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Theorem isprmrng 49638
Description: The predicate "is a prime ring". (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by AV, 18-Jun-2026.)
Hypotheses
Ref Expression
isprmrng.z 0 = (0g‘𝑅)
isprmrng.p 𝑃 = (PrmIdeal‘𝑅)
Assertion
Ref Expression
isprmrng (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))

Proof of Theorem isprmrng
Dummy variable 𝑟 is distinct from all other variables.
StepHypRef Expression
1 fveq2 6908 . . . . 5 (𝑟 = 𝑅 → (0g‘𝑟) = (0g‘𝑅))
21sneqd 4596 . . . 4 (𝑟 = 𝑅 → {(0g‘𝑟)} = {(0g‘𝑅)})
3 fveq2 6908 . . . 4 (𝑟 = 𝑅 → (PrmIdeal‘𝑟) = (PrmIdeal‘𝑅))
42, 3eleq12d 2858 . . 3 (𝑟 = 𝑅 → ({(0g‘𝑟)} ∈ (PrmIdeal‘𝑟) ↔ {(0g‘𝑅)} ∈ (PrmIdeal‘𝑅)))
5 df-prmring 49637 . . 3 PrmRing = {𝑟 ∈ Ring ∣ {(0g‘𝑟)} ∈ (PrmIdeal‘𝑟)}
64, 5elrab2 3652 . 2 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ {(0g‘𝑅)} ∈ (PrmIdeal‘𝑅)))
7 isprmrng.z . . . . . 6 0 = (0g‘𝑅)
87sneqi 4595 . . . . 5 { 0 } = {(0g‘𝑅)}
9 isprmrng.p . . . . 5 𝑃 = (PrmIdeal‘𝑅)
108, 9eleq12i 2857 . . . 4 ({ 0 } ∈ 𝑃 ↔ {(0g‘𝑅)} ∈ (PrmIdeal‘𝑅))
1110bicomi 227 . . 3 ({(0g‘𝑅)} ∈ (PrmIdeal‘𝑅) ↔ { 0 } ∈ 𝑃)
1211anbi2i 635 . 2 ((𝑅 ∈ Ring ∧ {(0g‘𝑅)} ∈ (PrmIdeal‘𝑅)) ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
136, 12bitri 278 1 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2147  {csn 4588  ‘cfv 6558  0gc0g 17639  Ringcrg 20489  PrmIdealcprmidl 21646  PrmRingcprmrng 49636
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-br 5107  df-iota 6512  df-fv 6566  df-prmring 49637
This theorem is used by:  prmringnzring  49639  smprngprmrng  49641  crngprmringidom  49643  isidom3  49647
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