊢ (((𝑥 ∈ 𝐷 ∧ 𝑦 ∈ 𝐹) ∧ (𝑧 ∈ 𝐷 ∧ 𝑤 ∈ 𝐹) ∧ (𝑣 ∈ 𝐷 ∧ 𝑢 ∈ 𝐹)) → 𝜑) ⇒ ⊢ ((𝐴 ∈ 𝑅 ∧ 𝐵 ∈ 𝑅 ∧ 𝐶 ∈ 𝑅) → 𝜃) | ||
| Theorem | opbrop 5714* | Ordered pair membership in a relation. Special case. (Contributed by NM, 5-Aug-1995.) |
| ⊢ (((𝑧 = 𝐴 ∧ 𝑤 = 𝐵) ∧ (𝑣 = 𝐶 ∧ 𝑢 = 𝐷)) → (𝜑 ↔ 𝜓)) & ⊢ 𝑅 = {〈𝑥, 𝑦〉 ∣ ((𝑥 ∈ (𝑆 × 𝑆) ∧ 𝑦 ∈ (𝑆 × 𝑆)) ∧ ∃𝑧∃𝑤∃𝑣∃𝑢((𝑥 = 〈𝑧, 𝑤〉 ∧ 𝑦 = 〈𝑣, 𝑢〉) ∧ 𝜑))} ⇒ ⊢ (((𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆) ∧ (𝐶 ∈ 𝑆 ∧ 𝐷 ∈ 𝑆)) → (〈𝐴, 𝐵〉𝑅〈𝐶, 𝐷〉 ↔ 𝜓)) | ||
| Theorem | 0xp 5715 | The Cartesian product with the empty set is empty. Part of Theorem 3.13(ii) of [Monk1] p. 37. (Contributed by NM, 4-Jul-1994.) |
| ⊢ (∅ × 𝐴) = ∅ | ||
| Theorem | csbxp 5716 | Distribute proper substitution through the Cartesian product of two classes. (Contributed by Alan Sare, 10-Nov-2012.) (Revised by NM, 23-Aug-2018.) |
| ⊢ ⦋𝐴 / 𝑥⦌(𝐵 × 𝐶) = (⦋𝐴 / 𝑥⦌𝐵 × ⦋𝐴 / 𝑥⦌𝐶) | ||
| Theorem | releq 5717 | Equality theorem for the relation predicate. (Contributed by NM, 1-Aug-1994.) |
| ⊢ (𝐴 = 𝐵 → (Rel 𝐴 ↔ Rel 𝐵)) | ||
| Theorem | releqi 5718 | Equality inference for the relation predicate. (Contributed by NM, 8-Dec-2006.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (Rel 𝐴 ↔ Rel 𝐵) | ||
| Theorem | releqd 5719 | Equality deduction for the relation predicate. (Contributed by NM, 8-Mar-2014.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (Rel 𝐴 ↔ Rel 𝐵)) | ||
| Theorem | nfrel 5720 | Bound-variable hypothesis builder for a relation. (Contributed by NM, 31-Jan-2004.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑥𝐴 ⇒ ⊢ Ⅎ𝑥Rel 𝐴 | ||
| Theorem | sbcrel 5721 | Distribute proper substitution through a relation predicate. (Contributed by Alexander van der Vekens, 23-Jul-2017.) |
| ⊢ (𝐴 ∈ 𝑉 → ([𝐴 / 𝑥]Rel 𝑅 ↔ Rel ⦋𝐴 / 𝑥⦌𝑅)) | ||
| Theorem | relss 5722 | Subclass theorem for relation predicate. Theorem 2 of [Suppes] p. 58. (Contributed by NM, 15-Aug-1994.) |
| ⊢ (𝐴 ⊆ 𝐵 → (Rel 𝐵 → Rel 𝐴)) | ||
| Theorem | ssrel 5723* | A subclass relationship depends only on a relation's ordered pairs. Theorem 3.2(i) of [Monk1] p. 33. (Contributed by NM, 2-Aug-1994.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) Remove dependency on ax-sep 5234, ax-nul 5244, ax-pr 5370. (Revised by KP, 25-Oct-2021.) Remove dependency on ax-12 2180. (Revised by SN, 11-Dec-2024.) |
| ⊢ (Rel 𝐴 → (𝐴 ⊆ 𝐵 ↔ ∀𝑥∀𝑦(〈𝑥, 𝑦〉 ∈ 𝐴 → 〈𝑥, 𝑦〉 ∈ 𝐵))) | ||
| Theorem | eqrel 5724* | Extensionality principle for relations. Theorem 3.2(ii) of [Monk1] p. 33. (Contributed by NM, 2-Aug-1994.) |
| ⊢ ((Rel 𝐴 ∧ Rel 𝐵) → (𝐴 = 𝐵 ↔ ∀𝑥∀𝑦(〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵))) | ||
| Theorem | ssrel2 5725* | A subclass relationship depends only on a relation's ordered pairs. This version of ssrel 5723 is restricted to the relation's domain. (Contributed by Thierry Arnoux, 25-Jan-2018.) |
| ⊢ (𝑅 ⊆ (𝐴 × 𝐵) → (𝑅 ⊆ 𝑆 ↔ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐵 (〈𝑥, 𝑦〉 ∈ 𝑅 → 〈𝑥, 𝑦〉 ∈ 𝑆))) | ||
| Theorem | ssrel3 5726* | Subclass relation in another form when the subclass is a relation. (Contributed by Peter Mazsa, 16-Feb-2019.) |
| ⊢ (Rel 𝐴 → (𝐴 ⊆ 𝐵 ↔ ∀𝑥∀𝑦(𝑥𝐴𝑦 → 𝑥𝐵𝑦))) | ||
| Theorem | relssi 5727* | Inference from subclass principle for relations. (Contributed by NM, 31-Mar-1998.) |
