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Theorem brabd0 38273
Description: Expressing that two sets are related by a binary relation which is expressed as a class abstraction of ordered pairs. (Contributed by BJ, 17-Dec-2023.)
Hypotheses
Ref Expression
brabd0.x (𝜑 → ∀𝑥𝜑)
brabd0.y (𝜑 → ∀𝑦𝜑)
brabd0.xch (𝜑 → Ⅎ𝑥𝜒)
brabd0.ych (𝜑 → Ⅎ𝑦𝜒)
brabd0.exa (𝜑 → 𝐴 ∈ 𝑈)
brabd0.exb (𝜑 → 𝐵 ∈ 𝑉)
brabd0.def (𝜑 → 𝑅 = {⟨𝑥, 𝑦⟩ ∣ 𝜓})
brabd0.is ((𝜑 ∧ (𝑥 = 𝐴 ∧ 𝑦 = 𝐵)) → (𝜓 ↔ 𝜒))
Assertion
Ref Expression
brabd0 (𝜑 → (𝐴𝑅𝐵 ↔ 𝜒))
Distinct variable groups:   𝑥,𝐴,𝑦   𝑥,𝐵,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥, 𝑦)   𝜒(𝑥, 𝑦)   𝑅(𝑥, 𝑦)   𝑈(𝑥, 𝑦)   𝑉(𝑥, 𝑦)

Proof of Theorem brabd0
StepHypRef Expression
1 df-br 5107 . . 3 (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑅)
2 brabd0.def . . . 4 (𝜑 → 𝑅 = {⟨𝑥, 𝑦⟩ ∣ 𝜓})
32eleq2d 2850 . . 3 (𝜑 → (⟨𝐴, 𝐵⟩ ∈ 𝑅 ↔ ⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓}))
41, 3bitrid 286 . 2 (𝜑 → (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓}))
5 brabd0.x . . 3 (𝜑 → ∀𝑥𝜑)
6 brabd0.y . . 3 (𝜑 → ∀𝑦𝜑)
7 brabd0.xch . . 3 (𝜑 → Ⅎ𝑥𝜒)
8 brabd0.ych . . 3 (𝜑 → Ⅎ𝑦𝜒)
9 brabd0.exa . . 3 (𝜑 → 𝐴 ∈ 𝑈)
10 brabd0.exb . . 3 (𝜑 → 𝐵 ∈ 𝑉)
11 brabd0.is . . 3 ((𝜑 ∧ (𝑥 = 𝐴 ∧ 𝑦 = 𝐵)) → (𝜓 ↔ 𝜒))
125, 6, 7, 8, 9, 10, 11opelopabd 38267 . 2 (𝜑 → (⟨𝐴, 𝐵⟩ ∈ {⟨𝑥, 𝑦⟩ ∣ 𝜓} ↔ 𝜒))
134, 12bitrd 282 1 (𝜑 → (𝐴𝑅𝐵 ↔ 𝜒))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1568   = wceq 1570  Ⅎwnf 1816   ∈ wcel 2147  ⟨cop 4838   class class class wbr 5106  {copab 5171
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5253  ax-pr 5396
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-br 5107  df-opab 5172
This theorem is used by:  brabd  38274
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