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Theorem elz12si 28536
Description: Inference form of membership in the dyadic fractions. (Contributed by Scott Fenton, 21-Feb-2026.)
Assertion
Ref Expression
elz12si ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])

Proof of Theorem elz12si
Dummy variables 𝑥 𝑛 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqid 2756 . . 3 (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))
2 oveq1 7392 . . . . 5 (𝑥 = 𝐴 → (𝑥 /su (2ss𝑛)) = (𝐴 /su (2ss𝑛)))
32eqeq2d 2767 . . . 4 (𝑥 = 𝐴 → ((𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛))))
4 oveq2 7393 . . . . . 6 (𝑛 = 𝑁 → (2ss𝑛) = (2ss𝑁))
54oveq2d 7401 . . . . 5 (𝑛 = 𝑁 → (𝐴 /su (2ss𝑛)) = (𝐴 /su (2ss𝑁)))
65eqeq2d 2767 . . . 4 (𝑛 = 𝑁 → ((𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))))
73, 6rspc2ev 3589 . . 3 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s ∧ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
81, 7mp3an3 1465 . 2 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
9 elz12s 28535 . 2 ((𝐴 /su (2ss𝑁)) ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
108, 9sylibr 236 1 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 398   = wceq 1554  wcel 2136  wrex 3080  (class class class)co 7385   /su cdivs 28250  0scn0s 28375  sczs 28441  2sc2s 28473  scexps 28475  s[1/2]cz12s 28477
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1809  ax-4 1823  ax-5 1924  ax-6 1981  ax-7 2022  ax-8 2138  ax-9 2146  ax-ext 2728  ax-nul 5250
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 857  df-3an 1097  df-tru 1557  df-fal 1567  df-ex 1794  df-sb 2085  df-clab 2735  df-cleq 2748  df-clel 2831  df-ne 2952  df-ral 3071  df-rex 3081  df-rab 3409  df-v 3450  df-dif 3902  df-un 3904  df-ss 3916  df-nul 4281  df-if 4475  df-sn 4577  df-pr 4579  df-op 4583  df-uni 4860  df-br 5095  df-iota 6466  df-fv 6518  df-ov 7388  df-z12s 28478
This theorem is referenced by:  bdayfinlem  28549
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