| ⊢ Rel 𝐴 & ⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 → 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ 𝐴 ⊆ 𝐵 | ||
| Theorem | relssdv 5728* | Deduction from subclass principle for relations. (Contributed by NM, 11-Sep-2004.) |
| ⊢ (𝜑 → Rel 𝐴) & ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 → 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐵) | ||
| Theorem | eqrelriv 5729* | Inference from extensionality principle for relations. (Contributed by FL, 15-Oct-2012.) |
| ⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ ((Rel 𝐴 ∧ Rel 𝐵) → 𝐴 = 𝐵) | ||
| Theorem | eqrelriiv 5730* | Inference from extensionality principle for relations. (Contributed by NM, 17-Mar-1995.) |
| ⊢ Rel 𝐴 & ⊢ Rel 𝐵 & ⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ 𝐴 = 𝐵 | ||
| Theorem | eqbrriv 5731* | Inference from extensionality principle for relations. (Contributed by NM, 12-Dec-2006.) |
| ⊢ Rel 𝐴 & ⊢ Rel 𝐵 & ⊢ (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦) ⇒ ⊢ 𝐴 = 𝐵 | ||
| Theorem | eqrelrdv 5732* | Deduce equality of relations from equivalence of membership. (Contributed by Rodolfo Medina, 10-Oct-2010.) |
| ⊢ Rel 𝐴 & ⊢ Rel 𝐵 & ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) | ||
| Theorem | eqbrrdv 5733* | Deduction from extensionality principle for relations. (Contributed by Mario Carneiro, 3-Jan-2017.) |
| ⊢ (𝜑 → Rel 𝐴) & ⊢ (𝜑 → Rel 𝐵) & ⊢ (𝜑 → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) | ||
| Theorem | eqbrrdiv 5734* | Deduction from extensionality principle for relations. (Contributed by Rodolfo Medina, 10-Oct-2010.) |
| ⊢ Rel 𝐴 & ⊢ Rel 𝐵 & ⊢ (𝜑 → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) | ||
| Theorem | eqrelrdv2 5735* | A version of eqrelrdv 5732. (Contributed by Rodolfo Medina, 10-Oct-2010.) |
| ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (((Rel 𝐴 ∧ Rel 𝐵) ∧ 𝜑) → 𝐴 = 𝐵) | ||
| Theorem | ssrelrel 5736* | A subclass relationship determined by ordered triples. Use relrelss 6220 to express the antecedent in terms of the relation predicate. (Contributed by NM, 17-Dec-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐴 ⊆ ((V × V) × V) → (𝐴 ⊆ 𝐵 ↔ ∀𝑥∀𝑦∀𝑧(〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐴 → 〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐵))) | ||
| Theorem | eqrelrel 5737* | Extensionality principle for ordered triples (used by 2-place operations df-oprab 7350), analogous to eqrel 5724. Use relrelss 6220 to express the antecedent in terms of the relation predicate. (Contributed by NM, 17-Dec-2008.) |
| ⊢ ((𝐴 ∪ 𝐵) ⊆ ((V × V) × V) → (𝐴 = 𝐵 ↔ ∀𝑥∀𝑦∀𝑧(〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐴 ↔ 〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐵))) | ||
| Theorem | elrel 5738* | A member of a relation is an ordered pair. (Contributed by NM, 17-Sep-2006.) |
| ⊢ ((Rel 𝑅 ∧ 𝐴 ∈ 𝑅) → ∃𝑥∃𝑦 𝐴 = 〈𝑥, 𝑦〉) | ||
| Theorem | rel0 5739 | The empty set is a relation. (Contributed by NM, 26-Apr-1998.) |
| ⊢ Rel ∅ | ||
| Theorem | nrelv 5740 | The universal class is not a relation. (Contributed by Thierry Arnoux, 23-Jan-2022.) |
| ⊢ ¬ Rel V | ||
| Theorem | relsng 5741 | A singleton is a relation iff it is a singleton on an ordered pair. (Contributed by NM, 24-Sep-2013.) (Revised by BJ, 12-Feb-2022.) |
