Theorem equcomd 2018

Description: Deduction form of equcom 2017, symmetry of equality. For the versions for classes, see eqcom 2747 and eqcomd 2746. (Contributed by BJ, 6-Oct-2019.)

Hypothesis

Ref	Expression
equcomd.1	⊢ (𝜑 → 𝑥 = 𝑦)

Assertion

Ref	Expression
equcomd	⊢ (𝜑 → 𝑦 = 𝑥)

Proof of Theorem equcomd

Step	Hyp	Ref	Expression
1		equcomd.1	. 2 ⊢ (𝜑 → 𝑥 = 𝑦)
2		equcom 2017	. 2 ⊢ (𝑥 = 𝑦 ↔ 𝑦 = 𝑥)
3	1, 2	sylib 218	1 ⊢ (𝜑 → 𝑦 = 𝑥)

Syntax hints:   → wi 4

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007

This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1778

This theorem is referenced by:  sndisj  5158  fsumcom2  15822  fprodcom2  16032  catideu  17733  pospo  18415  dprdfcntz  20059  ordtt1  23408  eengtrkg  29019  cusgrfilem2  29492  frgr2wwlk1  30361  ssmxidl  33467  gonar  35363  bj-nfcsym  36865  exidu1  37816  rngoideu  37863  2reu8i  47028  ichnreuop  47346  sprsymrelf1lem  47365