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Theorem elz12si 28490
Description: Inference form of membership in the dyadic fractions. (Contributed by Scott Fenton, 21-Feb-2026.)
Assertion
Ref Expression
elz12si ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])

Proof of Theorem elz12si
Dummy variables 𝑥 𝑛 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqid 2740 . . 3 (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))
2 oveq1 7370 . . . . 5 (𝑥 = 𝐴 → (𝑥 /su (2ss𝑛)) = (𝐴 /su (2ss𝑛)))
32eqeq2d 2751 . . . 4 (𝑥 = 𝐴 → ((𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛))))
4 oveq2 7371 . . . . . 6 (𝑛 = 𝑁 → (2ss𝑛) = (2ss𝑁))
54oveq2d 7379 . . . . 5 (𝑛 = 𝑁 → (𝐴 /su (2ss𝑛)) = (𝐴 /su (2ss𝑁)))
65eqeq2d 2751 . . . 4 (𝑛 = 𝑁 → ((𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))))
73, 6rspc2ev 3580 . . 3 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s ∧ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
81, 7mp3an3 1458 . 2 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
9 elz12s 28489 . 2 ((𝐴 /su (2ss𝑁)) ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
108, 9sylibr 235 1 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 396   = wceq 1547  wcel 2119  wrex 3064  (class class class)co 7363   /su cdivs 28204  0scn0s 28329  sczs 28395  2sc2s 28427  scexps 28429  s[1/2]cz12s 28431
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2712  ax-nul 5235
This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-3an 1094  df-tru 1550  df-fal 1560  df-ex 1787  df-sb 2074  df-clab 2719  df-cleq 2732  df-clel 2815  df-ne 2936  df-ral 3055  df-rex 3065  df-rab 3393  df-v 3434  df-dif 3893  df-un 3895  df-ss 3907  df-nul 4269  df-if 4462  df-sn 4563  df-pr 4565  df-op 4569  df-uni 4846  df-br 5080  df-iota 6448  df-fv 6500  df-ov 7366  df-z12s 28432
This theorem is referenced by:  bdayfinlem  28503
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