| ⊢ (𝐴 ∈ 𝑉 → (Rel {𝐴} ↔ 𝐴 ∈ (V × V))) | ||
| Theorem | relsnb 5742 | An at-most-singleton is a relation iff it is empty (because it is a "singleton on a proper class") or it is a singleton of an ordered pair. (Contributed by BJ, 26-Feb-2023.) |
| ⊢ (Rel {𝐴} ↔ (¬ 𝐴 ∈ V ∨ 𝐴 ∈ (V × V))) | ||
| Theorem | relsnopg 5743 | A singleton of an ordered pair is a relation. (Contributed by NM, 17-May-1998.) (Revised by BJ, 12-Feb-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → Rel {〈𝐴, 𝐵〉}) | ||
| Theorem | relsn 5744 | A singleton is a relation iff it is an ordered pair. (Contributed by NM, 24-Sep-2013.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ (Rel {𝐴} ↔ 𝐴 ∈ (V × V)) | ||
| Theorem | relsnop 5745 | A singleton of an ordered pair is a relation. (Contributed by NM, 17-May-1998.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ Rel {〈𝐴, 𝐵〉} | ||
| Theorem | copsex2gb 5746* | Implicit substitution inference for ordered pairs. Compare copsex2ga 5747. (Contributed by NM, 12-Mar-2014.) |
| ⊢ (𝐴 = 〈𝑥, 𝑦〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 𝜓) ↔ (𝐴 ∈ (V × V) ∧ 𝜑)) | ||
| Theorem | copsex2ga 5747* | Implicit substitution inference for ordered pairs. Compare copsex2g 5433. (Contributed by NM, 26-Feb-2014.) (Proof shortened by Mario Carneiro, 31-Aug-2015.) |
| ⊢ (𝐴 = 〈𝑥, 𝑦〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (𝐴 ∈ (𝑉 × 𝑊) → (𝜑 ↔ ∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 𝜓))) | ||
| Theorem | elopaba 5748* | Membership in an ordered-pair class abstraction. (Contributed by NM, 25-Feb-2014.) (Revised by Mario Carneiro, 31-Aug-2015.) |
| ⊢ (𝐴 = 〈𝑥, 𝑦〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (𝐴 ∈ {〈𝑥, 𝑦〉 ∣ 𝜓} ↔ (𝐴 ∈ (V × V) ∧ 𝜑)) | ||
| Theorem | xpsspw 5749 | A Cartesian product is included in the power of the power of the union of its arguments. (Contributed by NM, 13-Sep-2006.) |
| ⊢ (𝐴 × 𝐵) ⊆ 𝒫 𝒫 (𝐴 ∪ 𝐵) | ||
| Theorem | unixpss 5750 | The double class union of a Cartesian product is included in the union of its arguments. (Contributed by NM, 16-Sep-2006.) |
| ⊢ ∪ ∪ (𝐴 × 𝐵) ⊆ (𝐴 ∪ 𝐵) | ||
| Theorem | relun 5751 | The union of two relations is a relation. Compare Exercise 5 of [TakeutiZaring] p. 25. (Contributed by NM, 12-Aug-1994.) |
| ⊢ (Rel (𝐴 ∪ 𝐵) ↔ (Rel 𝐴 ∧ Rel 𝐵)) | ||
| Theorem | relin1 5752 | The intersection with a relation is a relation. (Contributed by NM, 16-Aug-1994.) |
| ⊢ (Rel 𝐴 → Rel (𝐴 ∩ 𝐵)) | ||
| Theorem | relin2 5753 | The intersection with a relation is a relation. (Contributed by NM, 17-Jan-2006.) |
| ⊢ (Rel 𝐵 → Rel (𝐴 ∩ 𝐵)) | ||
| Theorem | relinxp 5754 | Intersection with a Cartesian product is a relation. (Contributed by Peter Mazsa, 4-Mar-2019.) |
| ⊢ Rel (𝑅 ∩ (𝐴 × 𝐵)) | ||
| Theorem | reldif 5755 | A difference cutting down a relation is a relation. (Contributed by NM, 31-Mar-1998.) |
| ⊢ (Rel 𝐴 → Rel (𝐴 ∖ 𝐵)) | ||
| Theorem | reliun 5756 | An indexed union is a relation iff each member of its indexed family is a relation. (Contributed by NM, 19-Dec-2008.) |
| ⊢ (Rel ∪ 𝑥 ∈ 𝐴 𝐵 ↔ ∀𝑥 ∈ 𝐴 Rel 𝐵) | ||
| Theorem | reliin 5757 | An indexed intersection is a relation if at least one of the member of the indexed family is a relation. (Contributed by NM, 8-Mar-2014.) |
| ⊢ (∃𝑥 ∈ 𝐴 Rel 𝐵 → Rel ∩ 𝑥 ∈ 𝐴 𝐵) | ||
