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Theorem brabd0 35245
Description: Expressing that two sets are related by a binary relation which is expressed as a class abstraction of ordered pairs. (Contributed by BJ, 17-Dec-2023.)
Hypotheses
Ref Expression
brabd0.x (𝜑 → ∀𝑥𝜑)
brabd0.y (𝜑 → ∀𝑦𝜑)
brabd0.xch (𝜑 → Ⅎ𝑥𝜒)
brabd0.ych (𝜑 → Ⅎ𝑦𝜒)
brabd0.exa (𝜑𝐴𝑈)
brabd0.exb (𝜑𝐵𝑉)
brabd0.def (𝜑𝑅 = {⟨𝑥, 𝑦⟩ ∣ 𝜓})
brabd0.is ((𝜑 ∧ (𝑥 = 𝐴𝑦 = 𝐵)) → (𝜓𝜒))
Assertion
Ref Expression
brabd0 (𝜑 → (𝐴𝑅𝐵𝜒))
Distinct variable groups:   𝑥,𝐴,𝑦   𝑥,𝐵,𝑦
Allowed substitution hints:   𝜑(𝑥,𝑦)   𝜓(𝑥,𝑦)   𝜒(𝑥,𝑦)   𝑅(𝑥,𝑦)   𝑈(𝑥,𝑦)   𝑉(𝑥,𝑦)

Proof of Theorem brabd0
StepHypRef Expression
1 df-br 5071 . . 3 (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑅)
2 brabd0.def . . . 4 (𝜑𝑅 = {⟨𝑥, 𝑦⟩ ∣ 𝜓})
32eleq2d 2824 . . 3 (𝜑 → (⟨𝐴, 𝐵⟩ ∈ 𝑅 ↔ ⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓}))
41, 3syl5bb 282 . 2 (𝜑 → (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓}))
5 brabd0.x . . 3 (𝜑 → ∀𝑥𝜑)
6 brabd0.y . . 3 (𝜑 → ∀𝑦𝜑)
7 brabd0.xch . . 3 (𝜑 → Ⅎ𝑥𝜒)
8 brabd0.ych . . 3 (𝜑 → Ⅎ𝑦𝜒)
9 brabd0.exa . . 3 (𝜑𝐴𝑈)
10 brabd0.exb . . 3 (𝜑𝐵𝑉)
11 brabd0.is . . 3 ((𝜑 ∧ (𝑥 = 𝐴𝑦 = 𝐵)) → (𝜓𝜒))
125, 6, 7, 8, 9, 10, 11opelopabd 35239 . 2 (𝜑 → (⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓} ↔ 𝜒))
134, 12bitrd 278 1 (𝜑 → (𝐴𝑅𝐵𝜒))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 205  wa 395  wal 1537   = wceq 1539  wnf 1787  wcel 2108  cop 4564   class class class wbr 5070  {copab 5132
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1799  ax-4 1813  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2110  ax-9 2118  ax-10 2139  ax-11 2156  ax-12 2173  ax-ext 2709  ax-sep 5218  ax-nul 5225  ax-pr 5347
This theorem depends on definitions:  df-bi 206  df-an 396  df-or 844  df-3an 1087  df-tru 1542  df-fal 1552  df-ex 1784  df-nf 1788  df-sb 2069  df-mo 2540  df-eu 2569  df-clab 2716  df-cleq 2730  df-clel 2817  df-rab 3072  df-v 3424  df-dif 3886  df-un 3888  df-nul 4254  df-if 4457  df-sn 4559  df-pr 4561  df-op 4565  df-br 5071  df-opab 5133
This theorem is referenced by:  brabd  35246
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