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Theorem eldifpw 7788
Description: Membership in a power class difference. (Contributed by NM, 25-Mar-2007.)
Hypothesis
Ref Expression
eldifpw.1 𝐶 ∈ V
Assertion
Ref Expression
eldifpw ((𝐴 ∈ 𝒫 𝐵 ∧ ¬ 𝐶𝐵) → (𝐴𝐶) ∈ (𝒫 (𝐵𝐶) ∖ 𝒫 𝐵))

Proof of Theorem eldifpw
StepHypRef Expression
1 elpwi 4607 . . . 4 (𝐴 ∈ 𝒫 𝐵𝐴𝐵)
2 unss1 4185 . . . . 5 (𝐴𝐵 → (𝐴𝐶) ⊆ (𝐵𝐶))
3 eldifpw.1 . . . . . . 7 𝐶 ∈ V
4 unexg 7763 . . . . . . 7 ((𝐴 ∈ 𝒫 𝐵𝐶 ∈ V) → (𝐴𝐶) ∈ V)
53, 4mpan2 691 . . . . . 6 (𝐴 ∈ 𝒫 𝐵 → (𝐴𝐶) ∈ V)
6 elpwg 4603 . . . . . 6 ((𝐴𝐶) ∈ V → ((𝐴𝐶) ∈ 𝒫 (𝐵𝐶) ↔ (𝐴𝐶) ⊆ (𝐵𝐶)))
75, 6syl 17 . . . . 5 (𝐴 ∈ 𝒫 𝐵 → ((𝐴𝐶) ∈ 𝒫 (𝐵𝐶) ↔ (𝐴𝐶) ⊆ (𝐵𝐶)))
82, 7imbitrrid 246 . . . 4 (𝐴 ∈ 𝒫 𝐵 → (𝐴𝐵 → (𝐴𝐶) ∈ 𝒫 (𝐵𝐶)))
91, 8mpd 15 . . 3 (𝐴 ∈ 𝒫 𝐵 → (𝐴𝐶) ∈ 𝒫 (𝐵𝐶))
10 elpwi 4607 . . . . 5 ((𝐴𝐶) ∈ 𝒫 𝐵 → (𝐴𝐶) ⊆ 𝐵)
1110unssbd 4194 . . . 4 ((𝐴𝐶) ∈ 𝒫 𝐵𝐶𝐵)
1211con3i 154 . . 3 𝐶𝐵 → ¬ (𝐴𝐶) ∈ 𝒫 𝐵)
139, 12anim12i 613 . 2 ((𝐴 ∈ 𝒫 𝐵 ∧ ¬ 𝐶𝐵) → ((𝐴𝐶) ∈ 𝒫 (𝐵𝐶) ∧ ¬ (𝐴𝐶) ∈ 𝒫 𝐵))
14 eldif 3961 . 2 ((𝐴𝐶) ∈ (𝒫 (𝐵𝐶) ∖ 𝒫 𝐵) ↔ ((𝐴𝐶) ∈ 𝒫 (𝐵𝐶) ∧ ¬ (𝐴𝐶) ∈ 𝒫 𝐵))
1513, 14sylibr 234 1 ((𝐴 ∈ 𝒫 𝐵 ∧ ¬ 𝐶𝐵) → (𝐴𝐶) ∈ (𝒫 (𝐵𝐶) ∖ 𝒫 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 206  wa 395  wcel 2108  Vcvv 3480  cdif 3948  cun 3949  wss 3951  𝒫 cpw 4600
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2708  ax-sep 5296  ax-nul 5306  ax-pr 5432  ax-un 7755
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2065  df-clab 2715  df-cleq 2729  df-clel 2816  df-v 3482  df-dif 3954  df-un 3956  df-ss 3968  df-nul 4334  df-pw 4602  df-sn 4627  df-pr 4629  df-uni 4908
This theorem is referenced by: (None)
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