| Theorem | reluni 5758* | The union of a class is a relation iff any member is a relation. Exercise 6 of [TakeutiZaring] p. 25 and its converse. (Contributed by NM, 13-Aug-2004.) |
| ⊢ (Rel ∪ 𝐴 ↔ ∀𝑥 ∈ 𝐴 Rel 𝑥) | ||
| Theorem | relint 5759* | The intersection of a class is a relation if at least one member is a relation. (Contributed by NM, 8-Mar-2014.) |
| ⊢ (∃𝑥 ∈ 𝐴 Rel 𝑥 → Rel ∩ 𝐴) | ||
| Theorem | relopabiv 5760* | A class of ordered pairs is a relation. For a version without a disjoint variable condition, but a longer proof using ax-11 2160 and ax-12 2180, see relopabi 5762. (Contributed by BJ, 22-Jul-2023.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopabv 5761* | A class of ordered pairs is a relation. For a version without a disjoint variable condition, but using ax-11 2160 and ax-12 2180, see relopab 5764. (Contributed by SN, 8-Sep-2024.) |
| ⊢ Rel {〈𝑥, 𝑦〉 ∣ 𝜑} | ||
| Theorem | relopabi 5762 | A class of ordered pairs is a relation. (Contributed by Mario Carneiro, 21-Dec-2013.) Remove dependency on ax-sep 5234, ax-nul 5244, ax-pr 5370. (Revised by KP, 25-Oct-2021.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopabiALT 5763 | Alternate proof of relopabi 5762 (shorter but uses more axioms). (Contributed by Mario Carneiro, 21-Dec-2013.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopab 5764 | A class of ordered pairs is a relation. (Contributed by NM, 8-Mar-1995.) Remove disjoint variable conditions. (Revised by Alan Sare, 9-Jul-2013.) (Proof shortened by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel {〈𝑥, 𝑦〉 ∣ 𝜑} | ||
| Theorem | mptrel 5765 | The maps-to notation always describes a binary relation. (Contributed by Scott Fenton, 16-Apr-2012.) |
| ⊢ Rel (𝑥 ∈ 𝐴 ↦ 𝐵) | ||
| Theorem | reli 5766 | The identity relation is a relation. Part of Exercise 4.12(p) of [Mendelson] p. 235. (Contributed by NM, 26-Apr-1998.) (Revised by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel I | ||
| Theorem | rele 5767 | The membership relation is a relation. (Contributed by NM, 26-Apr-1998.) (Revised by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel E | ||
| Theorem | opabid2 5768* | A relation expressed as an ordered pair abstraction. (Contributed by NM, 11-Dec-2006.) |
| ⊢ (Rel 𝐴 → {〈𝑥, 𝑦〉 ∣ 〈𝑥, 𝑦〉 ∈ 𝐴} = 𝐴) | ||
| Theorem | inopab 5769* | Intersection of two ordered pair class abstractions. (Contributed by NM, 30-Sep-2002.) |
| ⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∩ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ 𝜓)} | ||
| Theorem | difopab 5770* | Difference of two ordered-pair class abstractions. (Contributed by Stefan O'Rear, 17-Jan-2015.) (Proof shortened by SN, 19-Dec-2024.) |
| ⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∖ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ ¬ 𝜓)} | ||
| Theorem | inxp 5771 | Intersection of two Cartesian products. Exercise 9 of [TakeutiZaring] p. 25. (Contributed by NM, 3-Aug-1994.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) Avoid ax-10 2144, ax-12 2180. (Revised by SN, 5-May-2025.) |
| ⊢ ((𝐴 × 𝐵) ∩ (𝐶 × 𝐷)) = ((𝐴 ∩ 𝐶) × (𝐵 ∩ 𝐷)) | ||
| Theorem | inxpOLD 5772 | Obsolete version of inxp 5771 as of 5-May-2025. (Contributed by NM, 3-Aug-1994.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ((𝐴 × 𝐵) ∩ (𝐶 × 𝐷)) = ((𝐴 ∩ 𝐶) × (𝐵 ∩ 𝐷)) | ||
