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Theorem isprmrng 49068
Description: The predicate "is a prime ring". (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by AV, 18-Jun-2026.)
Hypotheses
Ref Expression
isprmrng.z 0 = (0g𝑅)
isprmrng.p 𝑃 = (PrmIdeal‘𝑅)
Assertion
Ref Expression
isprmrng (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))

Proof of Theorem isprmrng
Dummy variable 𝑟 is distinct from all other variables.
StepHypRef Expression
1 fveq2 6881 . . . . 5 (𝑟 = 𝑅 → (0g𝑟) = (0g𝑅))
21sneqd 4600 . . . 4 (𝑟 = 𝑅 → {(0g𝑟)} = {(0g𝑅)})
3 fveq2 6881 . . . 4 (𝑟 = 𝑅 → (PrmIdeal‘𝑟) = (PrmIdeal‘𝑅))
42, 3eleq12d 2855 . . 3 (𝑟 = 𝑅 → ({(0g𝑟)} ∈ (PrmIdeal‘𝑟) ↔ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)))
5 df-prmring 49067 . . 3 PrmRing = {𝑟 ∈ Ring ∣ {(0g𝑟)} ∈ (PrmIdeal‘𝑟)}
64, 5elrab2 3653 . 2 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)))
7 isprmrng.z . . . . . 6 0 = (0g𝑅)
87sneqi 4599 . . . . 5 { 0 } = {(0g𝑅)}
9 isprmrng.p . . . . 5 𝑃 = (PrmIdeal‘𝑅)
108, 9eleq12i 2854 . . . 4 ({ 0 } ∈ 𝑃 ↔ {(0g𝑅)} ∈ (PrmIdeal‘𝑅))
1110bicomi 227 . . 3 ({(0g𝑅)} ∈ (PrmIdeal‘𝑅) ↔ { 0 } ∈ 𝑃)
1211anbi2i 634 . 2 ((𝑅 ∈ Ring ∧ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)) ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
136, 12bitri 278 1 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
Colors of variables: wff setvar class
Syntax hints:  wb 209  wa 400   = wceq 1568  wcel 2141  {csn 4588  cfv 6536  0gc0g 17491  Ringcrg 20314  PrmIdealcprmidl 21439  PrmRingcprmrng 49066
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1823  ax-4 1837  ax-5 1938  ax-6 1995  ax-7 2036  ax-8 2143  ax-9 2151  ax-ext 2733
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1571  df-fal 1581  df-ex 1808  df-sb 2095  df-clab 2740  df-cleq 2753  df-clel 2836  df-rab 3415  df-v 3455  df-dif 3907  df-un 3909  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-uni 4872  df-br 5109  df-iota 6492  df-fv 6544  df-prmring 49067
This theorem is referenced by:  prmringnzring  49069  smprngprmrng  49071  crngprmringidom  49073  isidom3  49077
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