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Theorem elz12si 28624
Description: Inference form of membership in the dyadic fractions. (Contributed by Scott Fenton, 21-Feb-2026.)
Assertion
Ref Expression
elz12si ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])

Proof of Theorem elz12si
Dummy variables 𝑥 𝑛 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqid 2765 . . 3 (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))
2 oveq1 7407 . . . . 5 (𝑥 = 𝐴 → (𝑥 /su (2ss𝑛)) = (𝐴 /su (2ss𝑛)))
32eqeq2d 2776 . . . 4 (𝑥 = 𝐴 → ((𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛))))
4 oveq2 7408 . . . . . 6 (𝑛 = 𝑁 → (2ss𝑛) = (2ss𝑁))
54oveq2d 7416 . . . . 5 (𝑛 = 𝑁 → (𝐴 /su (2ss𝑛)) = (𝐴 /su (2ss𝑁)))
65eqeq2d 2776 . . . 4 (𝑛 = 𝑁 → ((𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))))
73, 6rspc2ev 3597 . . 3 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s ∧ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
81, 7mp3an3 1474 . 2 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
9 elz12s 28623 . 2 ((𝐴 /su (2ss𝑁)) ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
108, 9sylibr 237 1 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 400   = wceq 1563  wcel 2145  wrex 3089  (class class class)co 7400   /su cdivs 28338  0scn0s 28463  sczs 28529  2sc2s 28561  scexps 28563  s[1/2]cz12s 28565
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1818  ax-4 1832  ax-5 1933  ax-6 1990  ax-7 2031  ax-8 2147  ax-9 2155  ax-ext 2737  ax-nul 5261
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1566  df-fal 1576  df-ex 1803  df-sb 2094  df-clab 2744  df-cleq 2757  df-clel 2840  df-ne 2961  df-ral 3080  df-rex 3090  df-rab 3418  df-v 3459  df-dif 3910  df-un 3912  df-ss 3924  df-nul 4289  df-if 4484  df-sn 4586  df-pr 4588  df-op 4592  df-uni 4869  df-br 5106  df-iota 6481  df-fv 6533  df-ov 7403  df-z12s 28566
This theorem is referenced by:  bdayfinlem  28637
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