Theorem difprsn2 4767

Description: Removal of a singleton from an unordered pair. (Contributed by Alexander van der Vekens, 5-Oct-2017.)

Assertion

Ref	Expression
difprsn2	⊢ (𝐴 ≠ 𝐵 → ({𝐴, 𝐵} ∖ {𝐵}) = {𝐴})

Proof of Theorem difprsn2

Step	Hyp	Ref	Expression
1		prcom 4696	. . 3 ⊢ {𝐴, 𝐵} = {𝐵, 𝐴}
2	1	difeq1i 4073	. 2 ⊢ ({𝐴, 𝐵} ∖ {𝐵}) = ({𝐵, 𝐴} ∖ {𝐵})
3		necom 3010	. . 3 ⊢ (𝐴 ≠ 𝐵 ↔ 𝐵 ≠ 𝐴)
4		difprsn1 4766	. . 3 ⊢ (𝐵 ≠ 𝐴 → ({𝐵, 𝐴} ∖ {𝐵}) = {𝐴})
5	3, 4	sylbi 220	. 2 ⊢ (𝐴 ≠ 𝐵 → ({𝐵, 𝐴} ∖ {𝐵}) = {𝐴})
6	2, 5	eqtrid 2809	1 ⊢ (𝐴 ≠ 𝐵 → ({𝐴, 𝐵} ∖ {𝐵}) = {𝐴})

This proof depends on syntax axioms:   → wi 4   = wceq 1570   ≠ wne 2957   ∖ cdif 3899  {csn 4587  {cpr 4589

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-ral 3079  df-rab 3415  df-v 3455  df-dif 3905  df-un 3907  df-in 3909  df-nul 4283  df-sn 4588  df-pr 4590

This theorem is used by:  f12dfv  7278  pmtrprfval  19620  nbgr2vtx1edg  29818  nbuhgr2vtx1edgb  29820  nfrgr2v  30760  indsupp  33321  cycpm2tr  33567  drngmxidl  33887  ldepsnlinc  49446