Users' Mathboxes Mathbox for Alan Sare < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  e2ebindVD Structured version   Visualization version   GIF version

Theorem e2ebindVD 45988
Description: The following User's Proof is a Virtual Deduction proof (see wvd1 45646) completed automatically by a Metamath tools program invoking mmj2 and the Metamath Proof Assistant. e2ebind 45640 is e2ebindVD 45988 without virtual deductions and was automatically derived from e2ebindVD 45988.
1:: (𝜑 ↔ 𝜑)
2:1: (∀𝑦𝑦 = 𝑥 → (𝜑 ↔ 𝜑))
3:2: (∀𝑦𝑦 = 𝑥 → (∃𝑦𝜑 ↔ ∃𝑥𝜑 ))
4:: (   ∀𝑦𝑦 = 𝑥   ▶   ∀𝑦𝑦 = 𝑥   )
5:3,4: (   ∀𝑦𝑦 = 𝑥   ▶   (∃𝑦𝜑 ↔ ∃𝑥 𝜑)   )
6:: (∀𝑦𝑦 = 𝑥 → ∀𝑦∀𝑦𝑦 = 𝑥)
7:5,6: (   ∀𝑦𝑦 = 𝑥   ▶   ∀𝑦(∃𝑦𝜑 ↔ ∃𝑥𝜑)   )
8:7: (   ∀𝑦𝑦 = 𝑥   ▶   (∃𝑦∃𝑦𝜑 ↔ ∃𝑦∃𝑥𝜑)   )
9:: (∃𝑦∃𝑥𝜑 ↔ ∃𝑥∃𝑦𝜑)
10:8,9: (   ∀𝑦𝑦 = 𝑥   ▶   (∃𝑦∃𝑦𝜑 ↔ ∃𝑥∃𝑦𝜑)   )
11:: (∃𝑦𝜑 → ∀𝑦∃𝑦𝜑)
12:11: (∃𝑦∃𝑦𝜑 ↔ ∃𝑦𝜑)
13:10,12: (   ∀𝑦𝑦 = 𝑥   ▶   (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑)   )
14:13: (∀𝑦𝑦 = 𝑥 → (∃𝑥∃𝑦𝜑 ↔ ∃ 𝑦𝜑))
15:: (∀𝑦𝑦 = 𝑥 ↔ ∀𝑥𝑥 = 𝑦)
qed:14,15: (∀𝑥𝑥 = 𝑦 → (∃𝑥∃𝑦𝜑 ↔ ∃ 𝑦𝜑))
(Contributed by Alan Sare, 27-Nov-2014.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
e2ebindVD (∀𝑥 𝑥 = 𝑦 → (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑))

Proof of Theorem e2ebindVD
StepHypRef Expression
1 axc11n 2455 . 2 (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥)
2 hba1 2326 . . . . . . 7 (∀𝑦 𝑦 = 𝑥 → ∀𝑦∀𝑦 𝑦 = 𝑥)
3 idn1 45651 . . . . . . . 8 (   ∀𝑦 𝑦 = 𝑥   ▶   ∀𝑦 𝑦 = 𝑥   )
4 biid 264 . . . . . . . . . 10 (𝜑 ↔ 𝜑)
54a1i 11 . . . . . . . . 9 (∀𝑦 𝑦 = 𝑥 → (𝜑 ↔ 𝜑))
65drex1 2470 . . . . . . . 8 (∀𝑦 𝑦 = 𝑥 → (∃𝑦𝜑 ↔ ∃𝑥𝜑))
73, 6e1a 45704 . . . . . . 7 (   ∀𝑦 𝑦 = 𝑥   ▶   (∃𝑦𝜑 ↔ ∃𝑥𝜑)   )
82, 7gen11nv 45694 . . . . . 6 (   ∀𝑦 𝑦 = 𝑥   ▶   ∀𝑦(∃𝑦𝜑 ↔ ∃𝑥𝜑)   )
9 exbi 1879 . . . . . 6 (∀𝑦(∃𝑦𝜑 ↔ ∃𝑥𝜑) → (∃𝑦∃𝑦𝜑 ↔ ∃𝑦∃𝑥𝜑))
108, 9e1a 45704 . . . . 5 (   ∀𝑦 𝑦 = 𝑥   ▶   (∃𝑦∃𝑦𝜑 ↔ ∃𝑦∃𝑥𝜑)   )
11 excom 2198 . . . . 5 (∃𝑦∃𝑥𝜑 ↔ ∃𝑥∃𝑦𝜑)
12 bibi1 354 . . . . . 6 ((∃𝑦∃𝑦𝜑 ↔ ∃𝑦∃𝑥𝜑) → ((∃𝑦∃𝑦𝜑 ↔ ∃𝑥∃𝑦𝜑) ↔ (∃𝑦∃𝑥𝜑 ↔ ∃𝑥∃𝑦𝜑)))
1312biimprd 251 . . . . 5 ((∃𝑦∃𝑦𝜑 ↔ ∃𝑦∃𝑥𝜑) → ((∃𝑦∃𝑥𝜑 ↔ ∃𝑥∃𝑦𝜑) → (∃𝑦∃𝑦𝜑 ↔ ∃𝑥∃𝑦𝜑)))
1410, 11, 13e10 45771 . . . 4 (   ∀𝑦 𝑦 = 𝑥   ▶   (∃𝑦∃𝑦𝜑 ↔ ∃𝑥∃𝑦𝜑)   )
15 nfe1 2186 . . . . 5 Ⅎ𝑦∃𝑦𝜑
161519.9 2241 . . . 4 (∃𝑦∃𝑦𝜑 ↔ ∃𝑦𝜑)
17 bitr3 355 . . . 4 ((∃𝑦∃𝑦𝜑 ↔ ∃𝑥∃𝑦𝜑) → ((∃𝑦∃𝑦𝜑 ↔ ∃𝑦𝜑) → (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑)))
1814, 16, 17e10 45771 . . 3 (   ∀𝑦 𝑦 = 𝑥   ▶   (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑)   )
1918in1 45648 . 2 (∀𝑦 𝑦 = 𝑥 → (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑))
201, 19syl 18 1 (∀𝑥 𝑥 = 𝑦 → (∃𝑥∃𝑦𝜑 ↔ ∃𝑦𝜑))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1567   = wceq 1569  ∃wex 1811
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-10 2177  ax-11 2193  ax-12 2212  ax-13 2401
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1812  df-nf 1816  df-vd1 45647
This theorem is used by: (None)
  Copyright terms: Public domain W3C validator