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Theorem elz12si 28479
Description: Inference form of membership in the dyadic fractions. (Contributed by Scott Fenton, 21-Feb-2026.)
Assertion
Ref Expression
elz12si ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])

Proof of Theorem elz12si
Dummy variables 𝑥 𝑛 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqid 2737 . . 3 (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))
2 oveq1 7367 . . . . 5 (𝑥 = 𝐴 → (𝑥 /su (2ss𝑛)) = (𝐴 /su (2ss𝑛)))
32eqeq2d 2748 . . . 4 (𝑥 = 𝐴 → ((𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛))))
4 oveq2 7368 . . . . . 6 (𝑛 = 𝑁 → (2ss𝑛) = (2ss𝑁))
54oveq2d 7376 . . . . 5 (𝑛 = 𝑁 → (𝐴 /su (2ss𝑛)) = (𝐴 /su (2ss𝑁)))
65eqeq2d 2748 . . . 4 (𝑛 = 𝑁 → ((𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑛)) ↔ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))))
73, 6rspc2ev 3578 . . 3 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s ∧ (𝐴 /su (2ss𝑁)) = (𝐴 /su (2ss𝑁))) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
81, 7mp3an3 1453 . 2 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
9 elz12s 28478 . 2 ((𝐴 /su (2ss𝑁)) ∈ ℤs[1/2] ↔ ∃𝑥 ∈ ℤs𝑛 ∈ ℕ0s (𝐴 /su (2ss𝑁)) = (𝑥 /su (2ss𝑛)))
108, 9sylibr 234 1 ((𝐴 ∈ ℤs𝑁 ∈ ℕ0s) → (𝐴 /su (2ss𝑁)) ∈ ℤs[1/2])
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395   = wceq 1542  wcel 2114  wrex 3062  (class class class)co 7360   /su cdivs 28193  0scn0s 28318  sczs 28384  2sc2s 28416  scexps 28418  s[1/2]cz12s 28420
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709  ax-nul 5241
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-ne 2934  df-ral 3053  df-rex 3063  df-rab 3391  df-v 3432  df-dif 3893  df-un 3895  df-ss 3907  df-nul 4275  df-if 4468  df-sn 4569  df-pr 4571  df-op 4575  df-uni 4852  df-br 5087  df-iota 6448  df-fv 6500  df-ov 7363  df-z12s 28421
This theorem is referenced by:  bdayfinlem  28492
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