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Theorem bnj89 35119
Description: First-order logic and set theory. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (New usage is discouraged.)
Hypothesis
Ref Expression
bnj89.1 𝑍 ∈ V
Assertion
Ref Expression
bnj89 ([𝑍 / 𝑦]∃!𝑥𝜑 ↔ ∃!𝑥[𝑍 / 𝑦]𝜑)
Distinct variable groups:   𝑥,𝑍   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝑍(𝑦)

Proof of Theorem bnj89
Dummy variable 𝑤 is distinct from all other variables.
StepHypRef Expression
1 sbcex2 3803 . . 3 ([𝑍 / 𝑦]𝑤𝑥(𝜑𝑥 = 𝑤) ↔ ∃𝑤[𝑍 / 𝑦]𝑥(𝜑𝑥 = 𝑤))
2 sbcal 3802 . . . 4 ([𝑍 / 𝑦]𝑥(𝜑𝑥 = 𝑤) ↔ ∀𝑥[𝑍 / 𝑦](𝜑𝑥 = 𝑤))
32exbii 1877 . . 3 (∃𝑤[𝑍 / 𝑦]𝑥(𝜑𝑥 = 𝑤) ↔ ∃𝑤𝑥[𝑍 / 𝑦](𝜑𝑥 = 𝑤))
4 bnj89.1 . . . . . . 7 𝑍 ∈ V
5 sbcbig 3794 . . . . . . 7 (𝑍 ∈ V → ([𝑍 / 𝑦](𝜑𝑥 = 𝑤) ↔ ([𝑍 / 𝑦]𝜑[𝑍 / 𝑦]𝑥 = 𝑤)))
64, 5ax-mp 5 . . . . . 6 ([𝑍 / 𝑦](𝜑𝑥 = 𝑤) ↔ ([𝑍 / 𝑦]𝜑[𝑍 / 𝑦]𝑥 = 𝑤))
7 sbcg 3815 . . . . . . . 8 (𝑍 ∈ V → ([𝑍 / 𝑦]𝑥 = 𝑤𝑥 = 𝑤))
84, 7ax-mp 5 . . . . . . 7 ([𝑍 / 𝑦]𝑥 = 𝑤𝑥 = 𝑤)
98bibi2i 340 . . . . . 6 (([𝑍 / 𝑦]𝜑[𝑍 / 𝑦]𝑥 = 𝑤) ↔ ([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
106, 9bitri 278 . . . . 5 ([𝑍 / 𝑦](𝜑𝑥 = 𝑤) ↔ ([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
1110albii 1848 . . . 4 (∀𝑥[𝑍 / 𝑦](𝜑𝑥 = 𝑤) ↔ ∀𝑥([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
1211exbii 1877 . . 3 (∃𝑤𝑥[𝑍 / 𝑦](𝜑𝑥 = 𝑤) ↔ ∃𝑤𝑥([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
131, 3, 123bitri 300 . 2 ([𝑍 / 𝑦]𝑤𝑥(𝜑𝑥 = 𝑤) ↔ ∃𝑤𝑥([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
14 eu6 2601 . . 3 (∃!𝑥𝜑 ↔ ∃𝑤𝑥(𝜑𝑥 = 𝑤))
1514sbcbii 3799 . 2 ([𝑍 / 𝑦]∃!𝑥𝜑[𝑍 / 𝑦]𝑤𝑥(𝜑𝑥 = 𝑤))
16 eu6 2601 . 2 (∃!𝑥[𝑍 / 𝑦]𝜑 ↔ ∃𝑤𝑥([𝑍 / 𝑦]𝜑𝑥 = 𝑤))
1713, 15, 163bitr4i 306 1 ([𝑍 / 𝑦]∃!𝑥𝜑 ↔ ∃!𝑥[𝑍 / 𝑦]𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wal 1567  wex 1808  wcel 2142  ∃!weu 2595  Vcvv 3454  [wsbc 3743
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-10 2175  ax-11 2191  ax-12 2212  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-tru 1572  df-ex 1809  df-nf 1813  df-sb 2096  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-v 3456  df-sbc 3744
This theorem is used by:  bnj130  35271  bnj207  35278
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