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Theorem isprmrng 48956
Description: The predicate "is a prime ring". (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by AV, 18-Jun-2026.)
Hypotheses
Ref Expression
isprmrng.z 0 = (0g𝑅)
isprmrng.p 𝑃 = (PrmIdeal‘𝑅)
Assertion
Ref Expression
isprmrng (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))

Proof of Theorem isprmrng
Dummy variable 𝑟 is distinct from all other variables.
StepHypRef Expression
1 fveq2 6871 . . . . 5 (𝑟 = 𝑅 → (0g𝑟) = (0g𝑅))
21sneqd 4597 . . . 4 (𝑟 = 𝑅 → {(0g𝑟)} = {(0g𝑅)})
3 fveq2 6871 . . . 4 (𝑟 = 𝑅 → (PrmIdeal‘𝑟) = (PrmIdeal‘𝑅))
42, 3eleq12d 2859 . . 3 (𝑟 = 𝑅 → ({(0g𝑟)} ∈ (PrmIdeal‘𝑟) ↔ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)))
5 df-prmring 48955 . . 3 PrmRing = {𝑟 ∈ Ring ∣ {(0g𝑟)} ∈ (PrmIdeal‘𝑟)}
64, 5elrab2 3657 . 2 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)))
7 isprmrng.z . . . . . 6 0 = (0g𝑅)
87sneqi 4596 . . . . 5 { 0 } = {(0g𝑅)}
9 isprmrng.p . . . . 5 𝑃 = (PrmIdeal‘𝑅)
108, 9eleq12i 2858 . . . 4 ({ 0 } ∈ 𝑃 ↔ {(0g𝑅)} ∈ (PrmIdeal‘𝑅))
1110bicomi 227 . . 3 ({(0g𝑅)} ∈ (PrmIdeal‘𝑅) ↔ { 0 } ∈ 𝑃)
1211anbi2i 634 . 2 ((𝑅 ∈ Ring ∧ {(0g𝑅)} ∈ (PrmIdeal‘𝑅)) ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
136, 12bitri 278 1 (𝑅 ∈ PrmRing ↔ (𝑅 ∈ Ring ∧ { 0 } ∈ 𝑃))
Colors of variables: wff setvar class
Syntax hints:  wb 209  wa 400   = wceq 1563  wcel 2145  {csn 4585  cfv 6525  0gc0g 17482  Ringcrg 20306  PrmIdealcprmidl 21422  PrmRingcprmrng 48954
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1818  ax-4 1832  ax-5 1933  ax-6 1990  ax-7 2031  ax-8 2147  ax-9 2155  ax-ext 2737
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1566  df-fal 1576  df-ex 1803  df-sb 2094  df-clab 2744  df-cleq 2757  df-clel 2840  df-rab 3418  df-v 3459  df-dif 3910  df-un 3912  df-ss 3924  df-nul 4289  df-if 4484  df-sn 4586  df-pr 4588  df-op 4592  df-uni 4869  df-br 5106  df-iota 6481  df-fv 6533  df-prmring 48955
This theorem is referenced by:  prmringnzring  48957  smprngprmrng  48959  crngprmringidom  48961
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