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Theorem bj-vn0ALT 37824
Description: Alternate proof of vn0 4294 which does not use eqabbw 2835 (and is shorter than vn0 4294 when eqabbw 2835 is inlined). (Contributed by BJ, 12-Jul-2026.) Using the same dummy variable for 𝑦 and 𝑧 slightly reduces the proof size. (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
bj-vn0ALT V ≠ ∅

Proof of Theorem bj-vn0ALT
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 fal 1584 . . 3 ¬ ⊥
2 dfv2 3456 . . . . 5 V = {𝑦 ∣ ⊤}
3 dfnul4 4284 . . . . 5 ∅ = {𝑧 ∣ ⊥}
42, 3eqeq12i 2780 . . . 4 (V = ∅ ↔ {𝑦 ∣ ⊤} = {𝑧 ∣ ⊥})
5 dfcleq 2755 . . . . 5 ({𝑦 ∣ ⊤} = {𝑧 ∣ ⊥} ↔ ∀𝑥(𝑥 ∈ {𝑦 ∣ ⊤} ↔ 𝑥 ∈ {𝑧 ∣ ⊥}))
6 df-clab 2741 . . . . . . . . 9 (𝑥 ∈ {𝑦 ∣ ⊤} ↔ [𝑥 / 𝑦]⊤)
7 sbv 2125 . . . . . . . . 9 ([𝑥 / 𝑦]⊤ ↔ ⊤)
86, 7bitri 278 . . . . . . . 8 (𝑥 ∈ {𝑦 ∣ ⊤} ↔ ⊤)
9 df-clab 2741 . . . . . . . . 9 (𝑥 ∈ {𝑧 ∣ ⊥} ↔ [𝑥 / 𝑧]⊥)
10 sbv 2125 . . . . . . . . 9 ([𝑥 / 𝑧]⊥ ↔ ⊥)
119, 10bitri 278 . . . . . . . 8 (𝑥 ∈ {𝑧 ∣ ⊥} ↔ ⊥)
128, 11bibi12i 342 . . . . . . 7 ((𝑥 ∈ {𝑦 ∣ ⊤} ↔ 𝑥 ∈ {𝑧 ∣ ⊥}) ↔ (⊤ ↔ ⊥))
13 trubifal 1601 . . . . . . 7 ((⊤ ↔ ⊥) ↔ ⊥)
1412, 13sylbb 222 . . . . . 6 ((𝑥 ∈ {𝑦 ∣ ⊤} ↔ 𝑥 ∈ {𝑧 ∣ ⊥}) → ⊥)
1514spsv 2020 . . . . 5 (∀𝑥(𝑥 ∈ {𝑦 ∣ ⊤} ↔ 𝑥 ∈ {𝑧 ∣ ⊥}) → ⊥)
165, 15sylbi 220 . . . 4 ({𝑦 ∣ ⊤} = {𝑧 ∣ ⊥} → ⊥)
174, 16sylbi 220 . . 3 (V = ∅ → ⊥)
181, 17mto 200 . 2 ¬ V = ∅
1918neir 2960 1 V ≠ ∅
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wal 1568   = wceq 1570  wtru 1571  wfal 1582  [wsb 2099  wcel 2145  {cab 2740  wne 2957  Vcvv 3453  c0 4282
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-9 2155  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-ne 2958  df-v 3455  df-dif 3905  df-nul 4283
This theorem is used by: (None)
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