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Theorem elz12s 28888
Description: Membership in the dyadic fractions. (Contributed by Scott Fenton, 7-Aug-2025.)
Assertion
Ref Expression
elz12s (𝐴 ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝐴 = (𝑥 /su (2s↑s𝑦)))
Distinct variable group:   𝑥,𝐴,𝑦

Proof of Theorem elz12s
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 elex 3475 . 2 (𝐴 ∈ ℤs[1/2] → 𝐴 ∈ V)
2 id 23 . . . . 5 (𝐴 = (𝑥 /su (2s↑s𝑦)) → 𝐴 = (𝑥 /su (2s↑s𝑦)))
3 ovex 7476 . . . . 5 (𝑥 /su (2s↑s𝑦)) ∈ V
42, 3eqeltrdi 2872 . . . 4 (𝐴 = (𝑥 /su (2s↑s𝑦)) → 𝐴 ∈ V)
54a1i 11 . . 3 ((𝑥 ∈ ℤs ∧ 𝑦 ∈ ℕ0s) → (𝐴 = (𝑥 /su (2s↑s𝑦)) → 𝐴 ∈ V))
65rexlimivv 3208 . 2 (∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝐴 = (𝑥 /su (2s↑s𝑦)) → 𝐴 ∈ V)
7 eqeq1 2767 . . . 4 (𝑧 = 𝐴 → (𝑧 = (𝑥 /su (2s↑s𝑦)) ↔ 𝐴 = (𝑥 /su (2s↑s𝑦))))
872rexbidv 3231 . . 3 (𝑧 = 𝐴 → (∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝑧 = (𝑥 /su (2s↑s𝑦)) ↔ ∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝐴 = (𝑥 /su (2s↑s𝑦))))
9 df-z12s 28831 . . 3 ℤs[1/2] = {𝑧 ∣ ∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝑧 = (𝑥 /su (2s↑s𝑦))}
108, 9elab2g 3637 . 2 (𝐴 ∈ V → (𝐴 ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝐴 = (𝑥 /su (2s↑s𝑦))))
111, 6, 10pm5.21nii 381 1 (𝐴 ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs ∃𝑦 ∈ ℕ0s 𝐴 = (𝑥 /su (2s↑s𝑦)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2147  ∃wrex 3090  Vcvv 3454  (class class class)co 7443   /su cdivs 28603  ℕ0scn0s 28728  ℤsczs 28794  2sc2s 28826  ↑scexps 28828  ℤs[1/2]cz12s 28830
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-nul 5263
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ne 2960  df-rex 3091  df-v 3456  df-ss 3901  df-dif 4050  df-un 4154  df-nul 4282  df-sn 4589  df-pr 4591  df-uni 4871  df-iota 6512  df-fv 6566  df-ov 7446  df-z12s 28831
This theorem is used by:  elz12si  28889  zz12s  28891  z12no  28892  z12addscl  28893  z12negscl  28894  z12shalf  28896  z12zsodd  28898  z12sge0  28899
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