| Theorem | xpindi 5773 | Distributive law for Cartesian product over intersection. Theorem 102 of [Suppes] p. 52. (Contributed by NM, 26-Sep-2004.) |
| ⊢ (𝐴 × (𝐵 ∩ 𝐶)) = ((𝐴 × 𝐵) ∩ (𝐴 × 𝐶)) | ||
| Theorem | xpindir 5774 | Distributive law for Cartesian product over intersection. Similar to Theorem 102 of [Suppes] p. 52. (Contributed by NM, 26-Sep-2004.) |
| ⊢ ((𝐴 ∩ 𝐵) × 𝐶) = ((𝐴 × 𝐶) ∩ (𝐵 × 𝐶)) | ||
| Theorem | xpiindi 5775* | Distributive law for Cartesian product over indexed intersection. (Contributed by Mario Carneiro, 21-Mar-2015.) |
| ⊢ (𝐴 ≠ ∅ → (𝐶 × ∩ 𝑥 ∈ 𝐴 𝐵) = ∩ 𝑥 ∈ 𝐴 (𝐶 × 𝐵)) | ||
| Theorem | xpriindi 5776* | Distributive law for Cartesian product over relativized indexed intersection. (Contributed by Mario Carneiro, 21-Mar-2015.) |
| ⊢ (𝐶 × (𝐷 ∩ ∩ 𝑥 ∈ 𝐴 𝐵)) = ((𝐶 × 𝐷) ∩ ∩ 𝑥 ∈ 𝐴 (𝐶 × 𝐵)) | ||
| Theorem | eliunxp 5777* | Membership in a union of Cartesian products. Analogue of elxp 5639 for nonconstant 𝐵(𝑥). (Contributed by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝐶 ∈ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ ∃𝑥∃𝑦(𝐶 = 〈𝑥, 𝑦〉 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵))) | ||
| Theorem | opeliunxp2 5778* | Membership in a union of Cartesian products. (Contributed by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 𝐶 → 𝐵 = 𝐸) ⇒ ⊢ (〈𝐶, 𝐷〉 ∈ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ (𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐸)) | ||
| Theorem | raliunxp 5779* | Write a double restricted quantification as one universal quantifier. In this version of ralxp 5781, 𝐵(𝑦) is not assumed to be constant. (Contributed by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ ∪ 𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexiunxp 5780* | Write a double restricted quantification as one universal quantifier. In this version of rexxp 5782, 𝐵(𝑦) is not assumed to be constant. (Contributed by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ ∪ 𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | ralxp 5781* | Universal quantification restricted to a Cartesian product is equivalent to a double restricted quantification. The hypothesis specifies an implicit substitution. (Contributed by NM, 7-Feb-2004.) (Revised by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexxp 5782* | Existential quantification restricted to a Cartesian product is equivalent to a double restricted quantification. (Contributed by NM, 11-Nov-1995.) (Revised by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | exopxfr 5783* | Transfer ordered-pair existence from/to single variable existence. (Contributed by NM, 26-Feb-2014.) (Proof shortened by Mario Carneiro, 31-Aug-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (V × V)𝜑 ↔ ∃𝑦∃𝑧𝜓) | ||
| Theorem | exopxfr2 5784* | Transfer ordered-pair existence from/to single variable existence. (Contributed by NM, 26-Feb-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (Rel 𝐴 → (∃𝑥 ∈ 𝐴 𝜑 ↔ ∃𝑦∃𝑧(〈𝑦, 𝑧〉 ∈ 𝐴 ∧ 𝜓))) | ||
| Theorem | djussxp 5785* | Disjoint union is a subset of a Cartesian product. (Contributed by Stefan O'Rear, 21-Nov-2014.) |
| ⊢ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ⊆ (𝐴 × V) | ||
| Theorem | ralxpf 5786* | Version of ralxp 5781 with bound-variable hypotheses. (Contributed by NM, 18-Aug-2006.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑧𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexxpf 5787* | Version of rexxp 5782 with bound-variable hypotheses. (Contributed by NM, 19-Dec-2008.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑧𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | iunxpf 5788* | Indexed union on a Cartesian product equals a double indexed union. The hypothesis specifies an implicit substitution. (Contributed by NM, 19-Dec-2008.) |
| ⊢ Ⅎ𝑦𝐶 & ⊢ Ⅎ𝑧𝐶 & ⊢ Ⅎ𝑥𝐷 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → 𝐶 = 𝐷) ⇒ ⊢ ∪ 𝑥 ∈ (𝐴 × 𝐵)𝐶 = ∪ 𝑦 ∈ 𝐴 ∪ 𝑧 ∈ 𝐵 𝐷 | ||
| Theorem | opabbi2dv 5789* | Deduce equality of a relation and an ordered-pair class abstraction. Compare eqabdv 2864. (Contributed by NM, 24-Feb-2014.) |
| ⊢ Rel 𝐴 & ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 𝜓)) ⇒ ⊢ (𝜑 → 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜓}) | ||
| Theorem | relop 5790* | A necessary and sufficient condition for a Kuratowski ordered pair to be a relation. (Contributed by NM, 3-Jun-2008.) A relation is a class of ordered pairs, so the fact that an ordered pair may sometimes be itself a relation is an "accident" depending on the specific encoding of ordered pairs as classes (in set.mm, the Kuratowski encoding). A more meaningful statement is relsnopg 5743, as funsng 6532 is to funop 7082. (New usage is discouraged.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (Rel 〈𝐴, 𝐵〉 ↔ ∃𝑥∃𝑦(𝐴 = {𝑥} ∧ 𝐵 = {𝑥, 𝑦})) | ||
| Theorem | ideqg 5791 | For sets, the identity relation is the same as equality. (Contributed by NM, 30-Apr-2004.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐵 ∈ 𝑉 → (𝐴 I 𝐵 ↔ 𝐴 = 𝐵)) | ||
| Theorem | ideq 5792 | For sets, the identity relation is the same as equality. (Contributed by NM, 13-Aug-1995.) |
| ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴 I 𝐵 ↔ 𝐴 = 𝐵) | ||
| Theorem | ididg 5793 | A set is identical to itself. (Contributed by NM, 28-May-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐴 ∈ 𝑉 → 𝐴 I 𝐴) | ||
| Theorem | issetid 5794 | Two ways of expressing set existence. (Contributed by NM, 16-Feb-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ (𝐴 ∈ V ↔ 𝐴 I 𝐴) | ||
| Theorem | coss1 5795 | Subclass theorem for composition. (Contributed by FL, 30-Dec-2010.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∘ 𝐶) ⊆ (𝐵 ∘ 𝐶)) | ||
| Theorem | coss2 5796 | Subclass theorem for composition. (Contributed by NM, 5-Apr-2013.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∘ 𝐴) ⊆ (𝐶 ∘ 𝐵)) | ||
| Theorem | coeq1 5797 | Equality theorem for composition of two classes. (Contributed by NM, 3-Jan-1997.) |
| ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶)) | ||
| Theorem | coeq2 5798 | Equality theorem for composition of two classes. (Contributed by NM, 3-Jan-1997.) |
| ⊢ (𝐴 = 𝐵 → (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵)) | ||
| Theorem | coeq1i 5799 | Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶) | ||
| Theorem | coeq2i 5800 | Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵) | ||
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